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Question compielionQUESTION 7Which of the following statements true about floating objects? The denser the object Is, the smaller the submerged volume of the floati...

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Question compielionQUESTION 7Which of the following statements true about floating objects? The denser the object Is, the smaller the submerged volume of the floating object Is The denser the fluid the larger the submerged volume of the floating object is The denser the fluid is, the smaller the submerged volume of the floating object is Solid density does not affect the submerged volume of the floating objectQUESTION 8 Which of the following statement IS true about Pascals principle? The larger

Question compielion QUESTION 7 Which of the following statements true about floating objects? The denser the object Is, the smaller the submerged volume of the floating object Is The denser the fluid the larger the submerged volume of the floating object is The denser the fluid is, the smaller the submerged volume of the floating object is Solid density does not affect the submerged volume of the floating object QUESTION 8 Which of the following statement IS true about Pascals principle? The larger A2 Is, the larger F1 is required The larger A1 is, the larger FZ Is produced fluid Is transmitted differently to every point within the fluid An external pressure applied to an enclosed Small external force Is requlred to left up car



Answers

(a) Which has the larger buoyant force acting on it when immersed in water, $1.0 \mathrm{kg}$ of lead or $1.0 \mathrm{kg}$ of aluminum? Explain. (b) Which has the larger buoyant force acting on it, $1.0 \mathrm{kg}$ of steel that is sinking to the bottom of a lake or $1.0 \mathrm{kg}$ of wood with a density of $500 \mathrm{kg} / \mathrm{m}^{3}$ that is floating on the lake? Explain. (c) Once you have answered the qualitative questions, find the quantitative answers to parts (a) and (b).

Okay, So which of the following statements is full? Her? A gases are Charlotte's danced in liquid. We know that. Yes, it is if we look at a container and have great gas molecules there for more parts than those of liquid. So we know based on this because we Well, because our gas mom chose our farm, we're apart then liquid molecules, then our gas molecules are Paulison. So this statement is true. So for part B, we're at gases are far more compressible with liquid. What is true, right, cause we know that gases take the shape of are basically whenever you have a container, it fills back straight part. See, the could look good. Water and liquid carbon carbon catch across. Do not mix leaders for their papers. Well, we know that one, um two liquids vaporised. Will they go into their cafes paces and we have to separate Gas is right. And we know that gases move animal E. So of course they're gonna make a statement is actually full. We're not We're not saying that if we have two gases, then, um what is it with liquid water would be separated. It's gas molecules from uh, carbon tempter quote cord. We know that at some point like this, if we said this the same molecules were carbon touch required. Then we know that it's gonna move over here at some quite, and it's gonna mix with our water. That's a minute fall. And then for party divulging occupied by a gas is determined by the volume of it. Spectator this issue because, um, gases fill its containers. So it's determined by the volume of of its computer.

So here we have the, uh, movement on a plane with friction. We can say that this plane can be horizontal. It can be on an incline regardless. Ah, we have represented with three statements we have acceleration is a function of applied force only. And in the case with the incline, we can actually just have gravitational force and the force normal. Here we can say that the force of friction is not enough to keep it stationary. And so here, in the absence of an applied force, we can potentially have Ah, the mass traveling down the incline due to the gravitational force, not an applied for us. So we can eliminate a statement one and we can say that more force is needed to accelerate a stationary object. Uh then an identical moving object. Now, this is true with force of friction. We know that the force of friction will be equal to the coefficient of friction multiplied by the normal force. No, In the case of the horizontal plane, we have the coefficient of friction times, the gravitational force and in the case of the incline, we have the coefficient of friction times, MGI and this would be signed brother co sign of data. And so in this case, we can say that regardless, the coefficient of static friction is always greater than the coefficient of kinetic friction. Which means that here for a stationary object MAWR forces needed to overcome friction, given that the maximum static frictional force is always greater than the kinetic frictional force. And so we can say that statement to is correct. Statement three. Now we have. Then the force of friction is independent of the mass. And as you can see here, it is not independent of the massive, directly proportional to the mass. And so statement three is false. And so we can say that the answer would be option B, where only statement to is correct. That is the end of the solution. Thank you for watching

