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An electrician spends his mornings walking from his house to a specific spot on a river bank then back to his house: He repeats this wolk (or cycle) all morning lon...

Question

An electrician spends his mornings walking from his house to a specific spot on a river bank then back to his house: He repeats this wolk (or cycle) all morning long (continuously) The distance from his house to the riverbank was 1.6 miles His wolking speed was 4 miles per hour: How far does he walk in one cycle? (House to the river bock to the house) Calculate his cycle period in hours and in seconds Colculate his frequency (in Hz):2 A turning fork vintoges at 0 frequency of 600 Hz in @ room wi

An electrician spends his mornings walking from his house to a specific spot on a river bank then back to his house: He repeats this wolk (or cycle) all morning long (continuously) The distance from his house to the riverbank was 1.6 miles His wolking speed was 4 miles per hour: How far does he walk in one cycle? (House to the river bock to the house) Calculate his cycle period in hours and in seconds Colculate his frequency (in Hz): 2 A turning fork vintoges at 0 frequency of 600 Hz in @ room with normal oir (c = 344 m/s): If the turning fork is now moved to @ room filled with Helium (c 1000 m/s): What will it's vibrating frequency be? Would the wavelength decrease?



Answers

A student holds a tuning fork oscillating at 256 Hz. He walks toward a wall at a constant speed of 1.33 m/s. (a) What beat frequency does he observe between the tuning fork and its echo? (b) How fast must he walk away from the wall to observe a beat frequency of 5.00 Hz?

For this problem, on the topic of superposition, we're told that a student is holding a tuning fork which is oscillating at 256 Hz. The student then walks toward a wall at a constant speed of 1.3, m/s. We want to know the beat frequency that is observed by the student, between the tuning fork and its echo, and then we want to know how fast he has to walk away from the wall in order to observe a beat frequency of five hertz. Now, for a Doppler shifted echo, F. Prime is equal to the frequency of the tuning fork, F into the speed of sound. V. Plus the speed of the source V. S. Over the speed of sound V minus the speed V. S. And the beat frequency F B is equal to the magnitude of F. Prime minus F. So if we solve for this beat frequency, we get F. B. Is equal to F into two V. S over the minus V. S. When approaching the wall. So the beat frequency F. B. is equal to the frequency of the tuning fork. 256 Hz into two times the speed of the tuning fork, Which is the speed of the boy, 1.33 m/s, Divided by the speed of sound in a 343 m/s 1.33 m/s. This gives us the beat frequency to be one 0.99 hurts Next. We want to know how fast he has to walk away from the wall. If he wants to hear a beat frequency of five Hz now when he's moving away from the wall, V. S. Changes sign. And we can solve for B. S. And we get PS. Is able to repeat frequency F. P. Times V. Over two times the source frequency -DB Frequency F. B. And so this is a beat frequency of five hertz Times the speed of sound, 343 m/s, divided by two times the source frequency of 256 Hz minus the beat frequency of five. And so he needs to be walking away from the wall at a speed of 3.38 m/s.

All right. So in this problem Ah, we have to To new folks. Those frequencies are 400 hertz and for 40. So we can find out that the frequency f a called a difference of the two frequencies. Right? So it's full. Full t minus 400 which is 40 hurts. And in part B. We want to know that. Ah, if some wave trouble from their little water, so want to know the changes of the frequency gremlins and we've speed. So the frequency will not change because the frequency of independent source it does not depend on the mature. If the materials water or oil here, Okay. And, ah, the velocity the we've lost that. It depends on the material density. So the dance that is larger than velocities largely is larger. So permanent water. The water density is larger in the air density ray. So the velocity in the air is smaller and the velocity of the water okay, and we've lands have expression. Lambda equals V over Alfre. So apparently the Lambda is a proportion to velocity. So we see that lambda here. He's also smaller than an underwater, okay? And in Parsi, So we have situation. Uh, so we have two students, so first students on the second floor and, uh and this is a lot of students. And the first the students on the ground floor is ah, throwing up tuning fork. It is going upward. So want to describe the change of the frequency of the tuning fork? So, uh, for the students on the second floor, because as he see that on the tuning fork traveling toward him, right? So in that says, Ah, the frequency that he hears about this about this tuning fork. Let's say it's new. It's new. Second for us is actually larger, then new ground floor. So new ground floor is the ah, not Newport, for what I mean is in you not which is the which is the original frequency for this tuning fork. So this is from the top floor is fact. Okay, So as something is getting getting closer, getting closer to you, you'll see that the frequency is actually it becomes larger and ah ah biggest it is going up. And because of the gravity, the speed is slowing down, Ray So and that says ah ah ah the frequency that the student on the second floor here is actually become smaller and smaller, and they're getting closer. Closer. Toby, not who knew a lot. Okay, So in that sense, if we draw a diagram of the frequency for the students on the second floor, here is actually something like this. Okay, so this is mean. Listen, you're not so as time goes by, I've seen that to the new that he hear the frequency that he hears. Ah Esko is decreasing, and it is getting closer to new knots.

Hello, friends. Here it is given to his speakers. Driven by the same off senators or frequency 200 huts are fixed on the pole at a distance off permitted. Our men is moving towards the lower speaker from the far distance perpendicular to the pole. In the first part, we have to find how many times he can hear the maximum intensity off, son and in the B. But what are the distance at that time from the port? Take the speed of sound, Toby. 3 30 m per second. Supposed at any moment, man is l distance away from the speaker. Then part difference between them will be rude. Off Ellie Square less Do square minus. And that's on wavelength will be be upon f for the spectrometer friends to take place. What difference? IPI two in minus one Lambda way to here and is the intelligent 123 and sort. Substitute the value here. Uh huh. Be upon toe transport system. This site we are solving for value off l home squaring with the site. So from here you will get l Toby. Do you square minus it? Can Britain It's and minus house. We received the part difference starts from the early Europe, right? The man is very far away from the speaker on. The increase is to be Yeah. Mm hmm. Then And it's going to zero. The number the number of minima he hears is the greatest into Egypt. Mhm, Mhm Be upon f, right? Yeah. The is greater than right. It's called the greatest interior listed the F upon Be. But that's how Yeah, Yeah, party. Simplify this. Well, mhm D is given for frequency is 200 hertz. Speed is 3. 30. So this quantity you are getting 2.92 It means he hears to minimum. So answer apart is to minimum. Oh, right, no deeper than any skull to burn. And it's called the square minus. You know little well, this value will be 9.28 m similarly for And it's called Toto, 1.99 m. That's all for it. Thanks for watching it


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