5

The the For the equilibrium initial formation U orbot chloromethane both 3 CHA 3 and Clz Clz 690 CH;Cl and HCL, product at a IL begin turecalculate...

Question

The the For the equilibrium initial formation U orbot chloromethane both 3 CHA 3 and Clz Clz 690 CH;Cl and HCL, product at a IL begin turecalculate

the the For the equilibrium initial formation U orbot chloromethane both 3 CHA 3 and Clz Clz 690 CH;Cl and HCL, product at a IL begin ture calculate



Answers

What is the value of the equilibrium constant at $500^{\circ} \mathrm{C}$ for the formation of $\mathrm{NH}_{3}$ according to the following equation? $\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)$ An equilibrium mixture of $\mathrm{NH}_{3}(g), \mathrm{H}_{2}(g),$ and $\mathrm{N}_{2}(g)$ at $500^{\circ} \mathrm{C}$ was found to contain $1.35 \mathrm{M} \mathrm{H}_{2}, 1.15 \mathrm{M} \mathrm{N}_{2},$ and 4.12 $\times 10^{-1} M \mathrm{NH}_{3}$

So here we're asked to consider the equilibrium between nitrogen and hydrogen gas and ammonia, and we're told that at equilibrium in a temperature of 500 degrees Celsius, the concentrations of each of these species are written down here below the equation, and they want us to calculate the value of equilibrium constant at this given temperature. What that means is that since we know that these concentrations represent the reaction vessel at equilibrium, we know that we could just write the equilibrium expression, plug these values into it and calculate the equilibrium constant. So we know that Casey is going to be equal to the concentration of products over reactions. So here we're going to have the concentration of ammonia squared, divided by the concentration of nitrogen and the concentration of hydrogen hydrogen to the third. So we're really just going to be plugging our values and for this So we're going to have a 0.412 square to the numerator, and we're going to have 1.15 times 1.35 to the third in the denominator when we multiply this through, what we find is that the equilibrium constant for this expression is six times 10 to the negative, too

When we know did look kissy is equal to In e Nord so divided by 0.591 It he's in is it will do de get toward minus e in Nord but putting you use less zero point 34 world minus minus 0.76 World is equal to 1.10 World did a world here and easy will do Do look k c is equal do through multi play 1.1 Tzeitel world divided by 0.591 world is equal to 37.29 29. So Casey is equal to and the Lord 37.29 is equal to 1.95 Multiply generous to the power 37.

This problem gives us a reaction. Um, and it gives us the concentration of eight reaction of each reacted and each product at the end of the reaction. And we need to find be equilibrium constant. So these are the equal of room concentrations, and they're in multiple leader or polarity, which are the proper units. So it's critical to know the basic formula for an equilibrium constant. Its products overreact. INTs. So for this specific equation or this specific reaction, B h 20 and then you need to put it to the power of its coefficient. It's two times the next product, chlorine gas to its coefficient, divided by the re product of the reactions to their coefficients. So then, if we plug in our numbers, we get 5.8. I'm sensing a to squared times 5.8 times tend to native two squared over 3.8 times 10 to the negative floor times 1.2 times 10 tonight. Give three to the fourth, and then we get one point for time sent to the fourth as our final answer or times 10 to the test

Hello everyone. So in this question we have to protect the equilibrium constant for the question. So the equation are as follows. So yeah, solid when upon to B guests. Yes. Let's see. Yes. Yes that is one. So okay one is giving is 0.334 Ah Treaty. Yes. Yes. Big as his plus two seal. I'm dictating so that it should be clear to you all to see that is to not see it. It was it is only see which is gaseous and to it's okay to is two point 35 No, we'll have to write the expression of equilibrium constant for the above this equation as shown. Yeah. So kevin equals two. Be on about two. See and it has not given a nd who will not write that for for decades to well let it as B. C two upon D three. All right. So the chemical reaction to which equilibrium consent to be calculated as Sean Hair to a s use it. We will to treaty. Yes. Yes. So now we'll have to multiply the equation one with the coefficient of two to have to A. S. All right we'll have to multiply the equation one with the coefficient of two to have two years on the reaction side. So we'll get to a. S. Yeah me. D. As to see G. Three. So we'll have to now write the equilibrium constant for the obtained obtained reaction three. As soon below who given it was to be see two. So okay when it was too finocchio and was zero point you're going to zero 334 power to equals two. You're on 0.1 into 10 days of our minus three. So now on reversing the equation too to have treaty on the website. Universal equation to to have three D. On the product side. So be yes yes. Were saying no this is the reverse one. Yes. Yes. To Edie. It should be very it is very easy to understand. This should be understandable. Yeah. So the expression for the equilibrium concerned for this direction will be like this. Do you do? It was to D. Three upon B. So you do. He goes to one of on B. See upon day three. So which comes out to be one upon 2.35 which is equal to approximately 0.4 to five. So now we'll have to add the two equations three and four to get the required a question as soon. Yeah. So to a B plus to see B plus to see treaty. After reading this will get us solid three D. G. All right. So now we have to create the equilibrium constant for the result. And the questioners short hair. So it will be in constant for the result. And equation will be like kate was too date D to the power three, as we can see here. So now the equilibrium constant case related to K one and K two. So cake was too Cuban into kato. So we'll get 1.1 into, tended to power minus three into zero point 4 to 5. After solving this will get your point who, sorry, force of 4.7 to 10 days of 40. So therefore the caribbean constant for the required reaction will be this and this is your answer. Thank you.


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