5

The CO() water can be reacted with HzOvg) in the following reaction: CO (2) HzO () < CO2 (g) Hz (g). At 90o K; Ka = 1.S6 for this reaction; The initial partial p...

Question

The CO() water can be reacted with HzOvg) in the following reaction: CO (2) HzO () < CO2 (g) Hz (g). At 90o K; Ka = 1.S6 for this reaction; The initial partial pressures of CO _ (g) are and HzO 0.23 atm and 0.23 atm respectively. The initial partial Hz (g) are 0.4 atm and 0.4 pressures of COz (g) and atm respectively. (R = 0.08206 L. atm mol. K)

The CO() water can be reacted with HzOvg) in the following reaction: CO (2) HzO () < CO2 (g) Hz (g). At 90o K; Ka = 1.S6 for this reaction; The initial partial pressures of CO _ (g) are and HzO 0.23 atm and 0.23 atm respectively. The initial partial Hz (g) are 0.4 atm and 0.4 pressures of COz (g) and atm respectively. (R = 0.08206 L. atm mol. K)



Answers

The equilibrium constant $\left(K_{P}\right)$ for the reaction $\mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}(g)$ is 4.40 at 2000 K. (a) Calculate $\Delta G^{\circ}$ for the reaction. (b) Calculate $\Delta G$ for the reaction when the partial pressures are $P_{\mathrm{H}_{2}}=0.25 \mathrm{atm}, P_{\mathrm{CO}_{2}}=0.78 \mathrm{atm}, P_{\mathrm{H}_{2} \mathrm{O}}$ $=0.66 \mathrm{atm},$ and $P_{\mathrm{CO}}=1.20 \mathrm{atm}.$

So to find the partial pressure of our CO. Two, we'll use the ideal gas law which is N. RT over V. So we'll put in the malls and our is point a week to one And we're at 500 Kelvin And then we'll divide by the volume which is two leaders. So that will give us a partial pressure of 4.10 ATM For our co two Partial pressure or ever H. two. We'll just use it's malls. It's got half as many moles. So it's gonna have half the pressure. We'll go ahead and plug all this in. But you can see where we're going here. True. So we're going to get 2.05 ATM of our hydrogen and then finally the vapor pressure of our water. 1600. We've got our or temperature Divide by two leaders. And that will give us three .28 ATM over the water vapor. So those are your partial pressures. So let's go ahead and make a write an equation and make an ice box to keep track of what's happening here. So this is our reaction mm twice initial change in equilibrium. So 4.10 In 2.5. We don't have any co to start. So we know this reaction is going to go forward and we know that At equilibrium. We have 351 for the water. So let's fill in what we know. So this must have gained 0.23. So at the same time I would have gained .23 of this and I would have used up to three at more of these. So that gives me 3.87 And 1.82, 10.23. And those are all in atmospheres so we can plug in the K. P. Expression. Right? So our products are 2 3 Times 3.51 and divided by our react mints, Which are 3.87 And 1.82. So that gives us a k p A .11.

From the first case. Let's calculate the equilibrium constant as all of our concentration are all of our partial pressures or add equilibrium, unplugging all of our values here get 0.60 0.30 and 0.10 You can find the equilibrium. Constant years equals 20. We're then going to increase the concentration of seal, too. So let's set up a nice table to show this. And this would be or is table here our initial values and should be 0.30 10 plus the additional point for zero that gets added in this is 0.60 The shift because of the increase in seal to listen ties principal shift away from the increase Loomis would deal 0.30 minus X point by zero minus X and 00.60 plus X uh, equilibrium Constant was 20. Plug in here. And for this expression here we do get a quadratic equation. Solving for the quadratic equation will yield us two routes. We will get through a 20.67 band 0.18 will reject the 0.67 as it does not agree with a race table. And now we're as to find the pressure of C o eso. This is defined as the partial pressure CEO at equilibrium was 0.30 minus X. So this would work out to zero point, um 12 atmospheres, and that is the partial pressure of C O at equilibrium.

