5

Find the Laplace transforms of the following functions of t1, f(t) = (t" + T)ult-1)(2t+1, Ozt<2 2. f(t) = t22t <4 3. f() = {,t <1 sin (+-1) t21f(t) =...

Question

Find the Laplace transforms of the following functions of t1, f(t) = (t" + T)ult-1)(2t+1, Ozt<2 2. f(t) = t22t <4 3. f() = {,t <1 sin (+-1) t21f(t) =

Find the Laplace transforms of the following functions of t 1, f(t) = (t" + T)ult-1) (2t+1, Ozt<2 2. f(t) = t22 t <4 3. f() = {, t <1 sin (+-1) t21 f(t) =



Answers

Find the Laplace transform of the given function. $$ f(t)=(t-3) u_{2}(t)-(t-2) u_{3}(t) $$

Hello and welcome to problem 11 of chapter six. Section three you're asked final pause transform 50 which is the quantity t minus three times you said to minus the quantity t minus two times U. Sub three. And to solve this um we are going to recognize our equation that were given in this chapter which is that the applause transform of you subsea of T times F. Of t minus C. Is equal to capital F. Of S. Times E. To the minus C. S. Great. And from here we can ah just look at what matches up and unfortunately nothing matches up by matching up. I mean a. C. Here and to see their so we're gonna have to force it to match up. And so let's say what would the perfect scenario B. It will look like a t minus two times U. Sub two of t minus a T -3 times use of three two. And what do we have to change to do that? Well in this case we added a U. Sub two. So to keep things equal, we'll subtract that. Use up to. And what do we do in this case? Well we had appear we had plus two times U. Sub two of T. And right here we've plus three times use of three of two. So we're going to subtract a use of three. And from here we can use our simple formula on the first bit and uh we know what the laplace transform of just the um heavy side functions by itself and we can do that for those bits. So the laplace transform Fft. Fft, which is F. F. S. Is equal to um E. To the minus two S. Over s minus E to the -3 s. And we're gonna subtract, okay? So this it should be S squared and we're gonna subtract um S. E. To the minus to us and S. E. To the Um -3. Yes. And that concludes our problem.

Hello and welcome the problem. 10 Chapter six Section 3 here were asked to final applause transformation of the given heavy said function. Have you said functions. And um to do this we have to remember the golden rule of each little past transformations and that's that you subsea of T um times F of t minus C is equal to E. To the minus C. S. Times little plus transformation of um F. Of T. All right that is. And of course the left side is a little pot transformation as well. So with this we can just substitute this F. F. T minus C. For one because that's essentially what all of these are being multiplied by. So doing that we're gonna be left with E. To the minus s. Well what's a little past transformation of one? What's one of us? Because the plus transformation T. To the end that we found in previous sections is in factorial Over us to the end plus one. So plugging this in The zero factorial is one over S. To the zero plus one is one. Yes. So I left with one of our S. And well so the whole posture information of you won each of the negative s over us. Likewise we can repeat this process for the others. We get to E. To the minus three S over us And -6 e. to the -4 s. Over us. We can of course combine them to be E. To the minus S. Plus two E. To the minus three S. Find a six e. to the -4 s over S. and that concludes the problem.

Hello and welcome to problem 10 of chapter six. Section three you are asked to find the applause transform of the given function F. T. Where's the linear combination of use of one. Use of three and use it for. So let's get into this. We're going to use the equation we learned at the beginning of this chapter. Which is which is that use of C. T. F. Of T minus C. Is equal to the universal applause transform of E. To the minus C. S. Times F. Of S. Great. And how does that help us? Uh Well what is multiplied by this use of one in this case? Um Actually it's uh in this case it's one in this case it's to this case it's six so we can really sub substitute that in. And um what is the laplace transform of 12 and three? Well it's that constant over S. So it will be one over S. To over s. -6 arrests. So let's let's find out what the final laplace transformation is going to be a capital F. Of S. Well that's gonna be eat the minus S over S. And we'll see argument of linear combination with a plus Uh to E. to the -3 s. and -6 E. To the minus for us for this S right there. And that concludes our problem

Hi, everyone. Today we are going to solve problems on the 10 here We had to find the loveless dance off 50 benches in going toe you to the color minus Do do u minus long saying but a de a minus for into you learn off so left less trance alof fine. Three days Do you buy? Yes, where plus rivka, If it's my departed by it'll about minus droopy. And then Intertainer is 23 by as plus to the whole square, I believe birthday by shifting property this second Those have been globality Big Ben because off day minus learn people. Right? But kids more minuses into how do you define it? But yes, Buster, the host. Plus that is God. That's enough for a question. Thank you.


