5

[0/2 Points] 8 S signment Submission DETAILS 7 | Scoring Ed Vollcanb Ao ANSTERS SCALCETB 2.7.044, 1Neod Help?2MietaFTeviau; Qucstior 9 Quesuon |z0i 20 1Isind1MYNOTE...

Question

[0/2 Points] 8 S signment Submission DETAILS 7 | Scoring Ed Vollcanb Ao ANSTERS SCALCETB 2.7.044, 1Neod Help?2MietaFTeviau; Qucstior 9 Quesuon |z0i 20 1Isind1MYNOTES 2

[0/2 Points] 8 S signment Submission DETAILS 7 | Scoring Ed Vollcanb Ao ANSTERS SCALCETB 2.7.044, 1 Neod Help? 2 MietaFTeviau; Qucstior 9 Quesuon |z0i 20 1 Isind 1 MYNOTES 2



Answers

Use the terminology from Section 8.2
Repeat Exercise 9 for the points $\mathbf{q}_{1}, \ldots, \mathbf{q}_{5}$ whose barycentric coordinates with respect to $S$ are given by $\left(\frac{1}{8}, \frac{1}{4}, \frac{1}{8}, \frac{1}{2}\right)$
$\left(\frac{3}{4},-\frac{1}{4}, 0, \frac{1}{2}\right),\left(0, \frac{3}{4}, \frac{1}{4}, 0\right),(0,-2,0,3),$ and $\left(\frac{1}{3}, \frac{1}{3}, \frac{1}{3}, 0\right)$ respectively.

Received at the points. The points Q won't, which is given us one over AIDS one over 41 over ends. What over it soon is inside the convicts, all of theirs. This is because, but Barry centric Orjan needs all positive. He's Andi. Also something warm? No, the points cute Sue on cue. For Which is it? Walter? Were cute. Suit is three over four minus one of the 401 of a zoo and then Q for zero minus 20 comma three. They are outside the convicts all off earth because be Considine Negative Bar Centrale coordinates. Ordinates. No, the points Q three, which is given a zero the year before. One of our 40 is on the edge. Do swing Vergis ese v tsu on victory. This is because this second on towards it's second on toward coordinates our course. It's Eve. I'm something Warren on the forced on fourth co ordinates zero. Now, lastly, we have Q five is on the fins. Consuming the bodice is V one v. Tsu on victory. This is because the forced 3/4 needs war grenades. Uh, faucets on something. Warren, we're us. The fourth coordinates zero is zero

We are going to do problem number eight. And discussion for four points are given. So we decided that point. 1st Point is given a 0:03. Now, point B is given, that is three comma menace, one point she is given that is managed to Got my minutes six and point he is given that is Man, I said comma two when I said come on to so what we need to so is we need to so that this is the point of trump, ADM or trapezoid. Okay, draper enjoyed. So this shape will have two vortices that is possible two sides as paddle, not where this is, two sides are parallel as this will have figured something like this. Okay, so this suddenly surgery panel so you can just check whether to sides have same slope or not. So again, we are going to use this formula for slope, that is Why two minutes 5, even by X 2- Actually. Okay, buy extra minutes. Excellent, Leonard is just the start checking for, we will check for a B first. Okay, so a B in case of a B y tu minus five and so have I to his minus one minus minus three. Bye X two X two X three X one is zero. So here the slope is coming out to be Menace four x 3. Okay, now we will check for another part that is for Well Let's say four BC. Okay, so for D C. M That is equals two minus six- of -1. Bye. Managed to minus three. So this will be equals two minus six plus one. That is Menace five by managed to ministry that is -5. So this will be equals to one. So the slope of BC is coming out to be one here. Now we will check for city Okay, No, we'll check for cities same formula we're going to use. So here this is two manners minus six. This is further divided by man is it? Man is self managed to show you. Just see how much this is. So six plus two. That is eight By many said Plus two. So this is -6 from here. We we got m equals two -4 x three. If we divide numerator, denominator by two. Okay, so if you check this part that is minus four common three minutes for common Menace four by three. These two are same. The slope is saving these both cases. So this is uh the services of trippy jim. Okay, this is the this is a trapezoid. The both are same. No, well check this low for the last one that is Eddie. Okay, so let's just find this slope already. So this will be um equals two. Why? To that is two men 3 by X two minus Saxon. So X two here is Mena said zero from here. It is going to minister that is -1 by a man is set. So management issues getting canceled. So it is one bite. Now you can right here. The slope that we got is Slopes that we got in this case is -4 x three comma minus four by three comma one. That is equals to one and not equals to that is the next one that is one by it. So these are the slopes which we got in this case. So this is the answer. Thank you.

