5

Point) Let11 1 1 A = [3 3]: 3 3Describe all solutions of Ax = 0 .X=X2+X3+X4...

Question

Point) Let11 1 1 A = [3 3]: 3 3Describe all solutions of Ax = 0 .X=X2+X3+X4

point) Let 11 1 1 A = [3 3]: 3 3 Describe all solutions of Ax = 0 . X=X2 +X3 +X4



Answers

Let $$\mathbf{A}=\left[ \begin{array}{rrr}{2} & {-1} & {1} \\ {-1} & {2} & {1} \\ {1} & {1} & {2}\end{array}\right].$$
(a) Show that $\mathbf{A}$ is singular.
(b) Show that $\mathbf{A} \mathbf{x}=\left[ \begin{array}{c}{3} \\ {1} \\ {3}\end{array}\right]$ has no solutions.
(c) Show that $\mathbf{A x}=\left[ \begin{array}{c}{3} \\ {0} \\ {3}\end{array}\right]$ has infinitely many solutions.

Residents are X minus three way is equals to three, and second is two X minus nine ways equals to one. First, let's put the point zero comma one in given system off it questions we get zero minus three, multiplied by one inch equals 23 This implies zero minus three. It occurs to three. This implies minus three. Is you close to three, which is false. In second person, we often to multiplied by zero minus nine. Multiplied by one. It occurs to one. This implies zero minus nine is equals to one. This implies minus nine is equals to one, which is false. Second, putting point four comma minus one. We get in first equation Ford minus three, multiplied by minus one in a quest to three. This implies four plus three equals +23 This in place seven. It occurs to three, which is false in second person to multiplied by food minus nine Might deployed by minus one. It was too one. This in place he'd plus nine equals to one. This implies 17 is because to one which is falls moving forward. The third point we had, let's put the third point fifties nine common to we get nine minus three multiplied by two intercourse. 23 in place nine minus six is it goes to three. This implies Today it equates to three, which is true. And secondly, Christian to multiplied by nine minus nine month applied by two. It was 21 This implies you're eating minus 18 is it was 21 This in place zero is It goes to one which is falls so neither second point that is four comma minus one nor third point that is now in common. Do is a solution. Do given system? Yes, it questions.

We're going to do problem number four in this question. What they have to do, we have to just applaud the points. Okay? The points are given, that is zero comma. Zero be point is given. That is one common management. See, point is given that point is three comma ministry. The point is given that is manners One comma, one you point is given that this ministry comma three. Okay, so we have to describe all these sorts off ones which are having a element, etc. Okay, where is the real number of this form? Okay, so we will just blow the Gaff Brought the points first on the ground. So let us name the exist. This is why I exist. This is, uh, Venezuela exist. This is X X system. This is Manus X axis. The central on is zero. We will take to intercept one so you'll write her one. This is two this is three This is four. This is five same follow So negative xx is also okay. So we will write that also this is management. This is managed toe. This is ministry. This is madness for same follow. So wakes is also 1234 Same for negative. I also when this one managed to and ministry. Now let's start boarding the points question zero comma zero in sections. You don't Y zero. This is point a now point to be There is one common menace. One in Texas one anyway is medicine. So this will be another point. Let's say this is B See point is excess tree And why is ministry So this is the point where Access three and why is ministry is this one. So the point will be this one. So we'll point it is see nowadays access management And why is one so this this point d He is a ministry access ministry on what is three. So this is three. So this will be the point, which is B. Okay, So if we talk about these shirts off a common management, so all are in the form the forms are Let's see, this is that is, uh, this one that is B see on BNC only are the source of this where y is having a negative sign on access. Having this. Okay, If you look at like that, only now if you see this all cases also. Okay, Okay. It will be a negative number. Let's say it will be many. Say, then, the This will be manners off, man, I say. Okay, so it is holding this property the third. That is a common management. So what will? What we can say is we can say that all the number, all the number A, B, C, D and E will hold the set. That is a comma management. A common menace. Sorry. Okay, Now, if we join all this line, then they're going to make a straight line equation of a straight line. Okay, for a straight line. So this is the properties off these old points. I management a man necessary. Yeah. So this is the required solution off this question, That's all. Thank you very much.

