4

Ethanol burns in air or oxygen according to the equation$$mathrm{C}_{2} mathrm{H}_{5} mathrm{OH}(l)+3 mathrm{O}_{2}(g) longrightarrow 2 mathrm{CO}_{2}(g)+3 mathrm{H...

Question

Ethanol burns in air or oxygen according to the equation$$mathrm{C}_{2} mathrm{H}_{5} mathrm{OH}(l)+3 mathrm{O}_{2}(g) longrightarrow 2 mathrm{CO}_{2}(g)+3 mathrm{H}_{2} mathrm{O}(g)$$Predict the sign of $Delta S^{circ}$ for this reaction.

Ethanol burns in air or oxygen according to the equation $$ mathrm{C}_{2} mathrm{H}_{5} mathrm{OH}(l)+3 mathrm{O}_{2}(g) longrightarrow 2 mathrm{CO}_{2}(g)+3 mathrm{H}_{2} mathrm{O}(g) $$ Predict the sign of $Delta S^{circ}$ for this reaction.



Answers

The combustion of liquid ethanol (C2H5OH) produces carbon dioxide and water. After 4.62 mL of ethanol (density = 0.789 g>mL) burns in the presence of 15.55 g of oxygen gas, 3.72 mL of water (density = 1.00 g>mL) is collected. Determine the limiting reactant, theoretical yield of H2O, and percent yield for the reaction. (Hint: Write a balanced equation for the combustion of ethanol.)

Let's turn first start by writing the reaction for the combustion of ethanol. See to each rebel churches eso plus three oxygen or yield to go to three h 20 We're told that we're starting with 4.62 millimeters of the ethanol and 15.55 grams of oxygen. We're going Teoh. Determine the limiting reactant, the massive water, the theoretical you'll the water and the present killed. Uh, let's first convert both of these two moles of water to determine the limiting reactant 0.79 grams per milliliters. Air density Convert Moles Molar Mass. 46.7 grams. One more rest of Calitri And this would yield 0.237 Moles of water based on the ethanol based on oxygen. Three moles of 02 Three moles of each tool. This would be equal 2.486 least amount produced is 0.237 moles, and it's based on ethanol. There for limiting reactant is ethanol C two, h five a week, the theoretical yield for H 20 based on our limiting our living reactant. So it's 1237 moles times one more molar mass of 18 grams. This would work out to 4.27 grams of H 20 That's what theoretical yield and therefore percent yield would be the actual amounts of water produced, which is 3.72 grams. Given in the question over the 4.27 grams, which is at theoretical yields, we just calculated times 100% reports to write about seven times 100 gives me a percent yield of 87.1%.

Hello Today we'll be talking about Chapter 15 Question 26 which asks us to consider the thermo chemical equation for the combustion of ethanol. So I've written out the combustion equation here. It's unbalanced, but I'd like to make a couple of points about it before we start. Whenever we write a combustion reaction, we always have our chemical being burned. Here. This is F inal C two h 50 H. Then we have, oh to gas and the products are always go to gas and liquid water. And so this is basically converting all of the seas to go to all of the O's toe water. And then the H is also become parts of water with the leftover oxygen. Now, to balance this equation, we first need to figure out how many of each element we have on the left and right side. So that's right. See? Oh, and H. Actually, it's ch No, C, h and O. And so on the left side we have to seize six h is and three O's while on the right side we have one c ah, we have to h is and we have three O's. So even though the oxygen's air already balanced. I like to start here and balance the carbons first, So the only way to change the carbons on the right side of the reaction is through CO two. So I usually make the coefficient before go to whatever number I need to match the number of carbons on the left side. So let's make that two. That brings our number of carbons up to two up to two, and it brings our number of oxygen's as well, up from three. And so now we have 45 oxygen's on the right side. We haven't changed the number of hydrogen sze. We have it all. Next I like to balance the hydrogen sze again. We have six on the left, which means we need to add more on the right. Since the number on the left is an even number, There's some coefficient we can have for oxygen or for water, which gives us two hydrophones for every water molecule to balance it. In this case, to get six, I would put a coefficient of three in front of our water, so we'll put three, and now we have six oxygen's there. Six hydrogen is. Excuse me, but now our number of oxygen's has changed. And so we have four from CO two here and a further three from the water molecules for total of seven Oxygen's on the right side, while we still only have three on the left. But lastly, it's pretty easy, usually to balance oxygen because we have 02 which on Lee gives us more oxygen atoms as we put coefficients in front of it here. So in this case, we need to get to seven oxygen molecules on the left side, one of which comes from ethanol itself. Which means we need to make six Oxygen's out of some number of O two's. And so to get to that number, we would put a three would write three in front Theo, too, for a total of 246 seven Oxygen's on the left side as well. And so if we write that in now, we can see there are Equation is balanced on both sides. We have the same number of all elements on the left and right, And so the last thing we need to do well, just right in the implied one here the last thing we need to do to make this a thermo chemical equation is just right. The Delta H of combustion and Delta H of combustion was given to us in the problem and is equal to negative 1367 killer Jules per mole. So that's gonna equal negative 1367 Killer Jules, her mole. So hopefully this makes you a little bit more comfortable writing balanced chemical equations and writing thermo chemical equations, which are a chemical equation, followed by a thermodynamic description of the reaction.

