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21 Compound has 3 molecular weight of 108, while the molecular weight of NaOH is 40. were uscd, how many grams solid NaOH woul be necessary tO convert all of it int...

Question

21 Compound has 3 molecular weight of 108, while the molecular weight of NaOH is 40. were uscd, how many grams solid NaOH woul be necessary tO convert all of it into a) Ifa 5,4 sample without having excess NaOH? Show your calculations: If In the question abovcA AM solutton NaOH were used instead of solid NaOH,how many milliliters of this 4M solution would be required? Show your cakculations;Assumt reagents and reaction novy Many Brams 0tMJve malecuiai weights 120 and 30,respectvety: vould consti

21 Compound has 3 molecular weight of 108, while the molecular weight of NaOH is 40. were uscd, how many grams solid NaOH woul be necessary tO convert all of it into a) Ifa 5,4 sample without having excess NaOH? Show your calculations: If In the question abovcA AM solutton NaOH were used instead of solid NaOH,how many milliliters of this 4M solution would be required? Show your cakculations; Assumt reagents and reaction novy Many Brams 0t MJve malecuiai weights 120 and 30,respectvety: vould constitute cquivalent? Show vour calculation: "Xare Usedin a



Answers

One mole of a mixture of $\mathrm{CO}$ and $\mathrm{CO}_{2}$ requires exactly $20 \mathrm{~g}$ of $\mathrm{NaOH}$ in solution for complete conversion of all the $\mathrm{CO}_{2}$ into $\mathrm{Na}_{2} \mathrm{CO}_{3} .$ How many grams more of $\mathrm{NaOH}$ would it require for conversion into $\mathrm{Na}_{2} \mathrm{CO}_{3}$ if the mixture (one mole) is completely oxidized to $\mathrm{CO}_{2} ?$ (a) $60 \mathrm{~g}$ (b) $80 \mathrm{~g}$ (c) $40 \mathrm{~g}$ (d) $20 \mathrm{~g}$

In this problem, we have a solution of sodium hydroxide. With the morality of 10.7, we're given the density of the solution and asked to determine the more fraction and weight percent of sodium hydroxide, and were also asked to find the mole aridity of the solution. We can start by using our morality. We know that morality is equal to our most of our soul. You divided by our kilograms of Selvin so we can give an unknown variable toe are moles of sodium hydroxide and divide by one kilogram of water. So when we solve for X, we find that we have 10.7 moles of sodium hydroxide present. We can then take our mass of water that we determined from the morality and convert it to amount of moles of water that we have present. So first we want to do a unit conversion to go from kilograms two grams and then we want to divide by the molar mass of water. From this calculation, we find that we have 55.5 moles of water President in our solution, we cannot find the mole fraction of sodium hydroxide by taking our moles of sodium hydroxide that we calculated up above and dividing by the total moles that are present in our solution. So we'll add the moles of sodium hydroxide, tour moles of water. And when we do this, we find that are more fraction of sodium hydroxide is equal 2.162 Next to determine our weight percent of sodium hydroxide, we can take our moles of sodium hydroxide and translate that to amass. And we can do this by multiplying by the molar mass of sodium hydroxide. So we have 427 0.97 grams of sodium hydroxide present in our solution. Now to determine our wheat percent, we can take this mass that we just calculated for our sodium hydroxide and divided by the total mass of our solution. So we have the mass that we just calculated over sodium hydroxide, and then we also know that we have one kilogram off water, which is equivalent to 1000 grams of water. Now we multiply by 100 since this is a percent and we find that the solution is approximately 30% sodium hydroxide by weight in order to find the mole Arat e. We need to know the amount of leaders of our solution that we have. We know that the total mass of our solution is equal to 1427.97 grams. And we know this because we just have to add our amount of grams of water tore, amount of grams of sodium hydroxide Now that we know are total mass of our solution, we can go ahead and divide by the density that we were given in the problem statement. In doing this, we translate toe a volume term and we know that in every centimeter cubed there is the equivalent of one millimeter and then we can translate to leaders by dividing by 1000 milliliters to do unit conversion. So we find that we have about 1.74 leaders of solution to find our polarity. We'll take the amount of moles of sodium hydroxide that we have present and divide by this volume that we just calculated. So this tells us that a polarity is equal to 9.9 secs, Moeller

Mm. Hello and welcome to this video solution of enumerate here we are having the equation too. In A. O. H plus CO two gives you and it was your tree plus H two big one mole of co two birth two more of any which right now there's two more of an edge which is equal to two times of 40 g. So muller muller myself in it which is 40. So there is equal to 80 g rate of any. Which Now if if if one mole of any ridge is used by. Yeah. Yeah 0.8 small mixture of Ceo plus co two been so much content. .5 more of sort rate. The rest 0.3 moles is Ceo fine. Yeah. Now if this if this 0.3 Mol ceo is oxidized. Yeah, she days too CO two right then 0.3 moles of Ceo. Yeah. So too will require .6 small of an average rate. 0.6 small N A. Which right thus we can say that 0.6 small more Amongst 0.6 Malmo Ravenna which would it require for the conversion of any two into an 8-0 3. The mixture is completely oxidized to suit rate. So 0.6 is the solution and we have the option in auction has be red. I hope this is clear to you and have a very good rest of the day. Thank you

So here we are continuing on with our solution chemistry. And what we're taking a look at here is a few like calculations. So just stepping into the physical chemistry side of things here. So the first thing we like to calculate is the moles of sodium hydroxide And to the moles of sodium hydroxide, we take the polarity multiplied by the volume to get 10 moles. And then what we can do is determine the massive nuh as we take the moles, multiply it by the mola max, So we get 400 g. And so the density of the sodium hydroxide solution is 1.33 times 1.33% meters cubed. So our weight percent is equal to the 400g, Divide that by 1, 3, 30 g of sodium hydroxide, multiplied by 100. What we get is 30.075%. And so we can round that to three significant figures to 30.1%. So that is the weight percent of sodium hydroxide.

All right, let's start with our sodium phosphate and do some calculations to figure out our joh mass. Okay, so we'll start with 26.2 grams of sodium phosphate. We'll go ahead and change grams of sodium phosphate. Two moles. And there are more ratio will change moles of our sodium phosphate, two moles of r. n. h. That ratio is 321 sodium phosphate weighs 163 0.94. Now, I can change moles of H two g of Noh. Yeah. And which was 40 grams caramel. And then finally, I can change our grams to middle leaders using our density of solution And see that I need 16 9 mm of the Nuh. But our solution There's only 12% Nuh. So I need to divide by by 12% And see that I would need to use 141 ml of my solution to provide the amount of any which I need.


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