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#G /C 4728 4 5 6 7 8 !Find the force On a tange of 1 /C on the $ Axis al f 3 4L Tle value of (lie Cvultl constant is 8.98755 x 10" N- m?/C2. Answer in units o...

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#G /C 4728 4 5 6 7 8 !Find the force On a tange of 1 /C on the $ Axis al f 3 4L Tle value of (lie Cvultl constant is 8.98755 x 10" N- m?/C2. Answer in units of N009 10.0 points Four point charges are placed at the four COr - nClS of a square Each siq] of the square has length L q = qq1 =-qm =Find the magnitude of the electric force O 9 due to all thrce charges 41, q3 and q4 for L = In and q = L5 #C. Tlie Coulomb constant is 8.98755 * 10" N - I?/C2 Answer in units of N_

#G /C 4728 4 5 6 7 8 ! Find the force On a tange of 1 /C on the $ Axis al f 3 4L Tle value of (lie Cvultl constant is 8.98755 x 10" N- m?/C2. Answer in units of N 009 10.0 points Four point charges are placed at the four COr - nClS of a square Each siq] of the square has length L q = q q1 =-q m = Find the magnitude of the electric force O 9 due to all thrce charges 41, q3 and q4 for L = In and q = L5 #C. Tlie Coulomb constant is 8.98755 * 10" N - I?/C2 Answer in units of N_



Answers

Force between charged particles: $F=k \frac{Q_{1} Q_{2}}{d^{2}}$ The force between two charged particles is given by the formula shown, where $F$ is the force (in joules -5 ), $Q_{1}$ and $Q_{2}$ represent the electrical charge on each particle (in coulombs - $\mathrm{C}$ ), and $d$ is the distance between them (in meters). If the particles have a like charge, the force is repulsive; if the charges are unlike, the force is attractive. (a) Write the variation equation in words. (b) Solve for $k$ and use the formula to find the electrical constant $k,$ given $F=0.36 \mathrm{J}, Q_{1}=2 \times 10^{-6} \mathrm{C}$ $Q_{2}=4 \times 10^{-6} \mathrm{C},$ and $d=0.2 \mathrm{m} .$ Express the result in scientific notation.

Hi There are three charges yep. At the vortices of Anita electoral triangle like this. The three charged particles are having the values upper one. This is plus 4.0 micro column. The lower one the left lower less 2.0 Micropal. Um And the right lower that is Plus 3.0 Micro column. Let it be A. The lower left that is represented by B. And the lower right support. This is C. Each side of this triangle is 20 centimetre. Cool. This upper charge Will be experiencing two courses of repulsion. This upper one upper charge Plus 4.0 micro colon. It will be repelled by the charge capped at B means plus 2.0 micro colon. And it will be repelled by the charge kept at sea means plus 3.0 Mike local. I'm also these two forces maybe named as F. A. B. Force experienced by the charge put at A. Due to that. Could that be? And F. A. C. Most experienced by the charge put at a. Due to that put at sea. And the angle between them will be 0°. Which will be helpful to find their vector addition. Now using columns law. F A. C will be given by a. Into you A. Into Qc. Charge put at A. And C. Respectively divided by the square of distance between them which is nothing but the side of his square In m. This will be 0.2 meter. The whole square. Now putting the values all other known values for K. This is nine in 2 10.9 into for cure a disease for micro problem or four into 10 for -6 column into QC which is three into 10 days par -6. School. I'm divided by 0.04. So finally this force comes out to be so 0.7 Newton. Similarly, F. A into Q. B. Invited by saying the side of this Equal Little Triangles 0.2 m. Or it will give it will be given by nine in 2. And as to the part nine, You took you a again four into 10 days par -6. You'll be To into 10 par -6 Divided by Square of 0.2, which will come out to be 0.0 both. And finally this force. F A B comes out to be 1.8 newton and angle between them That is 60°. Using the concept of vertically opposite angles. Well, finally, the net force acting at this charge put at the vortex A. Using triangle law of tradition, it will be given by square root of squared off FCC classes quite off. F A B plus two times of F A. C into F A B into cosine of angle between them which is 60° and cost 60° comes out to be half. Now putting all these values here Or FAC. This is 2.7. Newton Have a baby that is one pointed newton Last two times off 2.7- 1.8, Cost 60° half cancelling this half here. Finally, we get This is 7.29 less, 3.24 plus 4.86, which comes out to be equal to 15 point 39 Newton. Or finally, magnitude of this net force Comes out to be 3.9 two newton, which is the answer for the given problem here. Thank you.

