Consider the ionic bonds between $mathrm{Na}^{+}$ ions and $underline{mathrm{Cl}}^{-}$ ions in $mathrm{NaCl}(mathrm{s}) .$ Why must energy be added to break these b...

Why is the formation of solid sodium chloride from solid sodium and gaseous chlorine exothermic, even though it takes more energy to form the Na+ ion than the amount of energy released upon formation of Cl-?

So in this problem to find the only course of energy. We're just putting on numbers into this expression, this Cuban right operative question freely. 9 49 in a textbook. Um, so the curse wanting numerical value is simply negative Some 0.9 electoral rolls.

All right, this question is asking about lattice energy and wides and why it is important when for me, I on Bonds. So remember the definition of Gladys Energy. Gladys Energy is the energy released When an Ionic bond is formed, they noticed the key word energy released. That means that it's an energetically favourable process. Remember, it's a reaction. Absorbs energy. The direction absorbs energy. It's not likely going to happen unless you put energy into the system. But if a reaction releases energy, then that's likely to happen. Spontaneous. Therefore, um, when you have a so called negative lattice energy when energy is released, dude, due to the formation of bonds of that allows Ionic bonds to occur, and that's lettuce energy and why it's important.

The bond energy is the energy that you have to put in to break a Covalin bond. So therefore, the higher the bond energy or the Bond Association Energy Bond Association energy, the stronger the bond hire, um, bond strength.

Okay, so we know that I honest confirmations are Exeter, Mick. That means they release energy. And we know that the lower energy the product is, the more stable the original reactions are.