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(P) $+$ (Q) $\frac{\mathrm{NaBH}_{3} \mathrm{CN}}{\text { methanol }}-\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{NHCH}_{2} \mathrm{CH}_{3}$ (P) and (Q) are (a) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}$ (b) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}$ (c) $\mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{CH}_{3} \cdot \mathrm{NH} \cdot \mathrm{CH}_{2} \cdot \mathrm{CH}_{3}$ (d) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}+\mathrm{CH}_{3} \cdot \mathrm{NH} \cdot \mathrm{CH}_{2} \cdot \mathrm{CH}_{3}$

Yeah, okay. We are going to find the derivative of the dot product between these two vectors and the derivative of the cross product. So first of all, for our dot product we can go ahead and multiply our two tee times t squared, then our t squared times to T. And then our negative five times one to take the derivative. Now we will have a six t squared plus six t squared and then the minus five goes away. So it ends up being a 12 t squared. Okay, so now for our cross product, I like to write out my A I. Js and Ks of course we have to write are you first and then R V Since we're doing the cross product of U. And V. So to do that, remember um for I we're taking that um and we're going criss crossing right? So we have our t squared times one and then that's going to be Multiplied by the -20 T. Now, for RJ we subtract and we have our two tee times one minus R. T square times negative five. So that was also becomes a plus. And then lastly, we hired kind of that cake column and again we look at our two tee times to T. So that's our fourty squared and then we subtract R. T to the fourth. So now we're ready for our derivative and so are derivative of our cross product is going to be two T plus 10 in the I direction And then subtract two plus 10 T in the J direction, and finally A T minus 42 the third in the K direction.

Okay, so the letter A, B and C are constant and the equal is not there, so we want to solve this equation. Okay, so we first we can move be to the right side, so C plus B. Okay. The X. Okay? With divided eight uh divided A. To the both sides of the equation, so X. It goes to C plus B, divided by a. Okay, so here is not. There are. Okay, so this one, it's our answer.

Is this reaction commentator or district? Later? And what does it stay? A chemistry off the product of it, each in turtles involved into this reaction, it responds toe that enter our image transition stick. To make it on a magic will need to introduce another Lord to Homer, which is achieved by the color tater process. So those two parts the erupted in the same direction. It will bring this Mitchell job up and business or group down. So that's trance relationship. Same reaction under photochemical conditions in this case, it electrons to respond to the on a magic transition state toe. Keep the number off notes. We need to rotate those professions in the upper the directions, which is just prepared to refresher. It will bring Mr Woodroof one up and missile group. Then up it responds to the cysts stood a chemical relationship

Okay, so we're asking Add the falling. So let's start with our 1st 2 terms. And actually, it's put our 43288 on top since its larger. And then we have Gates. 2651 So that's 8 to 6 Close. Eight is Fortune. 75678 four and four. And now let's add 53626789 10 11 12 13. Fortune 3456 49 h for four. So we get the following, which is equal to he. Action. Now let's not be there. H So it's, um 448 964 So that's actually de