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20 m high stuirs 0l u constont = 'spced Lf i tukes him A 75 kg mon nuns up whal i$ his Jveruge MWET Seconds reich Ihe top of Ihe stairs Walty? [Onus",Cite...

Question

20 m high stuirs 0l u constont = 'spced Lf i tukes him A 75 kg mon nuns up whal i$ his Jveruge MWET Seconds reich Ihe top of Ihe stairs Walty? [Onus",Cite10z5 1875 2125 2175

20 m high stuirs 0l u constont = 'spced Lf i tukes him A 75 kg mon nuns up whal i$ his Jveruge MWET Seconds reich Ihe top of Ihe stairs Walty? [Onus", Cite 10z5 1875 2125 2175



Answers

Lars, of mass $82.4 \mathrm{kg},$ can do work for about $2.0 \mathrm{min}$ at the rate of $1.0 \mathrm{hp}(746 \mathrm{W}) .$ How long will it take him to climb three flights of stairs, a vertical height of $12.0 \mathrm{m} ?$

As you claim in Stakis the Great and which your potential energy increases is the same as a rate and what you do what and this rate is also known, is your average power. An average power is change potential energy over the change in time. So there are eight and what you do work is known as the power and the changing potential energy. It was just him. Hence g times we're changing heights. Do we have all these variables? Well, yes, we do. So free range secretion. We can calculate how long it will take someone to climb three flights of stairs if we know the average power doing something so doubt, t is it too M g Delta, right? Oh, look, the average how in this case we know the average power we know the height of the steak is and we know a massive individual. So if we substitute in our values, you find delta T is the culture 30 seconds. So a person off mass, 82.4 kilograms. Can you work at a rate off? 746 jewels per second? 726. What? We'll take 13 seconds to climb a flight of stairs and reach a height 12 meters

This question, we will learn about some basic concepts of what energy and power like. The question is a man whose weight is given us 16 years, climbs up their gas, which is carrying a lot of 20 kg. So I'm two Sequels to 20 kg on his head leg. The staircase has 20 steps each of hide 20 cm. If it takes 20 seconds to claim, then we have to find the power. So the total weight would be equal to the total mass would be equal to 60-plus 20. That is a close to 80 Kg And the height is equals two so the height is 20 centimeters side. So 20 cm can be written as Jesus find two m. The total height Of the hotel guests would be called the 0.2 multiplied by 20 since there are 20 steps, So this would be equal to four m. The gravity explosion would be equal to 10 m/s squared And that I am bacon is 20 seconds. So these are the information. Now the power is equal to the work done, divided by time taken. The well done is done against the gravity. Right? So that is MGH divided by T The weight inside the masses, 80 Kg gravity is 10. Total height is four m and the time they're going to 20 seconds. So when with all this, we get powerless 160, What? Yeah, Hence the correct option is a Yeah

All right. We have this gentleman and he runs up a flight stairs that are 20 meters high. He's got a mass of 80 kilograms. Heidi Stairs is 20 meters. Hi. And he does it in a time interval of 10 seconds. 10 seconds when a box is information here. So question is, we want to figure out much power. He, um how much power is used to lift this man up this flight of stairs? And we also want to figure out what happens if his if his body is 25% efficient. Which powers expend in this case? So let's give it a go power equals work over Delta T. The work in this case would be force times distance, but by Delta t we consume just one dimensional Aziz because, um, way assume one dimensional because it's, ah, conservative force field. So it's very convenient because have force times, distance force being mg distance being each. You could also think of this as using almost like the work energy theorem we have. Work equals Delta K. Let's tell to you, and you can see have no connect energy years, all potential. And it's here at the bottom so that you would have working. Was MGH all the way to get him into a demonstrate that? But by the way, both situations work. Either way, it's MGH in the numerator and delta t in the denominator we have than the power equal to 80 kilograms for mass. We have a gravity acceleration 9.81 dropping my units just to make the math more clear here. And then each is my 20 meters and will be divided by the time interval of 10 seconds. And we get a power output of 1568 jewels per second. Go ahead and box set in right here. All right. Now what if he's only 25% efficient? Remember, than P would be equal to 0.25 times power of body. And then this part here describes that efficiency issue. Go ahead and salt. For a Peabody, Peabody equals power. The bottom by 0.25 which equals 1568 multiple before or divided by zero points. You five, by the way, you get how are a body equal to 6200 in 72 Jules for a second, given that efficiency issue

The force normal is what they're calling the apparent weight and this would be equal to the mass times acceleration due to gravity. This would account for the gravitational force plus the acceleration of the system in the Y direction. Now we can see that the apparent weight is 750 Newtons. This would be equal to the mass. This would be equal to 9.8 meters per second squared plus two meters per second squared. And we find then that the mass is Equalling 63.56 kilograms. So we can say that the true weight would be equal to mg. This would be equal to 63 0.56 kilograms multiplied by 9.8 meters per second squared. And we find that the true rate is approximately 620 Newtons. That is the end of the solution. Thank you for watching


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