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The following experiment was performed to determine the effects of two different growth media on cell division lusing three different kinds of tissue. Cell counts f...

Question

The following experiment was performed to determine the effects of two different growth media on cell division lusing three different kinds of tissue. Cell counts from each tissue were recorded after 10 dayb using media type or media type 2. This experiment was repeated three times for each media type with the following results:Media Type 574, 564, 550 524, 573, 551 576, 540 , 592Media Type 1092, 1086, 1065 1028, 1073, 998 1066, 1045, 1055Tissue A Tissue B Tissue €Set up the appropriate ANOVA

The following experiment was performed to determine the effects of two different growth media on cell division lusing three different kinds of tissue. Cell counts from each tissue were recorded after 10 dayb using media type or media type 2. This experiment was repeated three times for each media type with the following results: Media Type 574, 564, 550 524, 573, 551 576, 540 , 592 Media Type 1092, 1086, 1065 1028, 1073, 998 1066, 1045, 1055 Tissue A Tissue B Tissue € Set up the appropriate ANOVA table for this problem and find the appropriate sums of squares, degrees of freedom, and mean squares_ Test for the significance of the main effects and interactions. Interpret the results_



Answers

Many college and university students obtain summer jobs. A professor wanted to determine whether students in different degree programs earn different amounts. She randomly selected five students in each of the 3 university programs and asked them to report what they earned the previous summer (in thousands of dollars). The following partially filled-in ANOVA table was obtained. Fill-in the rest of the table. (Use exact values for df and round all other numbers to 2 decimal places, if needed.)

Okay, so here let the null hypothesis would be it's not after and this is a um one will be equal to m times me too. Okay. And there is no difference between the means of the uh two treatments A and B. Okay. And the alternative to have parties a little added here. Okay, so it will be clear and this is him times Me too. Okay uh And this is equal to me one. Okay? And the alternative hypothesis, uh it will be, me one will be not equal to a mewtwo. Okay. And there is no difference between the mean of the two treatments in B. Okay. Now, in part two we are given that K is equal to two and Alpaca is up 10 vibe. Okay? And the p value is calculated by f is equal to nine. this p value is So so par degree of freedom is equal to one and a degree of freedom 1 uh uh Two is six. Okay, so para critical value, it is calculated that alpa is uh uh so we are degree of freedom is uh so let let write it here. Right, so let's clear it. Ah Let or mean is who are mean is ah And this is equal to 12 plus 24 divided by eight. Okay, and this is 36 divided by eight. So this is 4.5. And the degrees of freedom one is came in as one, so this will be two minutes when this is one. Okay and the ss treatment is let the ss treatment will be ah the ss treatment is equal to the sum up end times, expat up I. Menace overall, overall mean square. Okay, so this is equal to four times three minutes. 4.5 whole square plus four times six minutes 4.5 whole square. Okay, So this is equal to four times menace. sq plus four times one point pipe squared. Okay, so this is four times 2.25 plus four times 2.2 points. Okay, so nine plus uh nine will be equal to 18. All right. And ah M. S. T. R. Is equal to ss and this will be equal to treatment Divided by degrees of Freedom one. So this is 18 divided by one. This is 18, right? And the ss arab is equal to some times the sum of squares. Okay, sum up square. So this is a poor plus eight. This is 12. Right? And the degrees of freedom to this is equal to n menos que Right? And ah in his administered to a six. So, the M. S. Error is and this is equal to the essence error. Okay. Do you want me by degrees of freedom to Now this will be equal to 21 by six? So this is two, right? And uh a P is equal to M. S. T. R, divided by M. S. E. Right? So this will be equal to 18 to everybody to this is nine. Right? And uh so f is equal to nine now? Uh Mhm. A little added here. Right? So this is the source. This is N. O. R. So this is between Okay. And this is written. So this will be more easy. Right? And this is total. All right. So this is S. S. And this is degrees of freedom. And this is mean square, mean square and Epp and eps Cv and P. Right? So this is 18. This is 12 and the total is 30 30 And d. as 1 6 and seven uh 167. Right. And the main square is 18 two and it is nine and ah FcV is 5.98 74. Okay. And P S 010 to 40. So and three. Uh So the decision is so since it test uh is yeah write it here. So, a test ah uh This is uh this uh mhm. Uh This is greater than a critical right. Greater than A critical of 5.98. So then we reject each night. We reject we reject that's not okay now. So also let the ap test is greater than a critical than we rejected snap. And also the P value is less than alpa. So then we rejected not. So by the decision are by the process of P value are with the ah ah let with the process of people. We also rejected because the value is Which is period a period of 0.02 pour zero, which is less than the Alpa. All right. So, we will also reject it. Not here now. Uh Uh so in part for our conclusion is so there is a sufficient evidence at 95% level of significance to conclude that uh there is a difference in the means of the two treatments, right?

