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The picture shows a picture of a 'jewel beetle" taken in sunlight. The iridescent green color occurs because the carapace-i.e-, dorsal exoskeleton_~acts a...

Question

The picture shows a picture of a 'jewel beetle" taken in sunlight. The iridescent green color occurs because the carapace-i.e-, dorsal exoskeleton_~acts as a reflection diffraction grating: Calculate the separation between corrugations in the surface; assume normal incidence of the white light, green wavelength ^, and reflection angle Br

The picture shows a picture of a 'jewel beetle" taken in sunlight. The iridescent green color occurs because the carapace-i.e-, dorsal exoskeleton_~acts as a reflection diffraction grating: Calculate the separation between corrugations in the surface; assume normal incidence of the white light, green wavelength ^, and reflection angle Br



Answers

The wings of some beetles have closely spaced parallel lines of melanin, causing the wing to act as a reflection grating. Suppose sunlight shines straight onto a beetle wing. If the melanin lines on the wing are spaced $2.0 \mu \mathrm{m}$ apart, what is the firstorder diffraction angle for green light $(\lambda=550 \mathrm{nm}) ?$

Hi, everyone. This is the problem based on concept of diffraction. Grating. Yeah. Mhm. Yeah, Foot. I meant to order Bright Fitch. Jeez, I knocked it to to be m number for first order. Angle of reflection, building sign and worst of bold and gravity prevalent is given. Yeah, 5. 50 nanometer and which is given birth of each unit is given two in 2, 10 to the power by the six. So it is to be 15.96 degree, That's all. Thanks for watching.

In this problem, we're going to calculate the frustrated by friction angle that is you don't want in order to kill her. This angle view the question. Do you sign puta? M equals two. I'm Linda. Yet this disease that we call the Sleepytime untangle Responding to this and fringe on this Linda is the different of the light. For first order their friction angle we can white square in as a one equals two. Our sign off land Are you wanted by D? And if you call that equation about one when setting winners into the square we can write it. R one equals two. Our final We have waited for this. Linda is 550 multiplied with tourists for money. It's nine meter divided by the video 2.1 Terrorist money six. So this will give us a value for these, Peter. One is the one equals two 15 point 96 degrees. But it can be return as Peter one equals two 16 ing. So this is around. Thank you

We have to. We've, Linds. One is for red. On one is for a while. It for a light inside a diamond. Um, we can. Right? So we are asked to fight. What is the angle off separation between these two lights inside the diamond after their reflected offer refraction. So after a fraction were asked to find, um let's say this is for this is for red, and this is for a while. It so I'm right to your for wallet and our for red. So the angle of incident both lights, the light is making water is 53.5 degrees. Thank you for five minutes. So we will write a snail's law for this. So angle, uh, refractory. Next off air times the angle off incident here, which is a teddy K that is equal. Do untracked index for the wallet for the wall. It's over. Right. Uh, we hear V for the wallet inside Diamond Times. Um, sign off Anglo for a fraction for a wallet. So right that I'll be here. And then we will solve for battery. Here we are given the refracting nips off areas one, but we don't know the effect index off home off for a while it might for a diamond. We could find that using relation in reflecting dicks for a wallet Can Britain? Is the revenant off a light in a vacuum over the prevalent off the toilet? That's me. Then we can solve. We can plug this value here after planning that value. Then our that afford toilet becomes later for world becomes signing Worse sign in worse times one times sign 53 53 0.5 degrees The incident angle or the refractory next envy. So every weekend, right is a the revenant off light in the bedroom or the welland off a boil it light. If he saw this, then we will get the, uh, the angle for the Royal it. And then similarly, we will do the same procedure for red light. The only difference will be we will replace Lambda. Be here by Linda are so we'll write here signing worse one times the same thing site. So this is for right So I'll write to kept a lot of year sign signed 53 angle off incident five or or we have, um, the lender in Iraq Yume or the lambda for, uh, red light. So But I will just use capital are for this. So road use our, um by just playing there. Those values then we can find that are here also did it. So angular Suppression between these two will be written Is Delta t better, which is that they are minus said, uh, really end off the problem. Thank you for watching.

In this problem. We're just going to apply Snell's law twice. We're gonna plant first for the red light, which is the 400 a meter case. So for a red light, that's a lie. Snell's law, the index of refraction outside is just that ofher soul 0.0 time sign of the incident angle just 53.5 is equal to the new refractive index, which is two point for woman. But this is for red light. So it's 2.41 for red light time. Sign off refracted angle for red light. And so we can solve this now, before the refracted angle red light. When we do that, we get that this value is 19.48 degrees. And so this is the angle of refraction on ly for the red life. Now we're going to do the same for the violet light. So for the violent light, which is, uh, I think I messed up here. This red light is actually the longer wavelength. So it's 700 years. The violet light is the shorter, wailing like that. This is correct. Still. Oh, so now when we solve this equation, is gonna be the exact same thing. Pretty much just one number is going to change. This 1.0 is not going to change because we're still entering from the same medium and we're still entering at the same angle. So this is not going change. But now this next of refraction for Violet Light is going to change the 2.46 And this is just given in the problem here. This 2.41 in the 2.46 they're given problem so then and like himself for the data for violent light. And when I do that, I get 19.7 degrees. And so they figure out my own angular separation. I simply take the difference of these two extremes, and so I'll take this one and subtract this one. When I do that, I get about 0.41 degrees and that's the end. Your separation


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