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WEB Write a balanced net ionic equation for the reaction of each of the following aqueous solutions with $mathrm{OH}^{-}$ ions.(a) ammonium nitrate(b) sodium dihydr...

Question

WEB Write a balanced net ionic equation for the reaction of each of the following aqueous solutions with $mathrm{OH}^{-}$ ions.(a) ammonium nitrate(b) sodium dihydrogen phosphate $left(mathrm{NaH}_{2} mathrm{PO}_{4}ight)$(c) $mathrm{Al}left(mathrm{H}_{2} mathrm{O}ight)_{6}{ }^{3+}$

WEB Write a balanced net ionic equation for the reaction of each of the following aqueous solutions with $mathrm{OH}^{-}$ ions. (a) ammonium nitrate (b) sodium dihydrogen phosphate $left(mathrm{NaH}_{2} mathrm{PO}_{4} ight)$ (c) $mathrm{Al}left(mathrm{H}_{2} mathrm{O} ight)_{6}{ }^{3+}$



Answers

Write balanced complete ionic and net ionic equations for each reaction.
a. HCl(aq) + LiOH(aq)-H2O(l) + LiCl(aq)
b. MgS(aq) + CuCl2(aq)-CuS(s) + MgCl2(aq)
c. NaOH(aq) + HNO3(aq)-H2O(l ) + NaNO3(aq)
d. Na3PO4(aq) + NiCl2(aq)- Ni3(PO4)2(s) + NaCl(aq)

This question addresses ionic equations. Um they're asking us to write based on what we're given complete and net ionic equations for each example. So for the first example, we were given that we have potassium sulfate reacting with calcium iodine to produce a solid calcium sulfate and Equus potassium iodine. So the little acquis subscript always represents the fact that that means we have ions independently floating around in solution. So if we were to rewrite sort of what's going on um in terms of the potassium sulfate, we really do have free potassium ions floating around and free sulfate ions floating around that are available to react with something else. Same case is true here of the calcium iodide, we have calcium ions and iodide ions that are floating around in solution. And in terms of our products, we have potassium and iodine ions that ultimately are going to be formed as part of the product or be left as part of the product. So only in the case of this calcium sulfate solid, do we not have free ions that are capable of reacting with something? In fact, we have combined those free calcium ions, the sulfate ions and they are no longer sort of free to roam. Um They now become part of the solid material and are essentially tied up. The only free ions that are still left are those potassium and iodide ions and these are what we refer to as spectator ions. So spectator ions do not combine to form a solid, they really aren't part of the reaction there, just present as kind of like Spectators in an audience that are just there to um help drive the reaction or the process. So, um in a net reaction, we don't show the spectator ion. So the the net reaction, this would be the complete reaction completely balance showing every species involved, even the spectator ions and the net reaction or process. We would show only the ions that interact. So that would be calcium and the sulfite and we would show the formation then of calcium sulfate solid is our net reaction and leave out the spectator ions in this example, the next example we're going to write this little distinguish it a little differently than they did at the beginning by showing each of the independent ions that's involved here. So instead of saying ammonium chloride, we divided into the ammonium and chlorine ions and instead of saying sodium hydroxide we divided it into sodium and hydroxide ions because we know that's how these ions independently exist in solution. So what ends up happening is water is a liquid and ammonia gas are formed and we have I bet you can see here to spectator ions, right, the sodium and chloride ions. Um our Spectators here, they're the ones that just kind of sit by and watch and really aren't present or part of I think overall chemical bonding or reaction um that exists here. And so um if we were to write this as a net reaction as we did above, we'd simply include the ammonium and the hydroxide. And show the products that they produce the liquid water and the ammonia gas. And again leave out the spectator ions when we're writing a net reaction. So this would be an example of the complete reaction showing all of the ions and species involved. The net reaction just shows those species that are involved in making the product and not the spectator ions. So next example, pretty straightforward as well. We're combining silver nitrate here. So we have silver cat ions, nitrate and ions floating around along with sodium chloride. So we have some sodium and chloride ions floating in solution. They combine to form a solid silver chloride And here again, our spectator ions. So again, the complete picture looks like this, showing all ions that are present in solution. The net ionic solution will only show those that combine to make um a solid or given material while ignoring those spectator ions that are not involved in the process. So overall net reaction looks like silver ions combining with chloride ions to form that solid silver chloride. A final example takes a look at acetic acid. So acetic acid furnishes like a good acid, some protons along with its conjugate base. The acetate iron and those will be um divided up into ions in solution along with reacting potassium and carbonate ions and the products that we form are going to be water and carbon dioxide and here are our spectator ions, the potassium ions and the acetate ions. So they're not going to be non factors here and again. These are our Spectators there, cheering you on the sideline but doing little else. So the net reaction for this process shows those hydrogen ions coming together with the carbonate ions to form that liquid water And that co two gas.