We need to determine which of these points is a solution to the equation. So our 1st 1 X, Y. Y. So we plug in. So the absolute value of 1 -3 absolute value minus a negative two equals four. So we get the absolute value of negative two plus two is equal to four. Absolute value of negative two is two plus two equals four. We have four is equal to four so that's true. So one negative two is a solution. And so we try the next one, this is X and y. So we have the absolute value of negative 2 -3 minus a negative three equals four. So this becomes negative five, absolute value plus three is equal to four. So we get five plus three is equal to four, so this is eight is equal to four, so that's not true. So this is not a solution. So then we have X and y. So we have the absolute value of 1/10 minus three minus a negative 11 10th equals four, So 1 10th -3 Is the absolute value of -29/10. He plus 11/10 is equal to four. The absolute value of negative 29 10th is 29 10th plus 11 10th, So 29 plus 11 Comes out to be 40/10, 40/10 reduces to four, and so that equals four, so that works. So this is also a point that satisfies the equation.

So we got two equations. Why equals? That's minus one and then three X minus three Y equals three. So we're gonna graft these. That's the whole section. Slope is equal, the one because there's a one x. But why intercept is equal the negative one. See the blue I got If x zero, Why asked equal Negative one is negative three times negative. Well, if y equals you're the access to people. Positive one. That's enough for me to draw a graph here. The red line starts a negative one. It has a slope of positive one. So it would connect these two dots up into the right. The blue line would have, ah, why intercepted negative one an exit except of one. And so it's right on top of it. They touch an infinite number of times. There's infinitely many, infinitely many solutions, or you could just say infinite solutions.