We are I guess I should say, I'm trusting that we can use a graphing calculator based off the difficulty of this problem, at least decimals are not easy to work with. That's very over 0.9 Is equal to one. So you can see the center in this one because of that shift, the left at the center is off. Just a little bit agency where the top and the left and right of the circle. R uh sorry, of the ellipse is off just a little bit. Oops zoom in a little bit there ago. Whereas when we compare that to the other equation, we have x squared Divided by 0.9 plus Y -15. So I'm I 1.8 one. Now you can see there's four points of intersection here. Uh So maybe I'll even tell you where the center is on that one, It's shifted to the right, zero but 0.25. So you can see that dot is representing the center of that purple ellipse, whereas the green dots, the center of the blue ellipse. So you can evaluate some pieces in here and figure out where the vortices are supposed to be located. But what we really care about are the four points of intersection and I don't know the better way of doing it than just graphing it the way we've done it and writing out those ordered pairs, you should have four of them. Um So you might want to pause in the video and uh right out all those answers and make sure you have all four of them. Because the ellipses, this is two ellipses cross four times.

So the given points are 01 half to native one and negative 47 halves. That's our X one y one x two by doing extra y three. And then we put one's Donald. Last colony year, it was a three by three matrix. We take the determinant of this matrix and then these given points. Excellent. I want X two y two and x y three are co linear or they all lie on the same line if and only if the value of this determinant is equal to zero. So we expand along the first row here. So what we get when we get zero times all times, it's minor. So, um e that's already in here. But it's gonna be zero, because zero times anything is zero. But we could zero times it's minor, which is We cross out the road and the column that our entry is in. So the minor here is negative. One 17 halves one. But then we get minus with authentic science. So we have minus one half times. It's minor is going to be too one negative 41 and then we get a plus. While just one times It's minor, which becomes a again crossed with row and column that our entry is in. So you get two by two determinants. We get to native one negative for seven halves. See seven half right. So we go ahead and evaluate so we get zero times or something this determinant. I don't care what it is because time zero So that is gonna be zero. And then we get minus well, one half times one times two times one, which is two minus negative. Four times one that's two minus and negative. Four becomes two plus four. And then there's the plus one times while too times seven halves. That's seven, right? So we get seven minus negative four times native one. So that's again. Two times seven halves is just seven. That's seven minus a positive force in Southern minus four. Okay, so this becomes how we have zero minus what? More minus native? One half times two plus four. That's two goes for six. So six times native one half that's native three. So get zero minus three and then plus well, one times a minus four, which is three. That's plus three. So zero minus three plus three zero. So this is equal to zero. So since our determinant here is equal to zero, then yes, the given points are all coal linear. So yes, Yes, they are cold air. All right, take care.


