5

QUESTionConsider onc-item surcy as follows: Using scalc of 1 in which =Not as well as I hoped, 2 = Pretry well, 3 = Well 4 = Vecy well, and 5 = Crushing it, pleasc ...

Question

QUESTionConsider onc-item surcy as follows: Using scalc of 1 in which =Not as well as I hoped, 2 = Pretry well, 3 = Well 4 = Vecy well, and 5 = Crushing it, pleasc indicate how well you are doing s0 far in your MBA Coutee 1 [ ] 2 [ ] 3 [ ] 4[ ] 5 [ ] What type of data does this survey generate? ContinuousRatioTimc scricsExponentialBinomialIntervalBiascdIntersectionUnionHypergeometric

QUESTion Consider onc-item surcy as follows: Using scalc of 1 in which =Not as well as I hoped, 2 = Pretry well, 3 = Well 4 = Vecy well, and 5 = Crushing it, pleasc indicate how well you are doing s0 far in your MBA Coutee 1 [ ] 2 [ ] 3 [ ] 4[ ] 5 [ ] What type of data does this survey generate? Continuous Ratio Timc scrics Exponential Binomial Interval Biascd Intersection Union Hypergeometric



Answers

In Exercises $1-5,$ fill in the table and guess the value of the limit. $$ \lim _{x \rightarrow 1} f(x), \text { where } f(x)=\frac{x^{3}-1}{x^{2}-1} $$ $$ \begin{array}{|l|l||c|l|} \hline x & f(x) & x & f(x) \\ \hline 1.002 & & 0.998 & \\ \hline 1.001 & & 0.999 & \\ \hline 1.0005 & & 0.9995 & \\ \hline 1.00001 & & 0.99999 & \\ \hline \end{array} $$

So for this problem, after we fill in our graph, the main thing we can see here is that from the left and the right. It appears we have um different values going on, right. So we're trying to guess the limit of zero from the right, and it really hasn't been able to make up what it's doing, like there's dramatic changes from one to the other. And the main reason for this actually has to deal with how Ellen ex works. Um That is that L n X is undefined at zero. So it makes sense that the graph Ln X from the right as some problems with it, right? Uh But this is enough for us to say that this is not defined and that would be our answer for this particular graph because there just isn't enough information to make us safe assumption.

In part A. Were asked to use the binomial series and the fact that the derivative with respect to X. Of the inverse sine of X equals one minus X squared to the negative one half power to generate the first four non zeros terms of the tailored series for inverse sine of X. Were also asked to find the radius of convergence of this series. Hello? Well first of all, one minus X squared to the negative one half will expand using binomial series. The first four terms. Well we get one plus um negative one half times negative X squared which is X squared over two plus negative one half times negative three halves times negative X squared squared. And he was like yeah yes going on this side over keith factorial Which is three times X to the 4th over eight the most Plus and then the last term. But this is going to be negative 1/2 times -3/2 times negative five halves over three factorial. What? This is uh 5:16. Yeah And then we multiply by negative X squared to the third power. So negative X. D. A. This is positive 5/16 xd eight the same day nope. Sorry X to the 6th. My mistake. And you know the second you cool. Mhm bunch. So using these terms we find that the inverse sine. Well this is approximately right. You've never heard his place. The integral of this expression one plus X squared over two plus three X. To the fourth over eight plus 5 16 X. To the sixth D. X. Sorry Which is approximately yeah. Uh X plus X cubed over two times three or six plus. Let me have extra fifth times 3/40 plus number of five times X. To the 7/7 times 16 which is five X to the seven over 112. Don't have videos approx. Another these are the first four terms in the series expansion for english sign. Not quite as simple as inverse tangent, but we do have a way of finding them now to find the root radius of convergence. Consider the limit as an approaches infinity. Um Well, so now it's going 200 were called, definitely how we calculated this will have the ratio of consecutive terms the sex. It's one times three times five times all the way up to two, two and minus one times two N plus one times X to the two n plus three over two times 4 times six times all the way up to to end times two N plus two. I did I wanted to work and then we also divide bye uh to N plus three because we integrated. Yeah, I thought it two. Yeah, he did times and we have the term before this. But we flip it so we have two times four times six. All the way up to two in. And then two N plus 1/1 times three times five. All the way up to two and -1 times extra the two N plus one. It's when Well we can cancel out factors. We get the limit as N approaches infinity of the absolute value of. See we have two n plus one reach for like nick. Are you going to do that? It's like squared. Yeah. Over that's problems that sometimes both parts. Yes. Sometimes yes. Is the people that are like Mhm. Mhm. Usually two n plus two Times two n Plus three. Yeah. Thank you all times X squared. This commercial director. It's always the client. Yeah. It's always like the can bullshit. Like more and we want this to be less than one for it to converge. So while this limit is the same as one, this is the same as when X squared is less than one. Which is only the case When the absolute value of X is less than one. Yeah. Therefore by the ratio test we should find him. I got in trouble. Stick around. It follows that the radius of convergence is one. That's who that food is. Mhm. Not the people that are going to go out anyways and have a 6000 new ones compare this with the different exercise exercise 69 then in part B where asked the same question essentially. But for inverse Cosine effects breast user result in part A to find the first five non zero terms in the taylor series for inverse co sign fx. Yeah. Right. Well, we know that the derivative with respect to X of the inverse cosine of X is equal to the opposite of one minus x squared to the negative one half. And therefore it follows the coast inverse Cosine of X is equal to well integrating. It's uh pi over two minus the inverse sine effects. This is just an identity. Just because And this is approximately using our formula from before high over 2 -2 X plus X cubed over six Plus three x lifted over 40. Yeah Plus five extra 7th Over 112. Which is approximately a constant pi over two minus x minus X cubed over three -3 X to the 5th over 40 -5 X to the 7th over 112. Yeah. So these are the first five terms of the expansion of inverse Cosine effects. Yeah, john.