So we need the for us f b as a function of the depth at which the bubble is underwater, which I call each its initial volume of the night. The initial pressure, which is uninsured pressure, peanut and the density of the water. Well, first, we just do the definition of buoyant force, which is the density of the water in this case, times William. Now we know this volume is going to change and the volume of the air inside the blues gonna change so we can use the ideal Gasol PV equals and R T, which we know. And our tea was gonna remain constant. So you can see that PV equals p zero the zero and so we can solve for V to be p zero V zero over the pressure of the blinds. At now, we know the pressure that the blood is that could be getting my decree Asian P zero plus the density times gravitational acceleration, times H. So the void becomes p zero V zero over p zero plus rogue each. So the buoyant force putting this in just becomes p zero v zero times row. The density divided by P zero plus Roe G. H. So that's part A for part B. That s what happens as the depth increases and you see the each is on the denominator here, and it's not showing up anywhere else. So that means that the buoyant force increases. Sorry, it decreases as each increases. Finally, for part C, it asked, What is the death when the buoyant force is 1/2 of the buoyant force of the surface? So at the surface, which is where each equals zero, we know that FB Trickle FB zero is equal to p zero, the zero row divided by P zero, which is equals v Zira Row, Which makes sense because the row the density is not going to change. And we just have that the volume is the initial volume. So we said if be equal to 1/2 V zero row, the equals p zero v zero row designed by P zero plus Brody h and we're solving for each year. So we multiply the denominators of the other side. So 1/2 the zero row times p zero plus row G H is equal to p zero v zero times row, expanding out the left hand side, We have 1/2 p zero v zero row plus 1/2 the zero row squared G h equals P zero V zero row. Now we can it's attract his first term video this side. And so we get 1/2 the zero grow squared. G H is equal to 1/2 p zero v zero row. We can cancel terms and cancel with 1/2. Cancel out the V zero and we can cancel out one row on the left side and the other So we get that road. G h just equals the initial pressure we saw for H and we get P zero over row G. No, we can put in the values that we know. City atmospheric pressure at the surface is gonna be 1.13 times 10 to the five pascal's. The density of salt water is one 1025 kilograms per meter. Cubed touch 1025 and G is 9.81 meters per second squared and this comes out to be 10.1 meters. This is the depth at which the buoyant force is half of what it was at the surface

Okay, So what is given to us here is Okay. So what? What is given to us here is behalf. A container. Andi, it's filled. Let's say water You given the density off Votto, which is equal to presented me to Cuba. 1 g per centimeter Cube on. Do we have off Wooden block? Okay, this is P A. That is about water. And this is re be volume that is below water. Okay, so this total height is equal to 30 centimeter on Etch A, which is this high basically is equal to 13.5. Sending me toe What we have to compute is density off food. Let's call it does 00 Okay, so to solve this, what we should know is our committee's principal. Which which say is that Emmel is moss off the liquid. Mobbed up, off and e is moss off the object above water. Okay, we know density is equal to moss Overvalue Andi. In this case, volume will be equal toe a video monthly plied by the height. This is the hydrate off. It's like a cylinder so area into high. It will give me the volume. So volume off the displeased de quid is equal to volume off body under water. Right, So we n is equal toe Phoebe. Okay, so I know this. What will I do is I will write the formula, which is m l is equal toe m A. In this case, I know the density V l is equal to We eat, right? No, this movie e into HP, which is equal to e into Etch a Right. So this is the volume now through l E H minus. H a is equal toe row A e hb right. This will get canceled, wrote a will be equal to rule l h minus. H A over ECI right now we can calculate. Drew l is one. Graham presented me to a cube. Etch is 30. Oh, sorry. Okay, One thing is not correct. So this will be equal toe row a will be equal toe etch e divided by. Okay, So density of water is 1 g per sending me toe cube. Total height is 30 minus 13.5 centimeter. Divided by 13.5 centimeter. This forget canceled. I will get 1.2 g per centimeter cube. Okay. Moving on to the next part. We already know the formula right now. It just wants us to change the object. Oh, sorry. So now, instead of water, we have a liquid. So we need to know the density off that liquid. Okay, so we'll use the same equation as this one. So now liquid will be equal to do You go this a in tow h a divided by H minus. H a. Okay, so this will be 1.2 g percent in me to queue. Etch A would be 18.9 centimeters. Okay. Divided by 30 minus 18.9 centimeters. Okay, After solving it, you get 2.81 grams. Four centimeter cube. Last part is why are we not, uh, considering the volume and moss off the cylinder? Because a video refuse as a factor. Um, both sides time gets canceled. A video means value multiplied by what is on two fight. Okay, so that's why this is not


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