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Which one of the following aqueous solutions is estimated to have the point? lowest boiling0.40 m CsHizOg0.25 m KBr0.35 m NasPOa0.45 m CaBr2They = have the same boi...

Question

Which one of the following aqueous solutions is estimated to have the point? lowest boiling0.40 m CsHizOg0.25 m KBr0.35 m NasPOa0.45 m CaBr2They = have the same boiling point.

Which one of the following aqueous solutions is estimated to have the point? lowest boiling 0.40 m CsHizOg 0.25 m KBr 0.35 m NasPOa 0.45 m CaBr2 They = have the same boiling point.



Answers

(a) Which solution is expected to have the higher boiling point: $0.20 \mathrm{m}$ KBr or $0.30 \mathrm{m}$ sugar? (b) Which aqueous solution has the lower freezing point: $0.12 \mathrm{m} \mathrm{NH}_{4} \mathrm{NO}_{3}$ or $0.10 \mathrm{m} \mathrm{Na}_{2} \mathrm{CO}_{3} ?$

Now we'll discuss their problem. 85 from Chapter 13 in this problem were asked about two solutions UH, 0.5 Allow a T sodium fluoride or 0.5 mil ality potassium chloride, and which of them would have a boiling point closer to its predicted value. So now the issue is not what is higher boiling point, but what's one can we predict more accurately? So in this case, it would be the less ah concentrated solution. So this 10.5 has a concentration 10 times lower than the potassium chloride. And so the reason why this is is because of dilute, uh, solutions, behave more ideally and concentrated solutions. So as a rule, we can predict the loot solutions property is better than concentrated.

You compare any two eso four with sugar sugar will not associate uh, like any to s 04 Will and so any to us before will have a higher boiling point. If you look at in a two eso four vs and H for Enel three NH four n 03 has nine ah ions when it associates in a two s, 04 will have eight and so it will have any to s 04 for eight ions. NH four n 03 will have nine Any to s 04 will have a lower boiling point and therefore it will have a higher vapour pressure than NH four n all three.

Many to s 04 will associate into seven ions. Ah, sugar will not associate. And so any two s a four will have a higher boiling point. And a two s 04 will also have a lower vapor pressure. Then I'm sorry. Higher vapour pressure if you compare it to something like and age four and all three, which will have a higher boiling point then in a two s 04 and therefore a lower vapour pressure than any two s. So four.

If we compare for substances. Ah, a cheese Hochul ch 20 h c a c l to KBR and any to s 04 We'll find that the any to s 04 has a higher, higher boiling point on the lower freezing point on the other solutions based on its morality and the number of ions it has. Ah, the H o ch two ch 20 h will not associate, so it'll have the lowest vapor pressure.


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