In the first part of this question, we want to find the tailor Siris for us. Ah sine inverse x. So what we want to do is to use the the the expression that they've given us, So we want to work on that first. So we know that when we differentiate Sangin Bus X, we get one minus x squared to the power from the heart And what we can do if this issue you see expansion the binomial series for one plus x howl and we're in our case except being the great X squared and end with being the great half. So we would use it Ah Siri's and substitute excessive degree X squared and substitute or end terms with negative heart off the simplifying it We should get this then moving on for sine inverse X, we noted it's integrating. The differential signed involves sex is basically the same thing. So what we want to do is to substitute the differential off signing bus X with the expansion that we've just arrived. So everyone integrate this expansion now and can do that by applying a change rule to each pop the talks. So we incremental pall ex my one and divide about a new power simplifying we should get this. And yes, nothing. We want to see the relationship between the differential differentiator, um, expansion and the original because so with this expansion, we wanted you write the general or what we can call the general formula for each term. So we want to express each Tom solely with, um solely with and eggs. It is important because we need to know this, to be able to find the radius off convergence. So hoping to know where we derive the general pattern is still go back to the toe. The formulation off the serious expansion. We want to see what goes into the coefficient off each x term. So, for example, the second X squared is made up, off and by and minus want. You've got about two Fecteau room and three items in your way types and minus one times minus two. If I don't like reading factorial. So this is something that we want to try to identify, and and for the second part, being extra one, we departed bite to end one and then its victims. When we integrated the increment whole off X by one and we divided by the new power heads that and plus one in the denominator So defended radius off convergence Reuse a A plus a one You better by E n. So this is what we have. It looks very, very complicated. But you know that a lot off terms are repeated and it can be canceled out. So also simplifying this we should have We should have a simpler looking expression and way. Now I want to find a limit off this fresher as intense towards infinity. So, um, we have excess quit and the friction within the models it's going to be less than one because they have be seen. They're off the same power. So in the numerator, we have end square and in the tsunami until we have end square s well so we know that X Square model diffraction will be less than one. And so we can conclude the X squared. It's less than once, and so models off X should be less than one in the next part of this question. We want to find the two lists Siri's work assigning verse X. We first need to recognize the relationship between consign and site. So we should be familiar with this. So called sine X is equal Sign experts pirate too. But the inverse We should be a little careful Where? So how? The brackets. In the same time, I'm picky just on force. So basically causing inverse x goto pi over two minus sign in bus X. A simple example you can give us self is to say, for example, use one. So because I just wanted zero degrees and signing bus Alanis 90 degrees. So we know that signing verses Ah, hit off consigning buffs So we know the expansion. Plus we only Taylor series expansion for sine inverse X And I want to find the tailor Siris for consigning Boss X So we can simply a pilot to in front off negative sine inverse x And that would be our expansion for consigning verse X