See the frustration Here we have. Jack was a city usage reacting with ek was burying my drug sign. So first you write down the porter's off this relation with you all day barium pass it in, which is also salute in water. And that's how it'll back wass and we'LL have water Now I have to balance this equation So is started the medal and we will make sure that we have same number of metal atoms in both sides It's our mental here is very um we have one Very, um here and one very m here. Then we'll have flu Funny non metals are any in a group off atoms which is acting as radical here. So if we have any group of Adam intact in both sides, then we can We don't need toe count each adams in it individually. Instead, we can count the total group of atoms as the one So here we have. The faceted group is intact in both side in that Mexican counted altogether. So you have two exited group here and we have one here that missy have tomato bread this side by two. Now we have to. So after balancing metals nor medals and group off atoms. We have to balance high treason. So now here we have two hundreds in here and we have two hundred and here saying totally have four hydrogen in this sign and in the product side we have quiet reason that Mr to multiply the product signed by two. We have four presents in the product side also. Now we have ah forehead reasons here and in total for hydrogen in the reactor site and finally had to balance oxygen. So we have two oxygen here and we have two oxygen here. That means oxygen is also ballast. So this is the balanced molecular equation for creation. Now we have to write down the total iron education of distillation if you want to write the NATO and immigration So in case of total and education we will write the compounds in their ionic form. If they're strong electrolyte or there'LL be strongly, strongly associated or completely dissociated into their irons. So, um since acid I guess it is a weak acid, it will not completely ionized air completely dissociated into exiles. That's why we will right as city Gacy in its molecular form then barium hydroxide being a strong base that miss it will be completely ionized related in the Ionic form. Now we have proof as it did here. Are you a citizen? And we will write the barium hydroxide in the ironic form and in the product we will have so bury a massive did will be completely ionized And that's way um, we'LL have tto write this as barium on and as it did on. And now we have to look for the spectator rounds are common ensemble sites and here we can see that we have Barry Amar in both side and you could cut them. And the rest is our NATO Donaghy creation safer. Just got this true from here the barrier miles from from both sides. Then the reaction we have or the question we have is basically to see three c w h plus to wish minus is equal to and oh, here we had our twitch tool ceases to his l'equipe to not pay It believes in the commuter molecule of form. So you're in the reactor site. We'LL have a prestigious in two hundred signing the product side We have ah two c's three serial miners and which tour? And if we just write them in if fresh equation here it will be to see through see, never age plus two is minus in a quiz form I didn't give us USC Tate plus Jewish tool Come. So here is our net an equation for this creation here. Then we will go to our next one where we have home solid chromium hydroxide is active with nitrous ascent So here our actually question always here always three since it is solid from your grated Sahlin and it is reacting with Nitra Assassin agent too, which is obviously Akwa since it's a soluble in water and in the product we have chromium nitrate class is too Now To balance this equation, we'LL have to balance the chromium Sze first was the metal So we have one chromium in his sight. Then we have to Ah, Bella's the nitrate group here, which is a group off Adam's. So we have one nitrate here treated right here that missing tomorrow, right? She's on my three now we have nitrate balanced. Now we have to go for high treason. So you have in the reactor and said we have three had risen and three hundred in total. Six had risen your dark side. We have glide risen. That was a modified with three to get six had risen on the product side also and now we have to balance the oxygen's. So we have three oxygen and six oxygen here, two times two Sikhs and plus three that ms In total, we have nine nine oxygen in the reactors side. In the product side, we have three times two Sikhs and three blustery That missed nine oxygen in there in the products that also So this's our balanced molecular equation for registration. Now I've read the total and education So chromium hydroxide being solid, it will remain a solid in the interrogation also. Then we have to go. So a genital being equals It will be ionized into its H plus And you know, to Mina san and in the broad out we don't have chromium. In this case, chromium nitrate is also Acas R is soluble in water. That's it'LL be remain as here Tripolis and three you know to minors and finally we have three water. Now we have to look for the common aisles and we have remove them from the equation tohave the NATO an equation. So the common and here is nitrate on, so only nitrogenous common. And if we just cut the nitrate ion, we can write the name Tiny question, which is see our wage. Treem will react to it three h plus to provide Sierra Tripolis and traced to him. So this is our net on education forthis reaction. Now we go for the last one where we have a quiz. Night creatures city neck was ammonia reacting. So AC wass nitric acid a Channel three classic wass ammonia will produce anything for Plus, Hank was and you know, three minus. Now, if you wantto balanced this equation, let's look for any medals here, so I don't have any metal here. Then we start with the non metal. So we have. We have nitrogen here, one nighters and here and one night wasn't here. And then we have one night trade group here. Oh, one nitrate group here and one nitric moving the product side else. Um and then we have four had risen in the reactor sign and four hundred on the parasite. So the reaction is already balanced you don't have to balance it. Now let's go for our total and education's a Channel three being strong electrolyte, it will be completely ionized. Let men still write it as H plus and they're not three minors and and one day I will be an ex Monica or farm on the port side. We have both already in the attic. From now here we look for a suspected Ryan or the common, and on both side of the question here we can see that nitrate down is common in both side. Then we can cut them right, our net on medication that will be h plus creating with finished treem to produce and if you four plus. So this is the net on education for destruction.

