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6.36 Calculate AH? for each reaction.HO: CHaCH3 HzOb. CH;OH HBr CH;Br HzO...

Question

6.36 Calculate AH? for each reaction.HO: CHaCH3 HzOb. CH;OH HBr CH;Br HzO

6.36 Calculate AH? for each reaction. HO: CHa CH3 HzO b. CH;OH HBr CH;Br HzO



Answers

Calculate $\Delta{H}^\circ$ for each reaction.
a. CH$_3$CH$_3$ + Br$_2 \longrightarrow$ CH$_3$CH$_2$Br + HBr
b. HO$\cdot$ + CH$_4 \longrightarrow \cdot$CH$_3$ + H$_2$O
c. CH$_3$OH + HBr $\longrightarrow$ CH$_3$Br + H$_2$O
d. Br$\cdot$ + CH$_4 \longrightarrow$ H$\cdot$ + CH$_3$Br

Okay. Where some of the products of the following reaction with three metal two, cyclo hexane noon. Do you have three methods to cycle accident? The key to it on carbon too. And I'm sorry. There should be. Yes. So to the key in his own carbon to relatively cartoon and Bethel on carbon three and the first draft of the graveyard region Bethel magnesium. Very bad. So it's going to attack the carbon carbon and convert the key to it. It's an alcohol with the help of hcl plus should be we're reacting with access Syrian cyanide and hcl. This is something that is going to attack the carbon or carbon and hcl is going to be a cox. That ion is going to coordinate Hcl give us an alcohol just the same. It's like that And past 30 Florida. Percy reacting with hard guests and a palladium catalyst. So this is strong enough to reduce the key tune too arcane and also get rid of the arcane as well. You're still the bath right here. These are hot regions and hydrogen is here as well. Every day we're reacting with HPR. So this is simple Al Qaeda action. It's just gonna interact with your kids. And we'll have more comic off edition because we have a tertiary carpet cat on forget that for you have a Gilman region. We have two equivalents of ethel, the copy copy with you and hydrated my own. So it's not strong enough to attack and the carbon carbon, it's an attack at the beta carbon. So here's the metal and here is the addition of one fl group. Even though there's two in the reactions only adds born stress. We have Apple file, I believe this is similar to the Okay, so it's going to attack the beta carbon, just similar to the Goldman Regent. So here's the method. We still have a keystone and we're going to add this group about the addition of hydrogen. That's it

This question covers predicting the product of and I have a reaction between methyl bromide and each of the following equal files in a substitution reaction. We're gonna go ahead and just go down the line here. Um after the problems inside the book of the chapter, we should be relatively straightforward. Um So in this reaction where you're going to see that we're going to have our arrow pushing. Looks something like this and we're going to form It's a methanol great one here. Look plus Yeah minus. Yeah. In our second example we're going to see similar arrow pushing. We're going to form this mess. Olympia. Yeah. Yeah. Mhm. Mhm. And remind this next example. We're going to have some well impairs that again, will attack the carpet over here and this will form Okay, file compound here. Plus our romy bromide ion. Similar reaction here. Mhm. Mhm Mhm. He would probably see actually, yeah. Have an exodus. Mhm Plus HPR Yeah. Mhm. Yeah, like this. And we'll definitely see that in our next example that we are forming. How do I get sorry? Yeah. Not for 100 brake acid. You're forming a file neutral style with the bromide ion. Yes. In our next example again we're going to see Yeah. A similar reaction that looks like this and we're going to form a knife. Di ethyl ether. Yeah. Mhm. And in this the last example we're going to see something like this. We know that hydrochloric acid is Yeah. Yeah. Very acidic. And that means our basic So we're going to expect a quantity very mean. Yeah, bromide salt. Yeah. As our contrary substituted. But this second the secondary amine that's been doubly protected, forming assault. This. Mhm.

This question covers substitution reactions of alcohol leads. We're gonna go ahead and start off with the reaction between ethyl bromide and methanol. In this case our which identify our substitute mint are leaving group and our nuclear and nuclear file and in this case our leaving group is the romaine. Our nuclear file is the oxygen. Um and our substitution is of course the fo from my So the way this reaction would happen. Okay there would be a yeah mhm loss of a leaving group here and an attack of this. Um Yeah at all. My lady by the methanol here and this will lead us to produce a molecule that would look like this either plus okay, hydrogen hydrochloric acid as a side product. The next example is their reaction between reminded and Azide ion as that ions are very strong nuclear files. So this would go undergoing snt reaction. And again we would expect the movement of electrons to look something like this. And we would end up with um come on like you're Yeah. Such as this. Mhm Yeah. The next reaction is one between this try metal immune and that will provide in this case we would have again we have our ethnic room might uh substitute wint. Yeah. And we can go ahead and draw arrow pushing here for our substitution reaction. Okay. Something like this where we have Yeah. Yes, tertiary. Here we have this ammonia complex that was for and this would form a salt with our from my dad. The final reaction is and I felt very similar sort of process here. This is very similar to the either that we formed earlier except this time we are having a so fitted adam in the middle instead of the yeah, oxygen. And this would be the product of that reaction.