Similar Solved Questions

5 answers
Using the electrospray ionization (ESI) spectra of the two different unknowns shown below,determine their respective molecular masses The spectra very recorded using dilute sample solutions organic solventsMa SpectnmESI (+)1J8.000e+38.0e+26.0e+2110.00Oe+2195,002.0e+2200.0250.0300.0350.0100.0150.0Miss SpecinumL37.01,0e+3ESI ()8,de+2179.0.6.0e+24.0et22.0e+20.0- 80,C0140.0160,0100,0100,0120,0
Using the electrospray ionization (ESI) spectra of the two different unknowns shown below,determine their respective molecular masses The spectra very recorded using dilute sample solutions organic solvents Ma Spectnm ESI (+) 1J8.00 0e+3 8.0e+2 6.0e+2 110.00 Oe+2 195,00 2.0e+2 200.0 250.0 300.0 350...
5 answers
PhPh2 CH3OHOHCH3OOCH?HOSLto details, including lone pairs, formal charges and the use of curved arrows_ close attention Pay B) (14 pts) Provide a conplete mechanism for the following reactionheat 2) H2SO4188WYd ' [Phlone pairs, formal charges and the use of curved arrows to details, including Pay close attention A) (40 pts) Provide a complete mechanism for the following reaction IIIA
Ph Ph 2 CH3OH OH CH3O OCH? HOSL to details, including lone pairs, formal charges and the use of curved arrows_ close attention Pay B) (14 pts) Provide a conplete mechanism for the following reaction heat 2) H2SO4 188WYd ' [ Ph lone pairs, formal charges and the use of curved arrows to details, ...
5 answers
SANpLe1; 1 ] iJiuU04nnQ75a7anmPedZNu0 HOVLMUNlrsWana
SANpLe 1 ; 1 ] i JiuU 0 4nnQ 75a 7anm Ped ZNu0 HOVLMUNlrs Wana...
5 answers
Traveling particle has position vector at time t given by r(t) =< t cos t,t sin t,9 _ t2 > Find its speed at t = 1
traveling particle has position vector at time t given by r(t) =< t cos t,t sin t,9 _ t2 > Find its speed at t = 1...
5 answers
1.17 Given tan 0 = -V3 and cos8>0 , find 0<0<21 .AS0 = 3B0 = 2T 30 =4 30 = S2 3
1.17 Given tan 0 = -V3 and cos8>0 , find 0<0<21 . AS 0 = 3 B 0 = 2T 3 0 =4 3 0 = S2 3...
5 answers
Use 1336 8 0.235 1515 W Simpson'8 function t0 answer 1n3rd the method question with 1 number ol points integrate y from 0 t01Click Submicto complete this assessment:
Use 1336 8 0.235 1515 W Simpson'8 function t0 answer 1n3rd the method question with 1 number ol points integrate y from 0 t01 Click Submicto complete this assessment:...
5 answers
~/5 POINTSMy NoTESFind a power series representation for the function; find the interval of convergence: (Give your power series representation centered at x = 0.)"*)provided
~/5 POINTS My NoTES Find a power series representation for the function; find the interval of convergence: (Give your power series representation centered at x = 0.) "*) provided...
5 answers
Thin rod cf leng-h 2.25 and mass 14. rctated at an angular speed cf 3.95 rad/s around 3n 2X15 perpencicular to the roc anc througn cne of ends Find the magnitude of the rod's angular momentum 24.496 Ycur response differs from the correct answer JY more than 10% Double check your calculaticns kg m2/5
thin rod cf leng-h 2.25 and mass 14. rctated at an angular speed cf 3.95 rad/s around 3n 2X15 perpencicular to the roc anc througn cne of ends Find the magnitude of the rod's angular momentum 24.496 Ycur response differs from the correct answer JY more than 10% Double check your calculaticns kg...
5 answers
