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Wid Mas 0gndualed tyiner Water (0.9) Mass ogaduated Qyinper (Di7 Volume ofltnter iniodinder /0.8}Kaala 37.035 g 27.189 g l10.00 mLbbd Mass of graduated cylinder wat...

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Wid Mas 0gndualed tyiner Water (0.9) Mass ogaduated Qyinper (Di7 Volume ofltnter iniodinder /0.8}Kaala 37.035 g 27.189 g l10.00 mLbbd Mass of graduated cylinder water (D.9) bMass of graduated cylinder (0.7} Mass of water (a -b} (CT)Mzesured {D} and Calciated Data {qd. Volume of water in cylinder (D.8) Density of water (C 81f. Temperature (D.1O]|25C4% NaqlIscoupAlMass of graduated cylinder + water (D.LL} Mass of graduated cylinder (D.7} Volume ofwaterin Gxlinder (D B137.305 g "27.189 g 10 Dp

Wid Mas 0gndualed tyiner Water (0.9) Mass ogaduated Qyinper (Di7 Volume ofltnter iniodinder /0.8} Kaala 37.035 g 27.189 g l10.00 mL bbd Mass of graduated cylinder water (D.9) bMass of graduated cylinder (0.7} Mass of water (a -b} (CT) Mzesured {D} and Calciated Data {q d. Volume of water in cylinder (D.8) Density of water (C 81 f. Temperature (D.1O]| 25C 4% Naql IscoupAl Mass of graduated cylinder + water (D.LL} Mass of graduated cylinder (D.7} Volume ofwaterin Gxlinder (D B1 37.305 g "27.189 g 10 DpmL 4% NaCl a Volume of NaCl solution {D.8} b: Mass Of graduated cylinder + NaCl solution (D 11) CiMass 0i graduated cylinder (0.Z) d. Mass of NaCl solution (b c) (C.9) Measured (D} and Calculated Data (CH e. Density of NaCI solution {C.1OJ



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The total volume of seawater is $1.5 \times 10^{21}$ L. Assume that seawater contains 3.1 percent sodium chloride by mass and that its density is $1.03 \mathrm{g} / \mathrm{mL} .$ Calculate the total mass of sodium chloride in kilograms and in tons $(1 \text { ton }=2000 \mathrm{lb} ; 1 \mathrm{lb}=453.6 \mathrm{g})$

First, let's figure out a few masses. We'll figure out the mass of the solution but taking the difference in mass of the evaporating dish before and after adding a solution. 12.5 grams. Then we can figure out the mass of any C L after evaporation by taking the mass of the n a C l that stuck after all the water evaporated minus just the massive evaporating dish would get 1.4 grams and then we have to figure out mass percent. We'll take the mass of any CL divided by the mass of the solution times 100. We get 11.6% in a C l. The density of the solution could be determined, which will need for part B by taking the mass of the solution, which we determined to be 12.5 grams, divided by the volume of the solution which was given to us at 10 milliliters and we get 1.205 grams for middle leader. So if we start with what we know, the grams of the sodium chloride divided by the grams of the solution, we need to convert the grams of sodium chloride into mold sodium chloride and then the mass of the solution into, um, leaders of solution. And we will get more clarity. So to convert the gram sodium chloride into mall sodium chloride will use it smaller Mass. Then to convert through the mass of the solution into mill. Leaders of the solution will use the density of the solution, which is 1.205 grams per mil leader. And then we don't want middle leaves in the denominator. We want leaders in the denominator. So will on the tail end here. Convert leaders are milliliters of solution into leader solution, and we'll get 2.40 Moeller sodium chloride, then last of all, we want to convert the similarity that we just calculated 2.40 into a new mill. Arat e. When we take 10 milliliters and we dilute it to 60 milliliters, then we can use the delusion equation and we'll solve for X and X in this case will be three 0.99 Moeller sodium chloride if we don't do any rounding it all until the very end

Yeah. We have a graduated cylinder that is weighed at 66 5 grounds. Mhm. And to the cylinder was added some water. Yeah. Has a mass of 58.2 g and some sodium chloride. Because a massive 5.279 grams. What is the total mass of the cylinder? And the solution? This is equal to 66.5 g plus 58.2 g. 5.279 g. We're gonna report our answer to one decimal place. It's yeah. One decimal place. We would get. 100 30.0 g. Would be the mask of the cylinder and solution. Right. Mhm.

For the total morality of all ions and seawater, we first need to convert every concentration value in parts per 1,000,000 into morality. Parts per 1,000,000 can also be expressed as milligrams per leader of a certain Saul you we can take advantage of this fact and you that convert every parts per 1,000,000 value into moles per kilogram of solvent. The first step is converting milligrams in two grams. The second step is converting grams to moles. The last step is converting leaders of solvent into kilograms of solvent. This equates to a morality value of 0.536 moles her killer Graham her chlorine. The same process will be done for sodium using sodium Smolar mass and the morality of sodium equates to 0.457 most per kilogram. I do then herself eight and then from magnesium and then for calcium, but none for potassium and then for bicarbonate. And lastly for a broom MyDD. Now, if we add all of these individual moralities up, the total morality for all ions in the seawater equates to 1.11 rolls her kilogram of water now in part B were asked to find the osmotic pressure at 300 Kelvin's of seawater, assuming Morality and Mueller tear equal. And if we substitute our morality, the gas constant and the temperature into the equation for osmotic pressure, it yields 27.3 atmospheres.

Hi guys live. So problem. I find 134. We need to find some other mess off the guests. It's given that mess off. Empty baskets 65.347 gram and Menzel, The flask filled with water is three 27.4 gram. So then Ms O wanted these 3 27.4 minus 65.347 grand, which is due 62.1 grams. Therefore, the rolling off the plastic doing mass off water divided right, the density off watching, which is to 62.1 grams, divided by 0.997 Grandpa Milliliters in front of all the amount of class case to 62.9 millimeter Mum, the mess of the class with the unknown liquid ese 65.7 39 grand. Therefore, myself, the unknown liquid. He's 65 points 739 minus 65.347 grams, which gives us A 0.39 to Graham. The temperature of the system. Given these 99.8 dissensions only cancan wanted to give him a skin, which gives us 3 72.8 the fishing given ese 101 too. In the basket lives Dunwoody do most very Christian by dividing it with 101.3 to 5, he keeps a 0.999 Hey, Jim, no! In this condition, the unknown guest occupies the whole container. Therefore, the world of the bears should be 2 62.9 I really need you all to 62.9 in the 1st 3 And the mess off the guests. We can't believe it. He's zero point 3 92 cream and we know when a mess A grant to mass divided by a number of months. Oh, number of Morse. Is it gonna do, Nancy? Very, very Momus. No. We can use the ideal gas. A convention. It is goingto in D. Oh, baby is going to and using the secretion we company to that one of us I need to see inside. It's inside the values that we know Massive warned. That's constant use Airplanes. Hail storm. No, your son Give me your son In village, it is 72 point do added by the pressure, which is 0.999 It's a dream And the volume please. 2 62.9 to 10 in your 1st 3 leader. Let's check on the You know this, Lieutenant. Everyone will be gone. It was very pressure will be gone. So we elected Graham and Union Verse one. These gives us 45.7 Grandpa which is someone or myself down. And then? Yes.


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