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Create Viceo Explaining the belon Problem Lesson 2-6 Related Rates Std: AP CALCHA 3/Ccss 6.0 Sucel Crnterio Jo) Lcon Find the related rates_to_sole_real lite_Brobke...

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Create Viceo Explaining the belon Problem Lesson 2-6 Related Rates Std: AP CALCHA 3/Ccss 6.0 Sucel Crnterio Jo) Lcon Find the related rates_to_sole_real lite_Brobkems Ib) I can describe_and compong_soluion nethodsStudentII spilling (rem rptured tankct sprcads cink on thc suruce 0f tne &can Manaot sPill incteaees 44 Nic of 9x nrInun_Hov {24 n th nius ol Ikx "PIlI nctesintg when Idius /$ 40 m?Student 2Student 3JlateecMn CUawerin Mlueltich Mau o utent nEecaunn MnntenAnAMET Aelruty MAm I

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In a tetrad analysis, the linkage arrangement of the $p$ and $q$ loci is as follows: Assume that ' in region i, there is no crossover in 88 percent of meioses and there is a single crossover in 12 percent of meioses; in region ii, there is no crossover in 80 percent of meioses and there is a single crossover in 20 percent of meioses; and - there is no interference (in other words, the situation in one region does not affect what is going on in the other region) What proportions of tetrads will be of the following types? (a) $\mathrm{M}_{\mathrm{I}} \mathrm{M}_{\mathrm{I}}, \mathrm{PD} ;$ (b) $\mathrm{M}_{\mathrm{I}} \mathrm{M}_{\mathrm{I}}, \mathrm{NPD} ;(\mathrm{c}) \mathrm{M}_{\mathrm{I}} \mathrm{M}_{\mathrm{II}}, \mathrm{T} ;(\mathrm{d}) \mathrm{M}_{\mathrm{II}} \mathrm{M}_{\mathrm{I}}, \mathrm{T} ;$ (e) $\mathrm{M}_{\mathrm{II}} \mathrm{M}_{\mathrm{II}}, \mathrm{PD} ;(\mathrm{f}) \mathrm{M}_{\mathrm{II}} \mathrm{M}_{\mathrm{II}}, \mathrm{NPD} ;(\mathrm{g}) \mathrm{M}_{\mathrm{II}} \mathrm{M}_{\mathrm{II}}, \mathrm{T}$. (Note: Here the M pattern written first is the one that pertains to the $p$ locus.) Hint: The easiest way to do this problem is to start by calculating the frequencies of asci with crossovers in both regions, region i, region ii, and neither region. Then determine what $\mathrm{M}_{\mathrm{I}}$ and $\mathrm{M}_{\mathrm{II}}$ patterns result.

All right for this one. I've gone ahead and said, Oh, here, let me make it a little smaller. So if it's on the screen, there we go. Um, I use an online calculator called Does Most Feel free to check it out. You know, if you've seen any of my videos, That's what I like to use anyway. Is this linear? And if we look at it, I'm gonna go ahead and draw a line and say the best fit line might look. Yeah, I think I could do it. Hair better than that best fit line off this actually. Freehand drawing right here. Best fit line somewhere. Like that. Maybe a bit higher. So, yes, I'm going to say this is indeed linear.