Is to find the Binomial series representation and that afterwards find vote conversions. So first off here this is to the 1/5 power And that time is equal to 1/5. Therefore the plan on the serious representation, it's going to be from Chemical 0 to Infinity pass It's what 5th cheapskate next to the Okay power here. And so this in mind here. We're trying to find the current ratio test. Yeah, it's She was at this one Next campus one over 50 cent next to the end. So they're supervised here affects less than one. So therefore He got from -1. It's the next list in one here. And since I am as greater than zero that we include the endpoints. So our interval inc this is going to go from negative one too much.


Similar Solved Questions

2 answers
Fo1 aii En legers ~21ehemal:cal Inducbion: PAove b7 l e(v" '_1) efqt tay'_ +atev" = Y-1
Fo1 aii En legers ~21 ehemal:cal Inducbion: PAove b7 l e(v" '_1) efqt tay'_ +atev" = Y-1...
5 answers
(2pt) If the probability it will rain is 0.6 in other words, P(rain)-0.6, what is the probability it will not rain? And what is this an example of in words?
(2pt) If the probability it will rain is 0.6 in other words, P(rain)-0.6, what is the probability it will not rain? And what is this an example of in words?...
5 answers
Fy" + 2y' 3y = 0 Determine conditions on a,8 € R for which solutions to decay as t , |y(o) a,y (0) = 8 +00
fy" + 2y' 3y = 0 Determine conditions on a,8 € R for which solutions to decay as t , |y(o) a,y (0) = 8 +00...
5 answers
HW24: System of Equations Applicatons score: 1778 N8 jniswEredQuestionThe length of a reclarigle Iess Inan Umes the widch the perinteter of the rectangle [9 52 Mlw tind tne length arid the wicth (Hint_ Tha perimeter ot rectangle I5 Biven by: P = 21 + 2W)The {engthThe VidthSubmlt Questan
HW24: System of Equations Applicatons score: 1778 N8 jniswEred Question The length of a reclarigle Iess Inan Umes the widch the perinteter of the rectangle [9 52 Mlw tind tne length arid the wicth (Hint_ Tha perimeter ot rectangle I5 Biven by: P = 21 + 2W) The {ength The Vidth Submlt Questan...
5 answers
Determine the set of points at which the function Is continuous: Ty if (I,y) # (0.0) 1 +ry + y2 f(ry) = (0 if (I.y) (0.0){(x, Y) IxeR and y €R} {(x, Y)Ix- Y # 0} {(x,Y)Ix > 0 and y > 0} {(x, Y) |(x, Y) # (0, 0)} {(x, Y)IxeR and y $ 0}
Determine the set of points at which the function Is continuous: Ty if (I,y) # (0.0) 1 +ry + y2 f(ry) = (0 if (I.y) (0.0) {(x, Y) IxeR and y €R} {(x, Y)Ix- Y # 0} {(x,Y)Ix > 0 and y > 0} {(x, Y) |(x, Y) # (0, 0)} {(x, Y)IxeR and y $ 0}...
4 answers
Use tlte Laplace (ransfor Method to solve the following differeutial equation:d 426with bouuduy couditious 1(0) = 4and 4) =}
Use tlte Laplace (ransfor Method to solve the following differeutial equation: d 426 with bouuduy couditious 1(0) = 4and 4) =}...
5 answers
Consider the function f(z) = 23 and its relation to the degree 2 Taylor polynomial p2 (c) at x = 1: P2(2) = 1+3(2 _ 1)+3(2 _ 1)2 . By Taylor's theorem f(c) = P2(c) + Rg(c) The Lagrange form of the remainder gives (z-1)3 Rs(c) = f(8) (c) 31 where c is between and x. But f(8) (c) = This is a special case where the Lagrange form of the remainder can be calculated exactly: Rg(x)
Consider the function f(z) = 23 and its relation to the degree 2 Taylor polynomial p2 (c) at x = 1: P2(2) = 1+3(2 _ 1)+3(2 _ 1)2 . By Taylor's theorem f(c) = P2(c) + Rg(c) The Lagrange form of the remainder gives (z-1)3 Rs(c) = f(8) (c) 31 where c is between and x. But f(8) (c) = This is a spec...
5 answers
A company manufactures industrial laminates (thin nylon-based sheets) of thickness 0.020 in, with a tolerance of 0.003 in.(a) Find an inequality involving absolute values that describes the range of possible thickness for the laminate.(b) Solve the inequality you found in part (a).(IMAGES CANNOT COPY)0.020 in.
