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Uestion 9points Save AnswerAt standard temperature and pressure conditions calculate the volume of 35.2 g of N 2 gas A 1.57 L B. 44.0 L C.28.1 D. 56.3 L E; none of ...

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Uestion 9points Save AnswerAt standard temperature and pressure conditions calculate the volume of 35.2 g of N 2 gas A 1.57 L B. 44.0 L C.28.1 D. 56.3 L E; none of theseQuestion 9 of 25 Moving to another question will save this response.

uestion 9 points Save Answer At standard temperature and pressure conditions calculate the volume of 35.2 g of N 2 gas A 1.57 L B. 44.0 L C.28.1 D. 56.3 L E; none of these Question 9 of 25 Moving to another question will save this response.



Answers

Calculate the volume of each gas sample at STP. (a) $73.9 \mathrm{g} \mathrm{N}_{2}$ (b) $42.9 \mathrm{g} \mathrm{O}_{2}$ (c) $148 \mathrm{g} \mathrm{NO}_{2}$ (d) $245 \mathrm{mg} \mathrm{CO}_{2}$

Yeah. We have to calculate the volume of each guest. Simple. Uh, so here first we have what, a 48.9 g helium. Modern philosophy. Liam is Foda. Moller Moss is equal to four grand, foreground caramel. And so 48.9 g of helium is equal to we have 48.9 ground appeal. Liam, Um, do everybody before 4 g per mole. So here, Grand Grand Council and we have left it here. 12.2 moles. Mhm. Okay, so more One more occupy here. One more occupy. Oh, 22.4 liter, eight sdp. Yeah, hens. Okay, develop 0.2. Malls occupy 12.2. Multiply 22.4. Nature is equal to 2. 73.28 later. And next is what we We have 45.2 ground Xena on Moeller Moss, right? Yeah. Zino is 1 31 g per month. Yeah. So awesome. 45.2 grounds. Xenon is equal to 45.2131 is equal to 0.34 more. Yeah. So one more. Yeah. Occupy 22.4 liter at STP. So here we have 0.34 more occupy 0.34 Multiply 22.4 later is equal to 7.6 Later. Next Parsi, we have 48.2 merely gram of cl two So molar mass of chlorine is 35.5 grand caramel So here 48.2 multiply 10 Recipe power minus three. Divided by 35 Multiplied two is equal to video 48.2 multiply 10 Rest of the power ministry divided by 70 is equal to we have 0.68 multiply 10 Rest of the power minus three is equal to 0.68 So here one mall but one more occupy 22.4 liter at STP So here 0.68 mall. Okay, bye. 0.15 liters in body. Yeah, three point and three kg s 02 So mother myself is agrees So too is and 64 drum for more So here we have 3.83 multiplied and rest of the power tree divided by 64 is equal to 38 30 divided by 64 is equal to 59.84 malls, one more occupy. All right, 22.4. Later it sdp So here, 59.84 malls. Goodbye. 13. 40.5 later.

We look at these three containers in order to consider their pressures, we have to look at the moles. So there are 10 grams of each substance in here, which means the moles are not equal. I'm the mole. Amounts will be proportional to the pressure of the gas, since they're all the same temperature. So when we compare the molar masses, okay, we don't have to actually calculate them here. But when we look at these elements, if you just quickly look at the molar masses on the periodic table, we'll see that CH four as the lowest Mueller Mass. Which means for 10 grams it will have the greatest amount or the most moles present. So the more moles it has, the higher the pressure will be. So you're

All right. So this is basically this would have to use the ideal gas law, which is pressure times. Volume equals number of moles, times universal gas, constant times temperature. And what we do know is we want to figure out the highest pressure which is circled her here. And the only thing that differs would be the moles, which is right here. So to determine this, to determine what has the highest pressure, we would have to determine what has the highest number of moles and the reason it's so that they stay equal on both sides of the people signs. If this is increased that this also has to be increased. So I don't determine number moles. We have number of grams of each compound here. So it outside methane In addition, trickle ride. And they determined animals You do 10 grams divided by the molecular weight. So then it would be grams divided by grams per mole so that the grounds cancel out in the malls goes back onto the numerator. So eagles just bulls and the market of its over dioxide is round 64 can determine this by looking at the periodic table and adding them together. My memory of nothing would be 16. Am I clear up? This would be over 100 because the story five times three grounds. So we don't really need the exact value because we know that if we decrease the molecular weights, we actually increase the number of moles. Because this is smaller, the turnout in your cellars, you dividing 10 and buy smaller value so that the number of moles is greater. And is this basically has the highest normals right here? You know, that means there's a This has the highest pressure which led to contribute.

This question asked us to calculate the volume of each gas sample at STP. STP means standard temperature and pressure. The temperature is to 73 count been and the pressure is one atmosphere. We're gonna use the ideal gas equation PV equals and R t To do this, where are is constant? It is equal 2.8 to 1 leader atmosphere over mole Calvin So are gonna do here is take these gram quantities and convert them to moles. Um, and then use that to solve with the ideal gas equation. So we're looking for volume. Uh, P pressure is given to us by saying SCP and we can get from the gram quantities are Is this constant over here? And T is also given to 73 Calvin. So starting with water A. We have 48.9 g of helium. Helium has, um, 4 g per mole. So well, I multiplied by one mole. Over 4 g grams will cancel, and that is 12.2 moles. A helium. Some will use that PV equals NRT. Soapy is one atmosphere these were solving for we just solved for end, which is 12.2 no. Are is that constant? Um And then t is to 73. Calvin. So if you saw for B here, we will get to 74 leaders in part B. We have 45.2 g of zine on, um, Zen on has a molar mass of 1 31.3 g per mole. So we'll cancel those grams and we'll get 0.344 Moles of Xena. So again, our pressure is one atmosphere we're looking for. Volume en is 0.3 or four. Moles are is our constant and T issues only agree, Calvin. So so for B again here, where you will get 7.72 leaders important. See, we have 48.2 mg of chlorine eso That is 0.482 g of chlorine milligrams. 2 g is 1000. There's 1000 mg anagram. Um, and then chlorine has a more mouse, uh, 70.9 grams formal. Um, And so, uh, we can cancel those grams again, and I will give us 6.8 times 10 to the negative. Four moles of Korean. So again, R p is one atmosphere. These are looking for this end is 6.8 times 10 to the negative. Fourth air is that constant. And he used to 73 Calvin. So we get a B. Once we saw, uh, syrah 0.15 liters or 15 millimeters. And lastly, we have 3.83 kg of eso to. So kilogram, um, 1 kg has 10 to the third grants in it, and then the molar mass of eso to is 64 grams per mole. So cancel out programs grants here, and we end up with 59 0.8 moles. So again, one atmosphere pressure time C equals 59.8 miles. Times are times to 73. Calvin. And we saw Harvey. We get 13 40 leaders.


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