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Draw all possible products of the chlorination of ( $S$ )-2-bromo-1,1-dimethylcyclobutane. Specify whether they are chiral or achiral, whether they are formed in eq...

Question

Draw all possible products of the chlorination of ( $S$ )-2-bromo-1,1-dimethylcyclobutane. Specify whether they are chiral or achiral, whether they are formed in equal or unequal amounts, and which are optically active when formed.

Draw all possible products of the chlorination of ( $S$ )-2-bromo-1,1-dimethylcyclobutane. Specify whether they are chiral or achiral, whether they are formed in equal or unequal amounts, and which are optically active when formed.



Answers

Draw the structures of all the geometric isomers of [Ru(H2O)2 (NH3)2Cl2]+. Draw the mirror images of any that are chiral.

This is the answer to Chapter 26. Problem number 25 from the Smith Organic Chemistry textbook. This problem asks us to draw the products, including stereo I summers formed in each reaction. Um, okay. And so these are basically all, um, the addition of a car bean ah, to an al Keen. And so, um, for a our product is going to look like this s so the additional be right here. Um, and we can just draw this, uh, single stereo I summer because this molecule is a symmetric and so well, and because of the two methyl groups, um, so you'll see what I mean when we, uh when we do part B. But basically, the fact that there are these two method groups here, um, means that even if we were to draw this, you know, with stereo chemistry reversed at at these two carbons where we added the car bean, um, we can just rotate the molecule, you know, 180 degrees ah, vertically. And it would it would be the same molecule. So it suffices to draw just this single stereo. I summer here for a for B. We are gonna have to draw to stereo. I summers so be ah is going to look like this. So we've added the carbon there, and we have our two. Hydrogen is here. Um, And so, uh, that carbon can add such that it assists to this metal group or the anti mur would be, ah, the carbon. Adding such that it is trance to that metal group. So, um, we can draw this part the same way on then just draw the metal group with opposite stereo chemistry there. Okay, so there we go. There's be, um, for sea again. We're gonna get ah, pair of nan teamers so we can have our method group here. Ah, in which case, um, this molecule Adlai this so hydrogen there. Um and we can get the opposite of that as well. So metal group Ah, and hydrogen on dash is here. And the carbon that has added I would then be on the wedge. Okay, um, for port de, um, So the start of chemistry, that metal group is set for party. Um and so what will change eyes just whether the carbon here adds cysts or trans to that metal group. So the stare a chemistry set. We can get Cece addition, Which would look like that. Um And so our Hodgins here on these carbons will be dashed, or we can get the opposite of that. So again, uh, stare. A chemistry of this position is set, so that's not going to change. Uh, but what could change? That is the east side that that carbon comes from. Okay, s. So there is a party. Um, Part E. Again, we'll get a pair of nan humors. Um, this is probably the easiest way to draw this. I'm actually gonna move this down a little bit, okay? Now, So there is the one. Ah, and then the other would look like this. Um, yes. So the way that the book encourages us to draw this would be to flip everything. So this is flipped. And then we were just draw, uh, the same stereo chemistry's, but because it's flipped. Obviously, it's the opposite. Stereo chemistry's. That makes sense. Okay. Redraw that. Okay, so there we go. There is e on. And then for f again, we're dealing with, um ah, product. That's going to be symmetrical. Ah, And so once again, we can just draw a single product here. Because even if we we were thio rotate ah, and flitted about it, would it would still just be this sterile chemistry. Okay, so there we go. There's part F. Um Yeah, so e and f on this page. Ah, and then Ah, a through D here on first page. Ah, and that is the answer to Chapter 26. Problem number 25.