We're given the equation for the combustion of diphenyl. Therefore, me off ethanol is sick to page five wage gumbo stew neither with oxygen and composing good uses. Come on. The yoke site on water. First, we need to balance these equation. We have two carbons we place it to with a confession to in front of carbon dioxide. Then we have six hide regions. Place a three here. I know we have three Oxygen's for on three. He's seven on in order to have seven going to have the three here six and 17 So this I'm very five again. Two carbons garlands by from 16 three times toe 600 years. One my six seven for just three seven oxygen. And then we need to calculate the mask off carbon dioxide that is produced in grounds when you combust. 100 grand's oh, space. Okay, eternal and carbon dioxide. Are these substances involved in the question? Therefore, when established, the more Rachel between eternal on carbon dioxide. We have one more of ethanol reacting with two moles off carbon dioxide, one more off eternal reacting. Two canoes, two moles. Oh, cargo. Are you excited because we are given grants. And the quest on the answer on the answer should be given grounds. We convert these more Rachel in tow. Master Nature, we will reply the mole off eternal by the molar mass off basin, which is two times 12. Yes. Wait a cut off a car bomb plus six times one get told me weight of hydrogen was one time 16 and you told me it. Weight off. Oxygen or carbon? The yolk site. We have one times 12 plus two time. 16. This is grams per mole. It's just crabs for mole, small scan sel. And then the answer in the, uh, numerator Good B 24 plus six. That's 30 16 46 grands. Indeed. The nominated we have two times extinct. 32. Just 12. That's 44 grams. Okay, So if 46 grams off a signal react to produce 44 grands off carbon dioxide, then when you have 100 grams off base and all what will be the master of use of carbon dioxide with sold for X and we got 44 things 100 from divided by 46 and the answer is 95 going 65 grounds