Here for the solution. Used Pythagorean Forum to solve for the distance from 2 to 3 here by using the Pythagorean theorem, we get sequel 200 0.18 m square plus 0.24 m square, and from here he gets equal to 0.3 0 m. Have electrical. Two k Q one Q two by our square now sold for the force by both particles on the third. So F one and three equal to K here by substituting the values of yeah, Cuban Q to end our and sold for this we get f for one and three. We get 4.54 multiplied by 10 to depart minus five of world. Now for I have 42 and three equal to K. Harris will develop you and killed three and ask Then, from here we get it. 3.74 multiplied by 10 to the power minus five and downward and rightward. Now, after when three has X and y force so sold for each in other mm. To do this though need to solve for theta value can do this with the given length values so cheetah can t take all to 0.24 m divided by 0.18 m. And from here we get to take her to 53.13 Larry now for the wife sign 53.13 degree equal to y. Divided by 3.74 multiplied by 24 minus five. And and from here we get y equal to 2.99 multiplied by 24 minus five. And for ex costs 53.13 degree equal to X, divided by 3.74 multiplied by 10 to the power minus five. And and from here we get X equal to the 2.24 multiplied by 10 to the power minus five. And now find the some of the vertical force is the force from particle to is downward. So it is subtracted from the force upward. So we get Force one and three, minus 42 and three. So it will be 4.54 multiplied by 10 to depart, minus five and minus 2.99 Multiplied by 10 to depart minus fine. From here we get 1.55 multiplied by two and three par minus five pen. Now the vertical and horizontal forces add up at an angle to write an upward. Using Pythagorean tore, um, one can solve for the value so have finally equal to underwrote 1.55 multiplied by 10 to depart minus five and whole script plus 2.44 2.24 multiplied by 10 to depart minus five and whole square. And from here we get difficult to 2.7 to multiply by 10 20 power minus five. And yeah, now use the values there to solve for the angle of the vector. So angles, Tita. So 20 take all 251.55 multiplied by 24 minus five and divided by 2.24 multiplied by 200 part minus five. And And from here, we get to take her to minus 34.7 degrees. So this is a complete solution. Step by step with the explanation in detail. Please go through this

Hi in this given problem. In the first part of the given problem There is a charge you one which is given us 5.0 Into 10 AR -9. Coolum Then at a distance of our, whose value is given us her B centimetre or 0.30 m. We have to find electric field at the point B. So using expression for electric field E. Is equal to K into cuba artist squared. Okay, this is nine into 10 days. to the part nine Newton meters square park. Allami square multiplied by charge which is 5.0 into 10 for -9 column divided by Is tense, which is 0.30 m square cancelling this school are canceling this meter is square. Finally answer for this. Electrical failure comes out to be 500 newton for colon which is the answer for the first part of this problem. No, in the second part of the problem we are having another charge you too Having a value of 4.0 Into 10 for -10, Cooler. And that is kept at the point B. So it will experience a force of repulsion because the positive charge will push the positive charge away from it. And that force will be given us suppose it to be F2, it will be given us you two into E for Q two. This is 4.0 into and its former Anistan Electric field, we have already found it to be 500 new turn curriculum and here it was cool. Um for the charge canceling the school um by column finally get the magnitude of this force to be equal to 2.0 into 10 for -7 newton. Or we can say This is 0.2 Micro Newton and that is away from Cuban for soft repulsion. Now in the 3rd part of the problem, If we replace you too bye Q three Their Q three is having the same magnitude as that of you too. But a positive nature -4.0 into And this 1- then you'll um So discharge Q three will be attracted towards Cuban being opposite in nature and the magnitude will be equal to that we have obtained in the second part of the problem. 0.2 zero micro newton which becomes the answer where to her part of the problem. And that will be the words you want. Thank you.