Let's balance the following reactions for a We're gonna do this in basic conditions and oh H two solid plus H +202 Aquarius in base would yield M N oh h three solid. Let's break this apart under to have reactions. M N O H two solid T o M N O h three solid. Magnus is balanced on each side to oxygen's on the left. Three on the rights of H 20 on the left. That leaves Muth for 24 Hydrogen is on the left. One hydrogen on the right and one electron on the right, H 202 And to balance this will put to H 20 to balance the oxygen's and four hydrogen to H plus to balance the hydrogen. Two electrodes to balance the charge. I'm gonna double this half reaction here that would allow me to cancel out the electrons. This will leave me with two. Uh, sorry. Each tool would also council each plus would also council, and I am left with, uh, M and uh, M N o h two plus h +202 thio to m N O h. Three solid. And there's my balanced reaction. This one is neither acidic or basic. It's done just in, um, in neutral conditions, but in the presence of base for be we have m n four to minus mhm in the presence of acid to produce M N 02 solid and m n 04 minus acquis. Let's break this apart into two separate half reactions. M N 02 solid manganese balanced to H 20 to balance the oxygen or H plus to balance the hydrogen into electrons to balance the church and four to minus. T o M n four minus one electron develops the charge. I'm gonna double this here, and I am going to find that the electrons will cancel and those are the the only things that will cancel. So I'm going to be left with Yeah, I am in a four to minus um three m And before we can combine those together and for H plus to, uh m n 02 solid and to m n 04 minus and to h 20 And there's my balanced equation for C. We're going to balance this in acid. We have high, 03 minus, and I minus in the presence of acid, and this will produce I three minus. Let's break this up into two half reactions. Let's first put a three here develops the ID. I'm nine h 20 to balance the oxygen. 18 age plus to balance the hydrogen. You know, it's balanced. The charge have minus one on the right. Mm hmm. That's three. So I'll need 16 electrons to balance the church. Second half reaction. Put a three here to balance the electron or the iodine and two electrons. To balance the church, you need to multiple of the first half reaction by one second. Half reaction by eight 16 Electrons 18 age plus three. I owe three minus I three minus nine inch too old and times 8. 24 I minus eight I three and 16 electrons. 16 electrons were canceled and I'm left with three. I owe three minus 24 I minus 18 age plus 29 i three minus and nine h 20 Lastly for D. This is taking present in base p solid at p 43 minus will produce in base H P 003 to minus equals. Let's break this up into two. You have reactions. Well, phosphorus balance on each side. Three oxygen's on the rights of three. H 20 on left. Six hydrogen on the left. So five hussian on the right. This would be three electrons on the right to balance the charge. Phosphorus is balanced on your side. I need each 20 on the rate to balance the oxygen. That will leave me worth three hydration on the rights or three h plus on the left. Its balance. The charge. Here we're neutral minus two. So add two electrons on the left hand side times three times to so six h 20 piece to piece solid thio to H P 03 to minus 10 h plus and six electrons. Times three for the next 16 electrons at nine h plus three p 043 minus three h p 03 to minus three h 20 six. Electrons will cancel three h totally from three on the left. Nine h plus would leave me with just one h. Plus. It's put this all together here. Two p solid. Add three p 043 minus at three h 20 right. 25 h p 03 to minus and one each, plus switch this to basic H plus. We cancel each totally two on the left, and our final equation is this equation here that is balanced in basic conditions.

Asking us. Toe right, the balance net Ionic equation for strong tm hydride and potassium hydride both reacting with water. Now these are both Ionic hydroids, which means when they react with water, they're going to produce. It's to gas and an O. H I on in both cases. So we're gonna watch for both of those in the products on each of these. Now, for part, a strong Thiam is going to be one of the group to a metals. So we're going to write that as us are, it's too solid is going to react with water. It's a liquid, and it's going to produce some amount of hydrogen gas as well as strong Tia, my on and some amount of hydroxide ion. Now, really quick, let's make sure that we have balance to this. So we have one strong team on each side. That's fine. We have one oxygen here, one oxygen here, But let's look at the hydrogen XYZ We have four on the left and only three on the right. So one thing I'm gonna go ahead and do is I'm going to add it to here. So then we will have to six on one side and then attitude there and one there because we're balancing the numbers of hydrogen and oxygen. Check again. Strong teams. Okay, six hydrogen is on one side, sex on the other and to oxygen's on each side. So this is the balanced net. Ionic equation for strong. I'm hydrated for potassium hydrate. It's going to be the same process, except in this case, potassium is a group won a medal, so we're going to write that s K each plus it's +20 That's a safer solid. That's liquid. And that's going to react into hydrogen gas. Plus a potassium ion can't forget units. And then our hydroxide ion still had set up there as well. And just a check the amounts of K or equivalent three here. Three. Here, this is balanced. So the Net Ionic equation for potassium hydrate and water is that


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