Problem 39. But in part a We need to calculate initial appraisers obscure together as to God's and that triggers we know that PV equals two Nrt from Real gassy question. Therefore Pressure Equals two. Can we can right and artie divided with. We use this real basic question to calculate faces. Sorry to calculate initial partial pressure of co two H 2 and H two guests. So tunisian parcel pressure up. See you to guess is after putting the value number of giving their number of moles. See your two guests. 0.2 00 zero moles multiply by hi wended Calvin. Do you hide it where? Two leader multiply way 0.0 8 to 0 six liter ADM. Do you hide it by mole Calvin? After calculating we get poor point 1030. Approximately calls to poor point €1.80 M. This is the initial partial pressure drops you to guess. Similarly parcel places up at tigers calls to 0.1 000. Mall multiply by 500 Calvin, divided by two leaders. Multiply by 0.08-0 six. Later 80 divided by mole Calvin. That is equal to two points 051 pipe. That approximately equals two 2.0 pipe, etienne. And lastly, are still pressure. Initial partial pressure off ach two guests. It equals two zero point 16 double zero moles. Multiply by 500 Calvin temperature divided by two L of volumes. Multiply by Gas constant art. That value is zero 08 two 06 League Leader 80. M. divided by small television. After calculating, we get three point 282 poor approximately equal two 3.2880. This is our answer apart 1st his party in part B. That change given that at at equilibrium partial pressure of water is ah three point Hi Vanadium. So changing a partial pressure of S. two is door is three point hi bone minus three point do it. That is equals two zero point two 76 Approximately 0.23 idiom positives. And so that uh press it up as to at equivalent increases. So given the equation, see you to guess. Bless that's two guests. Gibbs C. 0. 2 gas plus at two gas mm we calculate initial present of C. 02 S. Two. C. 02 has to go through. And sorry, this will see you guessed. Mhm. So initially really upset your to guess as to gaga's yoga's and as to gas initially. So you two gas fields 4.10 ADM as to guests, 2.0 pipe A. T. M. C. Elegans And 0 80. Um and at two gas is three to A. T. M. Sends given that we can calculate standing at two Partial pressure of S. two is bless zero point 23 88 he had. We here we calculate this sense similarly partial prison changing a partial partial paste ropes. Yoga's is less 0.23 80. Um Therefore consent, partial pace drops your gas and estuaries decreases. That is -0.2380 M. And it will all It will also -0.23 etienne. At equilibrium partial pressure drops you to gases. We can and and get the result. Poor .1080 M minus two point 0.238 indicate 3.87 80. M. Similarly, similarly, This is 1.82 hmm. And this is 0.23 80. M. And this is three one 3.5180. Um This is our final answer. Up hard to be in park city. We need to calculate K. P. For this reaction. Keep equals two partial pressure of See You Multiply by partial pressure of H two. A guest divided by partial pressure of CO two gas. Multiply by partial pressure up has to guess after putting the hell you partial pressure of see you 0.23 multiply by three point pi one divided by 3.87 multiply by one point 82 we got That is a 0.11 46. That is approximately equals to 0.11. This is answered up artsy in part today we need to calculate case we need to calculate Casey for this reaction. We know that KPI was to Casey. Rt to the power double time and delta and is the some of the products some of moles of product that is equal. That is two elicited too minus some of um also reacted. This is also too 2 -2. close to zero Data and value is zero. So putting the value of in this question we get there delta KP equals two Casey because our T to the power zero is a cost to one. So keep it for this reaction is I'm sorry mm So keep people this reaction, it goes to Casey for this reaction. That is cause to zero point 1 1 we can calculate here case hair keeping. So this is our final answer up party and this is final answer apart see and this is our final answer of but the and this is final instead of party.

