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Constnuct 9% confidotco Intorvau , Uslt] tha Inenality - <ua<dtk Ho Lestathe @Hacinentas dng} that npled Ia Ikcqtase Iha nnta dhari aleep patientt gut duntlt...

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Constnuct 9% confidotco Intorvau , Uslt] tha Inenality - <ua<dtk Ho Lestathe @Hacinentas dng} that npled Ia Ikcqtase Iha nnta dhari aleep patientt gut duntlt9 Uwe nghl, nxsenrc hers randanly #eluct 13 palients and record tha number of hours atep Pnch gots valh nnd mlfaut Iha EWatoniE2ulthout Lhedrup) Slege using_the dryq 40436o36606 9Calculae (or Gich patient by subxricting nuinbcr nours sleep wth Ina drug Irom Ihe tulrnber wthaut the dug (Type Mee decimal Rourid decima Aoce needed )coli

Constnuct 9% confidotco Intorvau , Uslt] tha Inenality - <ua<dtk Ho Lestathe @Hacinentas dng} that npled Ia Ikcqtase Iha nnta dhari aleep patientt gut duntlt9 Uwe nghl, nxsenrc hers randanly #eluct 13 palients and record tha number of hours atep Pnch gots valh nnd mlfaut Iha EW atoni E2ulthout Lhedrup) Slege using_the dryq 40436o36 606 9 Calculae (or Gich patient by subxricting nuinbcr nours sleep wth Ina drug Irom Ihe tulrnber wthaut the dug (Type Mee decimal Rourid decima Aoce needed ) colidence inerv]l <ua<



Answers

Age and Hours Slept The ages (in years) of 10 infants and the numbers of hours each slept in a day \begin{array}{|l|l|l|l|l|l|l|} \hline \mathbf{A g e}, \boldsymbol{x} & 0.1 & 0.2 & 0.4 & 0.7 & 0.6 & 0.9 \\ \hline \text { Hours slept, } \boldsymbol{y} & 14.9 & 14.5 & 13.9 & 14.1 & 13.9 & 13.7 \\ \hline \mathbf{A g e}, \boldsymbol{x} & 0.1 & 0.2 & 0.4 & 0.9 & & \\ \hline \text { Hours slept, } \boldsymbol{y} & 14.3 & 13.9 & 14.0 & 14.1 & & \\ \hline \end{array} (a) $x=0.3$ year (b) $x=3.9$ years (c) $x=0.6$ year (d) $x=0.8$ year

If you have a number, suggest three point 15. This It's got a decimal point again. You can have another number such US four point 36 with the bar on top or no hole number. But serve point Sarah 15. So they start. Yes, the decimal point.

The first problem we're told um that it's a problem involving medicine. So the temperature in degrees Fahrenheit of a patient t. Hours after arriving to the emergency room is given by a. T. F. T. Which we're just going to call the local TFT um is equal to 98.6 Plus four co sign Hi T. divided by 36. Okay, so we have this craft And we see this going to be from 0 to 18. It's just the media reports right here. So we see that during this time the temperature is decreasing. We want to find the patient's temperature at 10. p.m. which is the initial temperature. So that's going to be 102.6 and then at four a.m. That's going to be six hours after. So x equals six. End up giving us about 102.064. And then by the time that there 12 hours later, so 10. a.m. And there Temperatures dropped about 100.6.

So let's say that you sleep for nine hours and you want to find out how much of your day is spent sleeping. So let's think how many hours on a day? 24 hours. Right. So, out of those 24 hours, nine hours are being spent sleeping so weakened by a faction nine out of 24. However, this can be simplified a little. So let's write out the multiples. So three times to be a is nine and three times eight is 24 so we can get rid of one of the threes and we get 3/8 of your day is spent sleeping, which is almost half, if you think.

So in the given question of a person, a person is given two mg of drugs drug each day. And during the 24 hour period, the body is utilizing the 40% of the amount and the demanding is 60% right. Since the body is utilizing the 40% of the drug each day. So the remaining drug at the end of each day would be 60% of two mg. Right? So at the end of first day that is a one would be equal to two, multiplied by Judah 20.6 to the power one for the second day. Similarly, it would be good opinion 60 square mhm. Similarly, at the end of third day the amount of drugs would be this much. So if we observe here, there is a pattern in the sequence and that's summing it up. We have sigma two multiplied by Judah 20.6 to the power hi where the value of I is wearing from 12 and right. So this is what we have to pull in the first part. Coming to the second part. We have to find the value of the amount of the drug at the end of each day, which is equals two, two, multiplied by 0.6 to the power one. So this is the remaining drug in the body for the end of each day. So when with all this, we get the value as 1.2 mg right, so 1.2 mg is left in the body at the end of each day.


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