Similar Solved Questions

5 answers
Question 2 For a two-Variate population, the observed sample covariance matrix is5 = 2Determine the sample correlation matrix R: Find R" and its spectral decomposition. Sketch the mean-centered ellipse TR-! I < c
Question 2 For a two-Variate population, the observed sample covariance matrix is 5 = 2 Determine the sample correlation matrix R: Find R" and its spectral decomposition. Sketch the mean-centered ellipse TR-! I < c...
5 answers
Bronsted-Lowry acid iscompound thal contains hydroxide and dissolves in water t0 form OH-3 cornpound lhal is prolon donora compourd (hal contains a hydrogen atomn and dissolves in waler to form a hydrogen compound lhal is J prolon acceplor
Bronsted-Lowry acid is compound thal contains hydroxide and dissolves in water t0 form OH- 3 cornpound lhal is prolon donor a compourd (hal contains a hydrogen atomn and dissolves in waler to form a hydrogen compound lhal is J prolon acceplor...
5 answers
Question One of the following molecules has bond angle of 1039_ Which one?SCl2SO2 BF3SiHaFzCO
Question One of the following molecules has bond angle of 1039_ Which one? SCl2 SO2 BF3 SiHa FzCO...
5 answers
If Emery has $1700 to invest at 6% per year compounded continously, how long will it be before he has $23002
If Emery has $1700 to invest at 6% per year compounded continously, how long will it be before he has $23002...
5 answers
A continuous random variable X that can assume values between x 1 and x = 3 has density function given by f (x) = Aa Show that the area under the curve is equal to 1. b. Find P(X < 1.6) .
A continuous random variable X that can assume values between x 1 and x = 3 has density function given by f (x) = Aa Show that the area under the curve is equal to 1. b. Find P(X < 1.6) ....
5 answers
Beginning at time t = 0, a computer receives messages continuously from either line A or line B Messages can only be received one at a time: Let P(Messages from Line A) = 3P(Messages from Line B):The length (in terms of time to process a message), X, of any messages is an independent random variable with the following PDF:For Line A messages: fx(x) =x >u otherwiseFor Line B messages: fx(x)x20 otherwise
Beginning at time t = 0, a computer receives messages continuously from either line A or line B Messages can only be received one at a time: Let P(Messages from Line A) = 3P(Messages from Line B): The length (in terms of time to process a message), X, of any messages is an independent random variabl...
5 answers
Question 12 ptsA 1.83kg object has three forces applied - toit: Asaresult; its acceleration vector is given by:-8.26 m/s25.67 m/s2If two of the three forces acting = on the object are:F =30.9N { 164NFz =-114N+7.94NFind the magnitude of the third force in N. Enter the numerical part only in the answer box
Question 1 2 pts A 1.83kg object has three forces applied - toit: Asaresult; its acceleration vector is given by: -8.26 m/s2 5.67 m/s2 If two of the three forces acting = on the object are: F =30.9N { 164N Fz =-114N +7.94N Find the magnitude of the third force in N. Enter the numerical part only i...
5 answers
{uestinu %: Calculale thd cntropy gnten A< follon ssturated iquid ~buteTeO8 "€ The vapr ptersue equation4350.2 Inpse(ra) = 68.49 74124 Int 1.050} * 10 *T'uhere is in Ka Ose Peng Robinson equation where "Ppropriate:(26 points]
{uestinu %: Calculale thd cntropy gnten A< follon s sturated iquid ~buteTe O8 "€ The vapr ptersue equation 4350.2 Inpse(ra) = 68.49 74124 Int 1.050} * 10 *T' uhere is in Ka Ose Peng Robinson equation where "Ppropriate: (26 points]...
5 answers
Solve the following systems algebraically " = 4 21' 4" Fb) Compute; if possible; the products of the following pairs 0f matrices [3|Qucstioni2 markes) Exhibit the augmented matrix o each system and give its size:T | "| " ' 'r4 7| " 'r1 'r4 4TT " r 3 3 6n 4 T1(C)r +re+ar, '201 + ire Hr; 'rg Ir;
Solve the following systems algebraically " = 4 21' 4" F b) Compute; if possible; the products of the following pairs 0f matrices [3| Qucstioni2 markes) Exhibit the augmented matrix o each system and give its size: T | "| " ' 'r4 7| " 'r1 'r4 4 TT &q...
5 answers
G(w) = 29 h(c) = x + 8(a) Find g(h(z)).g(h(x) )(b) Find h(g(z) ) .h(g(z))
g(w) = 29 h(c) = x + 8 (a) Find g(h(z)). g(h(x) ) (b) Find h(g(z) ) . h(g(z))...
1 answers
Use integration by parts to obtain the formula $$\int \sqrt{1-x^{2}} d x=\frac{1}{2} x \sqrt{1-x^{2}}+\frac{1}{2} \int \frac{1}{\sqrt{1-x^{2}}} d x$$.
Use integration by parts to obtain the formula $$\int \sqrt{1-x^{2}} d x=\frac{1}{2} x \sqrt{1-x^{2}}+\frac{1}{2} \int \frac{1}{\sqrt{1-x^{2}}} d x$$....
4 answers
Prove that the reflection of the point $(a, b)$ through the line $y=x$ is the point $(b, a)$ by verifying statements $(A)$ and $(B)$(A) The line through $(a, b)$ and $(b, a)$ is perpendicular to the line $y=x$(B) The midpoint of $(a, b)$ and $(b, a)$ lies on the line $y=x$
Prove that the reflection of the point $(a, b)$ through the line $y=x$ is the point $(b, a)$ by verifying statements $(A)$ and $(B)$ (A) The line through $(a, b)$ and $(b, a)$ is perpendicular to the line $y=x$ (B) The midpoint of $(a, b)$ and $(b, a)$ lies on the line $y=x$...
5 answers
4. How many ways can 7 flags be displayed on two flagpoles?
4. How many ways can 7 flags be displayed on two flagpoles?...
5 answers
1. Write the equilibrium expression for each reaction. (a) Nztg) ` + 0zg) 2NO (b) 2Hzg) ` + 0zg) 52H,O (c) Nzg) + 3Clzg) 5 2NCls) (d) 2Fe '(aq + 2l(aq = 2Fe ?aq + Iztaq) 2CHug) = CHstg) + Hzg)
1. Write the equilibrium expression for each reaction. (a) Nztg) ` + 0zg) 2NO (b) 2Hzg) ` + 0zg) 52H,O (c) Nzg) + 3Clzg) 5 2NCls) (d) 2Fe '(aq + 2l(aq = 2Fe ?aq + Iztaq) 2CHug) = CHstg) + Hzg)...
5 answers
0 0 0 0 1 8 = 35768
0 0 0 0 1 8 = 3576 8...

-- 0.017796--