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Une dlanrm bulor Snou dharned capacilor wiih nilormEaig Hn ue Ihernane hahEn InrDial Ihe othur plale AudilionaIlypanecle PEg: Use Ihis informalion uble belort lor p...

Question

Une dlanrm bulor Snou dharned capacilor wiih nilormEaig Hn ue Ihernane hahEn InrDial Ihe othur plale AudilionaIlypanecle PEg: Use Ihis informalion uble belort lor particle neqliqible Inturacuon betyeunWhermnment Khntn puricle(hoie dhue muanilude Moyes belwyeun theplles Ilorthe Aai( point;SacfN mNE Beelaectrompllepunecle elensacetrom KEthatit ha> [USt prior to impact wh the plale) Acume Travly />OaceriDecncnopozilive piale

Une dlanrm bulor Snou dharned capacilor wiih nilormEaig Hn ue Ihernane hahEn InrDial Ihe othur plale AudilionaIlypanecle PEg: Use Ihis informalion uble belort lor particle neqliqible Inturacuon betyeun Whermnment Khntn puricle (hoie dhue muanilude Moyes belwyeun theplles Ilorthe Aai( point; SacfN mNE Beelaectrom plle punecle elensacetrom KEthatit ha> [USt prior to impact wh the plale) Acume Travly /> Oaceri Decncno pozilive piale



Answers

Fill in the missing particle in each nuclear equation.
a. _____-21785At + 42He
b. 24194Pu-24195Am + _____
c. 1911Na-1910Ne + _____
d. 7534Se + _____-7533As

For this problem on the topic of nuclear physics, We want to find the disintegration energy for three. Hypothetical decay processes firstly for uranium 2 35. In tutorial 232 plus helium three. Next uranium 2 35 into thorium 2 31 plus helium four. And lastly uranium 2 35 decaying into thorium 2 30 plus helium five. Now the disintegration for you then in 235 decaying into Torrey, um 232 mm is given by We'll call it Q three and this is equal to the Massive uranium 2 35 the mass auditorium minus the mass of helium three or multiplied by C squared. So using the relative atomic masses, we get this to be 235 point 04 39 You -232 point 0381. You minus three point zero 16 You times the energy equivalent of C squared, which is 931.5 mega electron volts atomic mass unit. This gives us the disintegration energy for this reaction, two B minus nine 0.5 mega electron balls. Next for part B. The disintegration for your 18-35 decaying in territory um to 3 1 Q four is equal to the mass of the uranium minus the mass of the thorium minus the mess Of the Helium four. All multiplied by C squared. And this is 235 0.0 439. You -231.03 63 You minus four point 00 26 You I. MC Squared, which is 931.5 mega electron balls for atomic mass unit. And so this is equal to 4.66 mega electron volts for part C. We want to consider the transportation of uranium 2 35 into thorium 2 30. And this has a Q value Were called Q5, which is the mass of the uranium minus the Mass of the auditorium to 30 minus the mass of helium five times C. Squared. And so this is equal to 235.0 439 U -200 and 30.0 331. You minus 5.01 to to you Times 931.5 mega electron volts per atomic mass unit. You so calculating, we get the disintegration energy for this D K two b minus 1.3 mega electron volts. And we can see that only the second DK process is spontaneous as it releases energy.

42.50. So we're going to look at why it is that alfa particles are emitted by large radionuclides. Um, so I mean, it's because the alpha particle has a very stable structure. And so we're going to look it on actual outfit decay that occurs, and then two hypothetical ones where we have helium nuclei that have three years five nuclear on so one or three neutrons and look at the disintegration. So, without further ado, let's call this Q three because you have helium three. This is just going to be the mass of our uranium 2 35 minus the masses of the products. So how are you 2 32 and helium three. What? This is negative. 9.5 mega electron holds. So now the next one. The decay into Thor Iam 2 31 and helium for call this Q four because he lied before massive our uranium atom. This is the same. Is it the previous bed and now the mass of the 2 31 isotope of Tori um and the massive helium before C squared. Now this is 4.66 positive 4.66 mega electron volts. And then what will call Q fire? Because they have a helium five. Um, you 2:34 a.m. and helium five this way of negative 1.3 mega electron volts. And so we can see the two that don't happen spontaneously. Uh, have negative energies, which means that they would require the addition of energy toe happen, whereas this one has a positive disintegration. Energy eso This releases energy when it occurs, which is why this is the one that will happen spontaneously.

In this particular case, we have thought Initiate guy Knittig Energy the potential energy It was final kinetic energy plus put ensure the energy initially they were located infinity. So the potential energy zero Finally, the kinetic energy is 20 m e v. Thus the potential energy is one of lawyer for By s a lot times charge for prudent is the electron charge times charge of the lead is 82 Electron charge divided by r squared now are here is given by our off pro turned us are off then equals 1.2 Phantom eater for Putin is one raced apart off 1/3 for laid It is 82. Race the part off 1/3 and that comes out to be a boy and three Pham demeanor. So this is 8.3 family go major. So from here we can find initial kinetic energy. Toby 20 m e v. Thus 1/4 by yourself is nine times 10 to the nine times total. 80 Do times giant for you That drum squared divided by 8.3 times Tend to donate e 15 meter Now converted this into MTV. We would have this came out to the in Jewell. So dividing these by 1.6 times 10 to the maybe 13 gets it in m E v. So from here Okay, I becomes 34 point do MTV.

In this problem, the only incorrect statement is the only incorrect statement Ed Organ produces or you on produces the odd the odds inhabitants inhabitants by absorbing, by absorbing gamma radiations, by absorbing gamma radiations. Therefore, according to the option option c e. D, correct and set.


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