Similar Solved Questions

5 answers
CH3CHCH =CH2 CH3C "CHCH3 Which 1 and and of the {d following 1 CH3CCH2CH3 tautomers ofthe ketone IJ shown 2 below?
CH3CHCH =CH2 CH3C "CHCH3 Which 1 and and of the {d following 1 CH3CCH2CH3 tautomers ofthe ketone IJ shown 2 below?...
5 answers
HW-25: Problem 4Previous ProblemProblem ListNext Problem5 points) Find the area of the region between y xln and y = xl/S for 0 < x < 1_area1^(1/2)-1^(1/5)
HW-25: Problem 4 Previous Problem Problem List Next Problem 5 points) Find the area of the region between y xln and y = xl/S for 0 < x < 1_ area 1^(1/2)-1^(1/5)...
3 answers
#1Z: () Find the invcrse Laplace transformn 9'{6-4} (6) Using the fonnula9{ fo)a} 6) 2f06) _calculate %71 }6) 522 + 81)Ente Yout Cnsena[ symbolic function 0f Mn these Wannim 7a%z(a):Enter vour ansher 45 symbolic function o There EAatai,-12(b):
#1Z: () Find the invcrse Laplace transformn 9'{6-4} (6) Using the fonnula 9{ fo)a} 6) 2f06) _ calculate %71 }6) 522 + 81) Ente Yout Cnsena[ symbolic function 0f Mn these Wannim 7a% z(a): Enter vour ansher 45 symbolic function o There EAatai, -12(b):...
5 answers
Alight bulb has resistance of 240 ohms when operating at 120 volts. What is the current in the ligrn buibr 2.0 ADi.o A0,500.20
Alight bulb has resistance of 240 ohms when operating at 120 volts. What is the current in the ligrn buibr 2.0 A Di.o A 0,50 0.20...
5 answers
Find the exact value_ sin( g7)cos( gr)
Find the exact value_ sin( g7) cos( gr)...
5 answers
Intrinsically disordered proteins cannot serve a5structural protein such as Intermediate flamentsignaling moleculesscaffolds for multiple proteins, small molecules, and ionsregulators of activities of other moleculesQuestion 13Which of the three polypeptide sequences listed would form an amphipathic B sheet?0 TLNISFQ MQLDVSI RWTLNIS FQMQLDV SIRWLGVLSLF SGLMWFF WILGVLS LFSGLMW FFWIISGINAS VVNIQKE IDRLNEV AKNLNES LIDLQELISIGNAS VVINQKE IDLRNEV AKLNNES LILDQEL
Intrinsically disordered proteins cannot serve a5 structural protein such as Intermediate flament signaling molecules scaffolds for multiple proteins, small molecules, and ions regulators of activities of other molecules Question 13 Which of the three polypeptide sequences listed would form an amphi...
5 answers
197p Degree and order of the differential equation Vm x dx dx are respectively dy0 a.23Jtof0 b.22estion0 € 210 d 1,2
19 7p Degree and order of the differential equation Vm x dx dx are respectively dy 0 a.23 Jtof 0 b.22 estion 0 € 21 0 d 1,2...
5 answers
A full moon occurs every 29 nights. If you choose a night at random and then observe the night sky for successive nights (and there is no cloud to obscure your view) what is the probability you will see a full moon?
A full moon occurs every 29 nights. If you choose a night at random and then observe the night sky for successive nights (and there is no cloud to obscure your view) what is the probability you will see a full moon?...
5 answers
(b) Compute the variance for the profit associated with the two expansion alternatives. Round your answers whole numbers_ needed.YarMedium-Scale3225Large-Scale15200Which decision is preferred for the objective of minimizing the risk or uncertainty?Hedjum-Scale
(b) Compute the variance for the profit associated with the two expansion alternatives. Round your answers whole numbers_ needed. Yar Medium-Scale 3225 Large-Scale 15200 Which decision is preferred for the objective of minimizing the risk or uncertainty? Hedjum-Scale...
5 answers
QuationsiHow can the activation cnergy of & reaction be changed?How does the value of k vary with temperature? Explain why this happens in terms of the activation energy
Quationsi How can the activation cnergy of & reaction be changed? How does the value of k vary with temperature? Explain why this happens in terms of the activation energy...
5 answers
Colsidet the funiction f (x) We approximate f (x) by the Lagrange interpolating DCI Omal Pz (1) at thz pomts Xo 1X 1.5 ad X 1 JOuhO ofthe lh-oretical CIO of this approrimation a5 X 1.8 I9:0.004740.0810.000140.00004
Colsidet the funiction f (x) We approximate f (x) by the Lagrange interpolating DCI Omal Pz (1) at thz pomts Xo 1X 1.5 ad X 1 JOuhO ofthe lh-oretical CIO of this approrimation a5 X 1.8 I9: 0.00474 0.081 0.00014 0.00004...
1 answers
Trace or copy the graph of the given function $f$. (Assume that the axes have equal scales.) Then use the method of Example 1 to sketch the graph of $f^{\prime}$ below it.
Trace or copy the graph of the given function $f$. (Assume that the axes have equal scales.) Then use the method of Example 1 to sketch the graph of $f^{\prime}$ below it....
5 answers
You have a 1.5 m length of wire of cross-sectional area 0.35 cm? , made of some unknown alloy of metal: You measure the resistance of the wire between various points along the wire (ie , for different lengths of wire) You then plot the measured resistances in kilo-ohms (KO) against the length of the wire in centimeters (cm) You perform Iinear fit t0 this data and find the slope to be 1,002 What is the resistivity of this alloy in $ m?
You have a 1.5 m length of wire of cross-sectional area 0.35 cm? , made of some unknown alloy of metal: You measure the resistance of the wire between various points along the wire (ie , for different lengths of wire) You then plot the measured resistances in kilo-ohms (KO) against the length of th...
5 answers
Question 12 (5 points) Data sets A and B are dependent:Construct a 90% confidence interval for mean difference of the data sets:16 14 33 29 17B 14 10 11 21
Question 12 (5 points) Data sets A and B are dependent: Construct a 90% confidence interval for mean difference of the data sets: 16 14 33 29 17 B 14 10 11 21...
5 answers
AneennFEuiCAteAJJolnarhaaqncshnns remaln unanslhdpolni) Frid [t solutiol th: inlar %elcrndilt Itriilal Ecudla>MisivriciInitaal condilons (0and){O):Fha}
aneenn FEuiC AteA JJol narhaaqncshnns remaln unanslhd polni) Frid [t solutiol th: inlar %elcrn dilt Itriilal Ecudla> Misivrici Initaal condilons (0 and){O): Fha}...
5 answers
PART 5: ACID DERIVATIVE CONVERSIONS_ Fill in the provided boxes the reagent needed, or organic product obtained - 5 pointsAg(NH3)2HzOt'OCHZCH;Hz/PdKMnO4; H3Ot- HEATOHCHzCH;CHzCHzCH;
PART 5: ACID DERIVATIVE CONVERSIONS_ Fill in the provided boxes the reagent needed, or organic product obtained - 5 points Ag(NH3)2 HzOt 'OCHZCH; Hz/Pd KMnO4; H3Ot- HEAT OH CHzCH; CHzCHz CH;...
5 answers
Critical valueSourceDFSSMSF-ValuevalueMaterial176.8ErrorTotal296.3
Critical value Source DF SS MS F-Value value Material 176.8 Error Total 296.3...

-- 0.020888--