Evbule the fblowing integral22 +49) panal fracton decompos ion Used evaluate t8 given iniogral? Seloct the correci cholce below and; # necessary nIl Inte answennax comcel Ymir EenYes. partial fraction Ceccmposiion can be used The given teg4 No; parlial tracton decompasiton cannat be Used Euttlta the indefin te Integtal[eunten RJo) dz which i moru teadil; OY4 Jaled207 +49) (UaC 48 Enc arbitrary Cotstant )
Evbule the fblowing integral 22 +49) panal fracton decompos ion Used evaluate t8 given iniogral? Seloct the correci cholce below and; # necessary nIl Inte answennax comcel Ymir Een Yes. partial fraction Ceccmposiion can be used The given teg4 No; parlial tracton decompasiton cannat be Used Euttlta t...
5 answers
8 2 2 2 2 3 2 pl!i XF 2 8 7 L 88 1' L€ NL 8 F 3 1 8 # " 1 4 1 HLI 8 64 2 1 { 8 2 Tia 2 2+ 8 Ale I [ 1 1 4 [ [[ 2 74 2 {2 8 [ 8 } 2 24 3 if 2 1 3 2 8 2 JW 8 F Z 2 3 [ NF 1 8 8 8 0 u 0 8 5 1 iL 83 6
8 2 2 2 2 3 2 pl!i XF 2 8 7 L 88 1' L€ NL 8 F 3 1 8 # " 1 4 1 HLI 8 64 2 1 { 8 2 Tia 2 2+ 8 Ale I [ 1 1 4 [ [[ 2 74 2 {2 8 [ 8 } 2 24 3 if 2 1 3 2 8 2 JW 8 F Z 2 3 [ NF 1 8 8 8 0 u 0 8 5 1 iL 83 6...
5 answers
It' $ ssumed that the amino acids are thc first candidate protect body fluid against any PH change, are you agree or disagree relying on your titration curve
It' $ ssumed that the amino acids are thc first candidate protect body fluid against any PH change, are you agree or disagree relying on your titration curve...
5 answers
ZIUIIVE1V = I-V (pV =I-V (9 = Mwp (q1 = IV (e 6an1 S! SuMO[[O J41jo YPYM "Wa4L M3 V S3J11BU JLJUUKs EX€ JO poeds J01324 241 2q M 12Teize} eyeaJelijuiinexauaizi a^ wnanaJeixeufexejueldSixeq /auag
ZIUIIVE 1V = I-V (p V =I-V ( 9 = Mwp (q 1 = IV (e 6an1 S! SuMO[[O J41jo YPYM "Wa4L M3 V S3J11BU JLJUUKs EX€ JO poeds J01324 241 2q M 12T eize} eyea Jelijuiinex auaizi a^ wnana Jeixeufex ejueld Sixeq /auag...
5 answers
{ Help? Write the equatlon Through (4, and of the Ilne (-1 descilbed
{ Help? Write the equatlon Through (4, and of the Ilne (-1 descilbed...
1 answers
$$\begin{aligned}&\text { Given: } \widehat{\mathrm{AB}}=108^{\circ}, \widehat{\mathrm{CD}}=62^{\circ}\\ &\text { Find: } \angle \mathrm{AXB} \text { and } \angle \mathrm{Y}\end{aligned}$$ CAN'T COPY THE GRAPH
$$\begin{aligned}&\text { Given: } \widehat{\mathrm{AB}}=108^{\circ}, \widehat{\mathrm{CD}}=62^{\circ}\\ &\text { Find: } \angle \mathrm{AXB} \text { and } \angle \mathrm{Y}\end{aligned}$$ CAN'T COPY THE GRAPH...
1 answers
Write a quadratic equation in general form whose solution set is $\{-3,5\}$
Write a quadratic equation in general form whose solution set is $\{-3,5\}$...
5 answers
Capacitors C1 = 8.00 nF andC2 = 4.00 nF are connected in parallel to abattery. If the chargeon C1 is 4.00 nC, what isthe charge on C2?
Capacitors C1 = 8.00 nF and C2 = 4.00 nF are connected in parallel to a battery. If the chargeon C1 is 4.00 nC, what is the charge on C2?...
5 answers
Find the volume of the solid with vertices (0,0,0), (0,0,1), (0,2,0), (2,2,0)
Find the volume of the solid with vertices (0,0,0), (0,0,1), (0,2,0), (2,2,0)...
5 answers
10. compound with the molecular formula CsH:Oz has the following IR and IH NMR spectra_ Wavelength, (um)NEAT420)WAVENUMBERS (cmNICOLET 2oSX FT-IR'H NMR SPECTRUM (Solvent CDCIz; 100 MHz)Integration from left to right: 10 ppm - 1 H 7.8 ppm _ 2 H 7.0 ppm _ 2 H 3.9 ppm - 3 H
10. compound with the molecular formula CsH:Oz has the following IR and IH NMR spectra_ Wavelength, (um) NEAT 420) WAVENUMBERS (cm NICOLET 2oSX FT-IR 'H NMR SPECTRUM (Solvent CDCIz; 100 MHz) Integration from left to right: 10 ppm - 1 H 7.8 ppm _ 2 H 7.0 ppm _ 2 H 3.9 ppm - 3 H...

-- 0.018699--