Similar Solved Questions

5 answers
Researchers collected random sample of student data over 9-year period from the university admissions office, and summarized it in the frequency matrix below: Note that the element in the j) cell corresponds to the num- ber of students in the sample that progressed from state to state one academic year:So NR 1425 754 900 672 591 Se 577 1260 NR 61 34 26 7 456 457 DT 45 21 10 11 100
Researchers collected random sample of student data over 9-year period from the university admissions office, and summarized it in the frequency matrix below: Note that the element in the j) cell corresponds to the num- ber of students in the sample that progressed from state to state one academic y...
5 answers
For each permutation T of 1, N, let LIS(w) denote the maximal length of an increasing subsequence in T, and let LDS(r) denote the maximal length of a decreasing subsequence in (a) Show that LIS(F JLDS(T) > N for all T. (b) Let TN be uniformly random permutation of 1, Show that the expected value of LIS(Tw) is at least
For each permutation T of 1, N, let LIS(w) denote the maximal length of an increasing subsequence in T, and let LDS(r) denote the maximal length of a decreasing subsequence in (a) Show that LIS(F JLDS(T) > N for all T. (b) Let TN be uniformly random permutation of 1, Show that the expected value ...
5 answers
Meb 2414 Lab 6Page12&.2*@2 9
Meb 2414 Lab 6 Page 12 &. 2*@ 2 9...
5 answers
Concentration and VolumebbedeJu 0.44MXLCL Manl tolena orblood cuanin LONNtch47.60 mL ofa 180 Msolution Is diluted to volume of 278 mL A 139 mL portion of that solution Is diluted using 139 mL of water. What is the final concentration?48. Given a 0.75 M solution of AgNOBlaq); what is the mass of Agt in a 175 ml sample of that - solution?MW of Ag = 107.86 g/mole MW of N =14 g/mole, MW of 0 = 15.99 g/mole
Concentration and Volume bbede Ju 0.44MXLCL Manl tolena orblood cuanin LONNtch 47.60 mL ofa 180 Msolution Is diluted to volume of 278 mL A 139 mL portion of that solution Is diluted using 139 mL of water. What is the final concentration? 48. Given a 0.75 M solution of AgNOBlaq); what is the mass of ...
1 answers
Most abundant element dissolved in sea water is chlorine at a concentration of $19 \mathrm{~g} / \mathrm{kg}$ of sea water. The volume of earth's ocean is $1.4 \times 10^{21} 1$. How many g-atoms of chlorine are potentially available from the oceans? Density of sea water is $1 \mathrm{~g} / \mathrm{ml} .\left(N_{\mathrm{A}}=6 \times 10^{23}\right)$ (a) $7.5 \times 10^{20}$ (b) $27 \times 10^{21}$ (c) $27 \times 10^{24}$ (d) $7.5 \times 10^{19}$
Most abundant element dissolved in sea water is chlorine at a concentration of $19 \mathrm{~g} / \mathrm{kg}$ of sea water. The volume of earth's ocean is $1.4 \times 10^{21} 1$. How many g-atoms of chlorine are potentially available from the oceans? Density of sea water is $1 \mathrm{~g} / \ma...
5 answers
Evaluate each expression. See Example $4 .$$$6^{-1}-4^{-1}$$
Evaluate each expression. See Example $4 .$ $$ 6^{-1}-4^{-1} $$...
5 answers
Problem 2aSolve the equationVy? - x2 dx + dy =arcsinin implicit formProblem 2bSolve the equation(z2 y )dw + 3ry?dy = 0in implicit form_
Problem 2a Solve the equation Vy? - x2 dx + dy = arcsin in implicit form Problem 2b Solve the equation (z2 y )dw + 3ry?dy = 0 in implicit form_...
5 answers
Fky = Vzi + 372 + 3y2Step 0f 2 Find
fky = Vzi + 372 + 3y2 Step 0f 2 Find...
5 answers
For the experiment of series RL in Ac circuit; write the following: The objective (0.5 marks) Apparatus Required (0.5 marks) Draw the circuit diagram (0.5 marks) The Procedure marks) For a given value: V = 200 V; R = 80 0,L =0.191 H calculate the circuit current for 100 Hz, f = 500 Hz and f = 1000 Hz (1.5 marks) Use the calculated values to draw the graph between the current Vs frequency (0.5 marks)(0.5 marks)Conclusion
For the experiment of series RL in Ac circuit; write the following: The objective (0.5 marks) Apparatus Required (0.5 marks) Draw the circuit diagram (0.5 marks) The Procedure marks) For a given value: V = 200 V; R = 80 0,L =0.191 H calculate the circuit current for 100 Hz, f = 500 Hz and f = 1000 H...
5 answers
(6) Define H : R - R byH(z) =/ (sin (t))2 V1 + tdt. I2Prove by citing the appropriate theorem(s) that H is differentiable on R; and calculate H' (x)_ Be sure to justify YOur reasoning at every stage.
(6) Define H : R - R by H(z) =/ (sin (t))2 V1 + tdt. I2 Prove by citing the appropriate theorem(s) that H is differentiable on R; and calculate H' (x)_ Be sure to justify YOur reasoning at every stage....
5 answers
6. g(c) = 2 + I +1
6. g(c) = 2 + I +1...
4 answers
Find the following limit or stale that it does not exist lim (2x - 1) X39
Find the following limit or stale that it does not exist lim (2x - 1) X39...
5 answers
In mice coloring is determined by three alleles of the agoutigene. AA, codes for agouti coloring,AT codes for black with tan belly, andAB codes for all black. The dominance orderis AA>AT>AB. What proportionof offspring are expected to be black with a tan belly from thefollowing cross ABAT xAAAT?1/8none3/41/41/2
In mice coloring is determined by three alleles of the agouti gene. AA, codes for agouti coloring, AT codes for black with tan belly, and AB codes for all black. The dominance order is AA>AT>AB. What proportion of offspring are expected to be black with a tan belly from the following cross ...
5 answers
12. [0/4.54 Points]DETAILSPREVIOUS ANSWERSLARCALCET7 5.7.005_MY NOTESASK YOUR TEACHERPRACTICE ANOTHERFind the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constant of integration ) 2 dx
12. [0/4.54 Points] DETAILS PREVIOUS ANSWERS LARCALCET7 5.7.005_ MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constant of integration ) 2 dx...
5 answers
QUESTIONrecent study =lationship between social activity ad education showed the following results: Social Activity Above Average Avctuge Below_AvcrageEducation College High School Gradc School The degrees of freedom for the analysis130
QUESTION recent study = lationship between social activity ad education showed the following results: Social Activity Above Average Avctuge Below_Avcrage Education College High School Gradc School The degrees of freedom for the analysis 130...

-- 0.021560--