This is the answer to Chapter 23. Problem number 53 from the Smith Organic Chemistry textbook. This problem asks us to draw the products formed, including stereo. I summers in each reaction, okay. And so, in a way, we have a key tones, so we're gonna de protein eight. Um, the Alfa Carbon of the key tone. Ah. And in this case, um, the, uh, alcohol chloride can then add from either side. And so we're going to form a mixture of an anti murders here. So we should get an an equal mixture, um, of each of these to an anti Merce. Okay, um, part B eyes kind of a trick. Question s So there's a stereo chemistry in the alcohol hale I that we're using. Um, but, uh, doing this reaction does not induce a new stereo center. And so, um, we're only going to get a single in anti murder here. We're not gonna get a mixture, which I guess might be what you would expect at first. Look. And so, um, what we're actually going to get Is this okay on dhe? That's it. Um, no other Nancy murders. I said Ah. And that the case is the same for part C. Here. We're not inducing a new stereo center. Um, we're actually doing a reaction. Um, you know, far away from the existing serious center. Ah, and we're not inducing a new one. And so, um, there's not gonna be any stereo chemistry to account for here other than maintaining the stereo chemistry that's present in this starting molecule. Okay, s o so a is a mixture of an anti MERS. Ah, and B and C are not. And they're kind of almost like trick questions because there's either Cairo ality in the alcohol Allied and B or Cairo ality and starting material would see. But it's important to not, um, sort of fall for that. Ah, and to remember that since we're not inducing a new stereo center, um, or doing a reaction on really an existing stereo center, um, that nothing's going to change their, um And we're going to get back, you know, sterile chemistry that reflects the stereo chemistry of our starting materials. Ah, and that is the answer to Chapter 23. Problem number 53

Here's someone who could send human and you have to decide whether the monocle is a killer, our killer. And after that you could draw the middle image off each month. So here, for this you have to understand that in the molecule, if any carbon which is satisfied by different groups, all the four will insist us. It is very different groups. Then it is having is symmetric center on and our little center and the whole money you wouldn't be here. Otherwise it is a killer. The soul in the first Molly in June, in the first molecule to me tackle some present and that is why it should be a killer. Here. All the four balances are satisfied by different coasts. It is having this killer center, and that is why the whole morning commute is secure. Here may know symmetries present said should be Deacon. And here again, this carbon is present, which is satisfied by all four groups, different groups. That is my nature. After that, he had to make the middle image off each Just You have to imagine that some Miller is present in front of the molecule on by that how the media made me pee. So here, one siege trickle must be here. And this should have one seed Stryker. And here this year should be able to plane and disc looting. Must be. Yeah, In the 2nd 1 Lagoon, you have drug and imagine the media image. So this is non superimpose subliminal image. So here one seeds must be And this side should have glowing the stinking the media is so this should this should be hiding. I'm with the plane. Here it is symmetry. So no roaming. You're making one. C h t. This sake this is And here again it is Get an essential So one girl when he's here. One see? It's true. Ch Tigger must leave. I don't need it. And one must you hear. And after that, when you tell me ever took clean human hydrogen. You too to this community image off the decomp

Six, then growth. That's like you doing this for carpets. The true criminals that in there one day through or tools there's only one way to potentially group to the site of mutiny. This is a silent routine. The company is a cow. It has a plan Have seemed to you running for those permanence. Two missiles convey attention the same carbon or two different currents. There's on the one radio it is two missiles drew this 11 damn is a sign of you. Dean reaches a crown presently in the seeming to you through those curtains. Two missiles conducted. Station Commons. Nestor, Charlie, you can get the bitch through. This is fresh. And this one to says, that means excited. You came. It's big Carl. There's a bullet in the senator earned for Let me go. If those miles to his rules convert a dish, you know you drills fresh and this compound is a Cairo. There's a little plan of symmetry. It's also a meal that will convince another ice in here. Welcome. Then Tim here, right building a mirror image. It's in. Our friends want to the missile cycle of beauty, but sentence her opposite configurations in front of their candidates to miss rules to comments on the opposite science. By the miracle we couldn't do it in there, says Special. And this morning is a Cairo. If there's two planes have seemed to you running this ray, what do the Red Cross? The marshal? We're going through your rooms in the trance fish. This one favor train's damaged cycle do thing. And this morning, Gil is a steal a Kyle. It has a plan of symmetry, but I mean through those curtains.


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