Okay. This problem is asking us to write down the directions that would occur after these Lewis acids, and those bases react with each other. So first off, what is a Lewis acid? And what is a Lewis base? A. Lewis acid is an electron, except ER, and the Lewis base is an electron donator. Okay, so if we ever get those two confused, I would recommend looking to Brown said Lowry Acids and Bronston Lowry bases. Because when it comes to Bronson blurry acids such as HCL, this is going to be a Proton. Notice that I said Proton Proton donator right is donating its hydrogen. It's proton, and then a brown, said Lowry Base, such as I'll just say ch 30 minus. That is a Bronson lower base because it accepts that proton. Okay, so again we have the proton donator and the proton, except her versus in the Lewis acids and Lewis bases. We're not talking about protons any longer. We're talking about electrons. So again, proton donator, meaning that I have the brown said acid, and then Proton except, er me that I have the broad instead base versus the Louis assets and Lewis bases on my left side of screen. We have the electron donator meaning that is going to be the bluest base and the Lewis acid, which is the electron, except er Okay, so basically, it's the opposite one on one side of our bases and acids. We have the donating and we have the accepting. Okay, It's just going to be a matter of what's gonna be the proton and what's gonna be the electron donator or accept her. Okay, so that's the way I think about it. I just think about in terms of, um, I know that prostate, Larry acids and bases are gonna be in terms of Proton, and I just think about it in terms of the opposites for my loose as ism loose basis. It's whatever we want Teoh consider in terms of how we remember this. But basically, if I have a set of electrons, that's gonna be my Lewis base, because it's going to donate those electrons to my Lewis acid, which is the electron, except er okay, so again, this is my Lewis base because it has that sites of electron density, right? The oxygen has a lot of electrons around. It has in fact, two lone pairs on it. So that means that it's going to be able to do in it those electrons onto my Lewis acid, which is my bro. Me. Okay, so it's gonna go ahead and move those electrons onto my bro me like that. So this is going to be direction that occurs. I have my c h three oh, connected to my hydrogen. And then I also have that connection to my B F three. Okay, so now we have to determine the positive and negative charges. So because I want at least in row to every electron toe, have a full octet, I need to make sure that everything has a full octet, meaning that is going to either have positive or negative charges, depending on how many bonds has. So for this oxygen, for example, I added a bond to it, okay? And I need to make sure that it has that full octet. So if I have that set of lone pairs on that I have these 246 and then the connection to the carbon is eight. Okay? I can't have that extra set of lone pairs that I previously had because of a head that that I would have technically 10 lone pairs or 10 bonds or 10 electrons, which I can't have. Okay, so I know that I had to get rid of that settle in pairs. And that means that I'm gonna only have those five connections to it. I'm gonna have the connection to my carbon. These two connections, at least in terms of electrons, these connections and that connection. Right? So that is five compared to the number of Valence, electron and oxygen, which is six. So that means that I lost in the left from that time to have a positive charge on the oxygen. And then because roaming has three vans, electrons, If I'm adding a bond to it, that means it is gaining electrons. That means it's gonna have a negative charge in it. Okay, so that is the reaction that would occur. Okay, let's move on to this one. So here I have my ch three CEO direction with a l. C. L three. So, again, this is a wholesale three is kind of similar to be a three, and that's roaming and aluminum are in the same group in the periodic table right there, both in group three and then this one stage through CEO. It's not the same as my ch 30 h. But we do have that site of increased electron density because chlorine has that settle in Paris is going to be able to donate those electrons onto my lewis acid. So I'm gonna move those electrons onto my aluminum, meaning that this is going to be direction that occurs. I'm gonna have my ch three chlorine, and then that is that chlorine is gonna connected to my a l c l free. Okay. And we have to consider are positive integer charges. So if I moved um, sorry. If I gained a bond on the chlorine, that means that I'm gonna have that pause it charge on my corn. And I gained a bond on my three valence electron aluminum, meaning that I have a negative charge because now I have four. Okay, so next up is my ch 30 ch three. And then my BF three. So this is gonna be my dimethyl ether can. That's gonna record my BF three. So again, we have to locate the source of increased electron density and that is the site that has the settlement pairs. So my auction, in fact, has two sets of lone pairs, and that means it's gonna be able to donate my electrons onto my Lewis acid. So get Lewis Base and Lewis acid. So I'm gonna have to move those electrons onto my BF three main that the eventual reaction that is going to occur and have my ch three connected to my Oxford and then connected to the extra I'm gonna have my ch three. But from before and then my new bond, which is my B F three. Okay, so again, we have the positive charge on my oxygen because I gained a bond that I lost an electron. And then the F three is going to be gaining an electron because usually I would have three advance locked arms on my bro, meaning, but because I'm gaining a set of electrons, that means I'm gonna have my neck of charge. OK, so that is the reaction that is going to occur for each of them


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