In this question we've been given at the action in which carbon will not say reacts with chlorine to form C. Or C. L. Sure. So for us to determine the equilibrium concentration or the equilibrium pressure pressure of ceo first of all have to look at the initial pressure pressures and then relate them using I see each other that is the initial change. And finally we get to calculate the equilibrium concentration and we're going to use the K. P. To determine the equilibrium concentration. Say for example. Yeah, the initial concentration or partial pressure off C. O. is 0.3 And that of chlorine is 0.5. And we also have several points six of C or c. 0 2. So if C O is going to change by a factor of X, that is it is going to decrease by a factor of X Also means cl two is going to decrease by a factor of X. And it means the all too is going to increase by a factor of Okay, so at equilibrium the concentration of C O is equal to 0.3 minus X. And that of cl two is 0.5 minus X. And the concentration of C O C L two, equilibrium. 0.6 planners. X. So what we now have here we can have an expression of K P. Because K P is the ratio of the pressure operations of photo debated by that of the reactions which is P C of multiplied by pc Eltron. So the KP is 0.6 divided by 0.3 times zero what? It's okay P this is equally true. 20 So at equilibrium, we know that we also heard this expression we're still using the same expression and we now know that it equilibrium. These partial pressures are given as 0.3 minus X. 0.5 minus X. And 0.6 plus X. So 20 is still equal terms 0.6 Plus X Divided by 0.3 -6. Multiplied by 0.5 winners X. So if we calculate this we're going to have an X Being a quality 0.179. Now that we have our X. We know that peak the pressure pressure of sea or at equilibrium is equal to 0.3 -1. So the partial pressure of see who is going to be 0.3 -0.179. So the pressure, the pressure of ceo Equilibrium is equal to 0.12 atmosphere