A company manufactures industrial laminates (thin nylon-based sheets) of thickness 0.020 in, with a tolerance of 0.003 in. (a) Find an inequality involving absolute values that describes the range of possible thickness for the laminate. (b) Solve the inequality you found in part (a). (IMAGES CANNOT ...
5 answers
COS nT (28.7) Apply the Alternating Series Test to determine if converges. If the AL- n3/4 ternating Series Test does not give convergence; apply another test to determine whether the series converges Or diverges_
COS nT (28.7) Apply the Alternating Series Test to determine if converges. If the AL- n3/4 ternating Series Test does not give convergence; apply another test to determine whether the series converges Or diverges_...
1 answers
Rationalize each denominator. $$ \frac{3}{\sqrt[3]{9}} $$
Rationalize each denominator. $$ \frac{3}{\sqrt[3]{9}} $$...
1 answers
Use a CAS to perform the following steps: a. Plot the function near the point $x_{0}$ being approached. b. From your plot guess the value of the limit. $$\lim _{x \rightarrow 0} \frac{2 x^{2}}{3-3 \cos x}$$
Use a CAS to perform the following steps: a. Plot the function near the point $x_{0}$ being approached. b. From your plot guess the value of the limit. $$\lim _{x \rightarrow 0} \frac{2 x^{2}}{3-3 \cos x}$$...
5 answers
A Maxwell viscoelastic system has a normal modulus of 70 Pascal and relaxation time of 2.0 seconds; the storage modulus (in Pascal unit) at angular frequency of 0.1 radians per second is then?None2.882.692.50
A Maxwell viscoelastic system has a normal modulus of 70 Pascal and relaxation time of 2.0 seconds; the storage modulus (in Pascal unit) at angular frequency of 0.1 radians per second is then? None 2.88 2.69 2.50...
5 answers
Two protons, starting several meters apart, are aimed directly at each other with speeds of $2.00 imes 10^5$ m$/$s, measured relative to the earth. Find the maximum electric force that theseprotons will exert on each other.
Two protons, starting several meters apart, are aimed directly at each other with speeds of $2.00 \times 10^5$ m$/$s, measured relative to the earth. Find the maximum electric force that these protons will exert on each other....
5 answers
What is the projection y of xon the unit vector{v3?
What is the projection y of x on the unit vector {v3?...
4 answers
Which is NOT true of the outer membrane of certain bacteria?it contains lipopolysaccharide with the lipid portion being endotoxinb. its presence in the blood can result in an increase in the permeability of the blood vesselsits presence in the blood results in high blood pressure as a result of vasoconstrictiond_ it can cause a fever by
Which is NOT true of the outer membrane of certain bacteria? it contains lipopolysaccharide with the lipid portion being endotoxin b. its presence in the blood can result in an increase in the permeability of the blood vessels its presence in the blood results in high blood pressure as a result of...
5 answers
The uniform boom shown below weighs 3,560 N; It is supported by the horizontal guY wire and by the hinged support at point ,2000 NWhat is the tension (in N) in the guy wire?What Is the force on the boom due to the support at A? (Enter the magnitude In nevttons and the direction in degrees counterclockwlse from the magnitude direction counterclockwise from the +X-axis-axis. Assume that the +x-axis is to the right: )Does the force at A act along the boom? Yes0 No
The uniform boom shown below weighs 3,560 N; It is supported by the horizontal guY wire and by the hinged support at point , 2000 N What is the tension (in N) in the guy wire? What Is the force on the boom due to the support at A? (Enter the magnitude In nevttons and the direction in degrees counter...
4 answers
Consider the dynamical systemdc dt dy dtsin(c)Around the fixed point at (0,0), integral curves are of the form:0 y =y = a.20 y = %y = ax
Consider the dynamical system dc dt dy dt sin(c) Around the fixed point at (0,0), integral curves are of the form: 0 y = y = a.2 0 y = % y = ax...

-- 0.022940--