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Tumailuu-naleionuco Wnve WlrWeneranco052 [0.65 mHanttn...

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Tumailuu-naleionuco Wnve WlrWeneranco052 [0.65 mHanttn

Tumailuu-naleionuco Wnve Wlr Weneranco 052 [ 0.65 m Hanttn



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Multiply. $$0.2\left(6.8 m^{3}+0.44 m-7\right)$$

We're being asked assault to given equation for so first we want to do is get rid. There are fractions, and it might be a little difficult at first to see what our least common denominator would be. So I'm gonna write our fractions out to the side. Well, 0.65 as a fraction would be 65 over 100 1.5 is a fraction would be 15 temps and 0.43 as a fraction would be 43 hundreds. So now is easy to see. That 100 is our common denominator. So we're gonna go ahead and multiply both sides of our equation by 100. Now, remember, when multiplying decibels by 100 you just need to move the decimal 1000.2 places to the right. So on the left hand side, we have to distribute so 100 times 0.65 Well, in with the decimal 0.2 places to the right. So we get 65. Next, we multiply 100 by 1.5 them again with the decimal 0.2 places to the right, so you'll get positive. 150 equals and 0.43 times 100 again, Remove the decimal point. Two places to the right. So we'll get 43. Now we've got over the broad decibels. Now I see we have, like, terms on the left hand side of our equation. So let's combine them. Well, 65 m plus 150 m is 215. You have 215. Em is equal to 43. So now we got to get them by itself. So to do this, we're gonna divide both sides of our equation by 215. So I mean that want to reduce? Well, we can reduce both the numerator and denominator by dividing by 43. Well, 43 divided by 43 is one and 215th about by 43 is five. And now we've solved our equation for em. So what? The solution is that em is equal to 1/5

All right. So we need a multiple of these, but we can see that we have a difference of squares because we have the same terms and one of them has a subtraction sign, and one of them has, in addition sign. So if we remember, the formula for the difference of squares is a is a squared minus p square where April's be times a minus bi. Okay, so But that said, Oh, we're gonna have to do is where this and then square this so poor their 0.1 squared is 0.1 and then we have m squared. Then we subtract 0.41 squared is 0.16 eight once word So our final answer is 0.1 and squared minus 0.1681

Okay, so we're asking simple fighters falling. So we have em cubed, and I'm cute here. Remind us he showed his to be cancelled, and we have m squared by itself. So that's 4.2. I'm squared. And then, uh, M in common, minus nine minus 1.2 which is get a 10 of point girl to, um and then we have 0.6 plus 0.5, so that's equal to plus 1.1.

Eso we want to know about, um a sulfuric acid solution 0.1 muller sulfuric acid solution on And we want to know the hydro Nia, my on concentration and ah, sulfuric acid, of course, is a strong acid. The first proton will disassociate 100% and give us 0.1 model airport once era Moeller I droning on my on, But then the hydrogen sulfate ion has got a pretty large K a for a weak acid points. It's 1 to 1.1 times 10 to the minus two, which is 20.11 So we are going to get a little bit mawr age plus from the 2nd 1 And so it's gonna be a little more than, uh, 10.1 Moeller because we get that from the first proton, plus a little from the second. But we're not going to get both of the protons to dissociate completely. So those are all out. And in fact, what we have seen is that the second Proton, once we've had 100% association or whatever dissociation of the 1st 1 then the 2nd 1 tends to give hydro Nia my on equal to the K a value. So the second Proton will give us this much high droning my on the 1st 100% So this much so when you add them to get 0.111 and so that would be the hydro me in my own concentration.


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