Similar Solved Questions

5 answers
13.Here is vector field: Fl,>,?) =yzi (r+2y)j+3k Calculate the cur] of this vector field, VxF Calculate the divergence ofthis vector field , V-F Calculate the type-two surface integral ffr-nds, where Binthe colid box Wit and 0 <2<1 and where €B represents the boundary of 0<*<1, 0sY<1 which in class last week [ called the divergence theore [Use Gauss' s theorem,
13. Here is vector field: Fl,>,?) =yzi (r+2y)j+3k Calculate the cur] of this vector field, VxF Calculate the divergence ofthis vector field , V-F Calculate the type-two surface integral ffr-nds, where Binthe colid box Wit and 0 <2<1 and where €B represents the boundary of 0<*<1,...
5 answers
Which of the following carbon hydrogen (C-H) bond stretches appears at the highest wavenumber?0 R-C=C - H0 R Cac_H0 R-C-C = H0 AICHbond stretches occur at the same wavenumber on an IR spectrum and cannot be differentiated.
Which of the following carbon hydrogen (C-H) bond stretches appears at the highest wavenumber? 0 R-C=C - H 0 R Cac_H 0 R-C-C = H 0 AICHbond stretches occur at the same wavenumber on an IR spectrum and cannot be differentiated....
5 answers
In this experiment We Hset hanging WINss of I(0 grams_ IF instend we uSed M:SS of' [((0 Krallis _ wlut woukd be the value of the lirst hArmonic freqpuency?
In this experiment We Hset hanging WINss of I(0 grams_ IF instend we uSed M:SS of' [((0 Krallis _ wlut woukd be the value of the lirst hArmonic freqpuency?...
5 answers
#It pieeu1 10.57718In Anlyt ellettUut1 1
# It pieeu 1 1 0.577 1 8 In Anlyt ellettUut 1 1...
4 answers
How many cycles of PCR does it take to produce eight DNA molecules of the desired size?0 a. 8 0 b. 7 c. 4 0 d.3 e. 5
How many cycles of PCR does it take to produce eight DNA molecules of the desired size? 0 a. 8 0 b. 7 c. 4 0 d.3 e. 5...
5 answers
Problem Write the dual problem of the following optimization problemMinimize2x2 3r, +X4Subject to5x1 4x2 " 311 2x4 = 3x1 5x2 711 944 2 16x1 4x2 214X1 unlimited, X2 20,4 = 0,Xa unlimitedProblem 2 The load data of 4 3-bus SyStem and the asseciated uncentainty set are shown in the folE Lable DZ D3 Uneentainty Uncentainty Uncenainy boud ADZ bouud AL DJ DZandDB I4SMW GOMW Z0MWList all the extreme points of the uncertainty set
Problem Write the dual problem of the following optimization problem Minimize 2x2 3r, +X4 Subject to 5x1 4x2 " 311 2x4 = 3x1 5x2 711 944 2 1 6x1 4x2 214 X1 unlimited, X2 20,4 = 0,Xa unlimited Problem 2 The load data of 4 3-bus SyStem and the asseciated uncentainty set are shown in the folE Lab...
5 answers
Calculate the concentrations of all species in a 1.02 M Na,SO; (sodium sulfte) solution: The ionization constants for sulfurous acid are K, =14X10-2 and Ka = 6.3X 10-8.MNNat][so}-]M[HSO;][HzSOg]M[OH-][#t]
Calculate the concentrations of all species in a 1.02 M Na,SO; (sodium sulfte) solution: The ionization constants for sulfurous acid are K, =14X10-2 and Ka = 6.3X 10-8. M NNat] [so}-] M [HSO;] [HzSOg] M [OH-] [#t]...
5 answers
Real estate investment; originally worth 56000 grows continuously at the rate of 400e0.04t dollars per year, where is the number of years since the investment was made_ (a) Find formula for the value of the investment after years_V(t)(b) Use your formula to find the value of the investment after 10 years_ (Round your answer to the nearest dollar.)
real estate investment; originally worth 56000 grows continuously at the rate of 400e0.04t dollars per year, where is the number of years since the investment was made_ (a) Find formula for the value of the investment after years_ V(t) (b) Use your formula to find the value of the investment after 1...
5 answers
Question 410 poines Saue AnseverLer ffxy) be & function wnich has $ €ritical point at (1, 2) witn continuous partial derivatives: which of the follavng properties jLengugh to conclude that (1,+2) i$ a sadd e poing? fxx (1/2) < 0 ard fy}(+2)<0. Iy[12) < 0. IL Ixx (122}tyy(12) <fsy(122) fyx (1,21 IV: Ixx(1,2) y (1 2)-fxy (12)6y* (1,2)0a IOb OcIOam
question 4 10 poines Saue Ansever Ler ffxy) be & function wnich has $ €ritical point at (1, 2) witn continuous partial derivatives: which of the follavng properties jLengugh to conclude that (1,+2) i$ a sadd e poing? fxx (1/2) < 0 ard fy}(+2)<0. Iy[12) < 0. IL Ixx (122}tyy(12) <...
1 answers
Figure 7 shows the rate $R(t)$ of natural gas consumption (in billions of cubic feet per day) in the mid-Atlantic states (New York, New Jersey, Pennsylvania). Express the total quantity of natural gas consumed in 2009 as an integral (with respect to time $t$ in days). Then estimate this quantity, given the following monthly values of $R(t)$ : $$\begin{array}{llllll} 3.18, & 2.86, & 2.39, & 1.49, & 1.08, & 0.80, \\ 1.01, & 0.89, & 0.89, & 1.20, & 1.64, & 2.
Figure 7 shows the rate $R(t)$ of natural gas consumption (in billions of cubic feet per day) in the mid-Atlantic states (New York, New Jersey, Pennsylvania). Express the total quantity of natural gas consumed in 2009 as an integral (with respect to time $t$ in days). Then estimate this quantity, gi...
5 answers
Ifa regression model is developed by splitting the data into training and validation sets, the least squares prediction equation describesthe training datathe validation data_both the training and validation data.the population:
Ifa regression model is developed by splitting the data into training and validation sets, the least squares prediction equation describes the training data the validation data_ both the training and validation data. the population:...
5 answers
Determine whether the Mean Value Theorem applies to fr) =x on [0, 10]. If yes; find the value guaranteed by the theorem: If no, explain
Determine whether the Mean Value Theorem applies to fr) =x on [0, 10]. If yes; find the value guaranteed by the theorem: If no, explain...
5 answers
When copper metal is placed into a colorless solution ofAgNO3, a change occurs. The solution turns blue nomore copper metal is visible and silver metal appears at the bottomof the mixture. Is this change a physical change or achemical change? Explain how you arrived at youranswer.
When copper metal is placed into a colorless solution of AgNO3, a change occurs. The solution turns blue no more copper metal is visible and silver metal appears at the bottom of the mixture. Is this change a physical change or a chemical change? Explain how you arrived at your answer....
5 answers
What type of biological molecule is this?RHN=C HOHnucleic acidamino acidDNAnone of these
What type of biological molecule is this? R H N=C H OH nucleic acid amino acid DNA none of these...
5 answers
Use the VSEPR model to predict the bond angles about each numbered atom:The predicted angles about atom aredegrees:The predicted angles about atom 2 aredegrees:The predicted angles about atom 3 aredegrees.
Use the VSEPR model to predict the bond angles about each numbered atom: The predicted angles about atom are degrees: The predicted angles about atom 2 are degrees: The predicted angles about atom 3 are degrees....

-- 0.020737--