So this grammatical question is about punctuation, and we want to make sure that um punctuation follows the correct grammar rules, so if we look at the underlying passage, we actually don't need a comma because we wouldn't normally pause at that point of the passage. So since it is unnecessary, we're going to go with an answer choice that eliminates that um comma or any punctuation, which is j. So answer choice, jay is correct, and the reason is no punctuation.

High for this problem. We want to test the Uh no hypothesis has a significance level of 0.05 data is provided over here. I collected from the problem, even though I find the strength that the standard deviation is still have rather than the mean. But if that's the problem is they uh it's kind of just do Okay, so, first we're gonna check the condition. So we just for the purpose of this video, we just assume the conditions on that. So assume sample. So random, assume the sample size is less than 1/10 of the population, so that we can assume independence and the normal condition. Uh since our sample size is not large enough to satisfy the essential limits the room, we just assume the population distribution is normal so that we can start testing practice. So, uh I'd like to write out a formula for the tea. Uh place, since we're gonna use it a two sample. Mhm. Mhm. T test for a difference of meat. Mhm. Yeah. All right. So, the format for t it's gonna be a swallow. T is gonna be called to the difference between the sample means minus the difference between the population mean, has hypothesized in the null hypothesis over The standard error. To standard error is the co two The standard deviation of uh sample one square over samples and substantial sample one plus this better alleviation of sample to square over the sample size of sample too. And so now, since in no hypothesis, we aside, we assume the difference gonna be zero became no difference this part indeed. Question you just become zero. Now we only have to do is put the rest in. So we have X one expo one is for United Streets minus 85 over standard deviation of distribution. Why square is going to be 200 square more than 10. Last 1 60 square over 10. So it's gonna give us a T. Score 00. Uh So it's 0.1. Mhm. Alright. So then we're gonna wrap it on the mm hmm we're visualizing so since we're doing to tell tests again, I don't know why the problems they increase um productivity of physical activity. But then you request me to do a two tail test. So I will do as you requested. So let's try to write down, run over here. Run over here. The middle is can be zero and this would be the point, what they will be called. What? Since we're doing two tail test want to find the area on the two sides. Yeah, that is going to be the area and come to find out. So we're gonna find that by. Uh huh. First. So the P value. Mhm. What are you going to do is we're going to find the area of one of the tail and then we multiply by two. So it's gonna be close to two times the area of the, of one of the tail. So the hotel, we're gonna use the TCP iP functioned on the graphing calculator For a local limit. We will put one times 10-99, times 29 99. And the epidemic when I got put negative zero point work and it's a degree of freedom. You're going to have Let me check out a 17.17 because that's what a calculator give us. Okay. And that's going to result in a p value equal to 0.92. All right. So, we have a P value when compared to the significance level. Uh, since .92 is bigger than .05. You have a p value watching on the alpha level. So having that we will make the decisions. We have. We have we have failed to reject the no hypothesis self. Our conclusion we write as follows. Okay, at the significance level of significance level of 0.05, there is not mhm, mm hmm. Sufficient evidence to conclude that the mobile app improve productivity, physical activities, musical activity. And that's going to be our final answer. I hope that helps

Hi I'm David and I'm here you have your answering your question. Now let me bring up your question here. Any questions going to fill up the end of the table and in this one here we are given that the treatment in has the three University programs means that we go to three and then we have the belief five students for each then found him in. He called you The three times 5 and equal to the 15. And now let me try to live on the Empty some being one two, three for five, six and seven. Now let me try to find the first. Uh let me try to find the missing sale. We made our first one and the great freedom from the treatment. Then we'll echo to the The number of the categories here and then -1 And therefore we have to go to the 3 -1 and negative ju and then they Next one I want to five it will be the number three and the decree freedom on the daughter Every Echo Children to do. And we -1. So we have equal to 15 -1. And we go to the fourth thing and then the degree of freedom followed to the creative freedom on the era. There we go to the end minus guy And then we get this on Echo to the 15 3 -3 and Echo to the trial. And then for the Number four, once you find some of square in the era and we could use some subscribed the doctor man is sum of square the treatment and I felt we get equal to the 24.31 strip 0.3 and eco june the trail And next one the # five. I want to find the mean square error on the treatment. They were equal to the sum of the square of the treatment of a degree of freedom. So we have to go to the trump on 3/2. Then we get to go to The 6.15. and next we will have the number six the mean square error of uh and then we have the same subscribed the era of the degree of freedom on the era. They were echoed to the ground running by trial and look at you one and then the last one we will have the seven. So we have here will be 6.5. There will be one. The upstairs here we go to the mean square error. I'm the treatment of a mean square error. All right. And then we will have this one will be in the 6.15 the 1x1-6.15. And this will be the 6.15. And that will be in the over temple. We need to fill up here


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