Harassed ranks. Let's start our discussion on electrostatic force. Suppose we have a co ordinate system in which a point a lie that origin and at a a charge off tree in tow. 10 days by minus four Fulham charges place at point B four Coma Jiro meter charge off minus six in pretenders Bar minus four. Cola misplaced. And at one See, that is Cheeto Coma Tree A charge off one into tangles by minus four. Coolum is placed. Okay? No, like a sea like this. Flying forces on Brady's condition. No flush. Firstly, what is the X component off force that is exerted on sea by it means we have to find are the X component off. Fourth on, See, due to a basically, forcing due to a is purely invite direction that is in a poor direction. So x component off. This is Joe that is at sea access Jiro. Okay, now we have to find out of I component of force on seed you may have seen right. That is K Q one duty by our country square, That is Ah, nine into tenders by nine into three in tow. Attendance by minus four into one into 10. This part minus four by three meters squared. OK, if you solve this core values, you will get the answer off. 30 Newton. This is in positive y direction that isn't off for direction. Okay, this is the direction off FC and positive I traction. Okay, Now you have to find out the force on C Do Do be. No leg was supposed a the triangle condition. Ah, this is three meter and this is four meter no charge off minus six. Inter tenderness. Par minus four. Cola misplaced. Here. And chart one intact, endless par minus four will have is placed here. This is buoyancy and disappointment. Now, this baby exert force on seat to watch yourself. Okay. So forth on C due to be will be okay, Butto beauty by our B C square Or you considered are two or three square if this is the 0.3 and this is the point to so our duty square. Okay, uh, basically the value of our 23 this fight. If you see, this will be a right angle triangle. This is four meter and this is three meter. So from high Pythagoras tour, um, this will come. So, Toby, five meter. So if I put the values nine into tennis by nine into a six Inter tenders by minus. For in the values here, we are taking only magnet yours. Okay, Uh, one entertain this part minus four by five square. If you solve this, you will get the value of 21.6 21 0.6 Nuta. This is force on C exerted by B O only magnitude. Okay, Now you have to find out the X component off this foot. Basically, this force exerted in this direction because this is negative charge and this is positive charge, it will attract waters. And the X component is in this direction. That is absolutely X. And the vie component is in this direction. That is FCB. Why so teachable comes here? Because this is the extraction. The X component off this force FCB will be fcv course cheetah. Okay, The value off fcv is 21.6 Newton and the value of course to ties based upon hyper two news, that is oh, high protein is's or five and bases off foot. That is four. By fight into four by five, you will get the X component off. This force is 17 point toe it Newton for Vikram. Moment off. This force is FCB scientist. This is why complaining 21.6 in tow. Scientist. It will be three by four that is prophetically born High party Gnaeus two by four you will get the value 12.96 Newton. But this force exerted negative Y direction that is in a downward direction. So the negative science will comes off. Okay, this is the now let us suppose we have to find out the net result and force won't see that is exerted by both A and B but only in X company. Basically force on sea do toe X component of forcing c x component off fourth seed You okay plus X component or force on C due to be basically, this will be Jiro because they're no forced life and test will be. We find out earlier 17.28 Newtons. So net force on axe direction means next four Xanax. Campell names will be 17 going the mutant. Okay, Now we have to find out the vie component off, resulting force this on C do end. Basically vie component off force on C will be by component for foursome CDO a plus bi component off fours. Uh, on seeing you to be okay, so we find out that I see is 30 Newton in a poor direction. Plus, basically, this is in the negative by a negative y direction. Then it will be minus off 12.96 newton. Then it will comes to me. 17.4 Neutra in ah, four direction. This is the vie component off net result in force on C. Okay. Thank you. Now you have to find other net force on sea. Do A and B. Okay, so, uh, if I assume, like like a triangle, then this is 44 seed. You do a A. This is force on seed you to be and the net result enforce. Will, comes off somewhere like here. Some. They're like absi dessert. Okay. Not to solve this, we have to find out first the angle between them Basically, if I make a line here and this is will be 90 degree love, we have to find out this. Okay, This angle we have to find out without this angle were unable to solve this. Okay, let them this angle. B X So if this will be acts by alternate angles, this will also x Okay, so from course Cheetah missed by course X Uh, this is 435 We will get the value for by fight, so acts will be course in words for by five that is Tartus 6.86 degree. This is the value effects if you add this, uh, if you add the value off packs in this 90 degree, you will get the angle between this FC and Absi, That is Pita is 90 plus acts that is 90 plus touch his 6.86 diggy. That is 1 26 point air 60. Okay, now we know in the next Resultant is Bangu. Have fun square plus have to square plus two Afghan after course. Okay, so here, after one is at sea, a square blurs FCB square plus toe at C A F C B course 1 26.86 degree. Okay, thank you. If you will put all the values here that is 30 neutral square last 21.6 Newtown Square. Let's two in tow tarty into 21.6 into minus 0.59 Okay, this is a value off course. 1 26.8 60 Okay, By solving this, you will get an approximate answer off, resulting fourth, 24.4 newton. This is the next result and force on sea by D's to tow A and B. And this is in the direction. This way. Okay, well, this is all for me for this video. I hope you will like the video. Thank you.


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