This question tells us that in Organa, metallic compound contains at least one metal carbon bond. An example of an organo metallic species. Is this CH. Three siege to MM br where M is a metal? Um and so they asked us. In part part A. If M two plus has the electron configuration a r. Three d 10 what is the percent by mass of end in that come out so and two. Plus, um, if we look at the periodic table, we go toe are gone, and then we we know that there's two electrons missings that we add to and then go to three. D 10 will find that this is zinc and zinc has a mass of 65.4 grams per mole, Um, and the rest of this compound. So the siege three, siege to A and B are we end up with this whole of two carbons. One think one bro mean and five hydrogen. So carbon two carbons equals 24 g per mole. Thes Inc was 65.4, bro. Mean is 79.9 and five. Hydrogen would equal five. So all of this together equals 1 74.5. So if we take, we want percent of mass will take that 65.4 from the sink over the total of 1. 74.5 and we will get 0.375 So that's a total percent of 37.5% by mass that the end takes up in that compound. Then Part B says that a reaction involving the compound that we just looked at is the conversion of a key tone to an alcohol as shown here on and they ask, how does the hybridization of the start carbon atom changed if it all going from reacted to products. So the hybridization of this carbon here is f p two and we know that because it has one pie pond. So, in general, a general rule of thumb is that if they on Adam has no pi bonds, it'll be SP three. It has one pie bond. It will be SP two. And if it has two pi bonds, it'll be SP. This one has one pie. Bronze was SP two, and this carbon over here has zero pi bonds. So it's s P three. So we've gone from SP to toe sp three during that reaction and then part c asked us for the systemic name of the product. So this, um, is the molecule of the product. I'll just redraw it to make it easier to see. So first we're going to look for the longest carbon chain and that is going to be this chain right here. And then we'll number it to put the alcohol. The lowest number competes, and that has the highest priority. So this will be one too. 3456 carbons. We have a metal group here and here on carbons three and four. So that will come first. So we'll have 34 dime. Ethel, you do have to say dimethyl even have already indicated to locations. And then we have our alcoholic carbon three. So three and then six carbons is heck sane. And then we add ol to the end indicate the alcohol So 34 dimethyl Hexen all is the name for that product

This is problem # 26 we are given a set of data regarding the number of pixels in an MRI image and the IQ score of a student. So we will begin by finding our Russian equation. So for our some of x, we get eight .76 million For the sum of why we get 173 0.17 Put some of x times y. We get 154 million. For the sum of x squared We get 77.2 times, tend to be 12th 7.7, 2 times 10 to the talk. And for the sum of y squared we get 8695 6. So using these for our regression equation, we get the following, we have white hat equal to 6, 65 times 10 to the mhm minus five X minus 40 point 999. So I would just write this as -41. So we now have our regression line notice that the value of the slope is incredibly small, but this makes sense as the values we are using are very large for inputs and the values of our outputs are fairly small in magnitude relative to them. Next, we will predict Two values firstly, for x equal to one million. We get a predicted Y value equal to 25.53 And for the value of 830,000, we get a predictive value for why hat Equal to 14.22.

Yeah. All right guys, the first thing we need to do here is we do identify on are null and alternative hypothesis are no hypothesis. Excuse me being that the variations are going to be the same. And the turn of prosthesis is that they're going to have different variations as you can see right here. Okay, so the next thing I did to solve the problem was I opened a google she and I am putting a lot of the data. You'll notice all the data is and put it right there. Okay. And then, so what I'm gonna do from there, what I'm gonna do from there is this I'm gonna go ahead and calculate the variances for each. The first variance I'm gonna calculate using google sheets. So I'm gonna type equals var open parentheses and then just highlight everything I want. I know have an extra box in there. That's not a big deal. And there is my first variant. Second variants will be found the exact same way it looks like it already knows what I want, which is great. And there is our second variance. Alright, so from there I need to find my f statistic. Okay, so my F statistic is just going to be the greater variance divided by the smaller variance and there we go, there's my f statistic. Once I found my F statistic, I'm ready to find my P value. Actually. Sorry, scratch that. Once I find my F statistic, I'm almost ready to find my P value. But there's one more step in order to find a P value. Using google sheets with an F statistic. First need to calculate degrees of freedom. Okay, very easy to do in google sheets. So degrees of freedom is just all the data, the amount of data you have minus one. So how do you find that? Google sheets is equals count. Just highlight everything. I have noticed how I do have an extra box there. That's not a big deal to subtract one. And that I have 20 in this case 24 degrees of freedom. And in our second case again equal count Open parentheses, highlight everything and I do need to subtract one. And the other case have 15 15 degrees of freedom. Okay, so now I'm ready to find my P. Value. So my P value uh through here is going to be something called an F. Distribution or F. Dist. And then open parentheses. I need to put three values. Number one, my F statistic. The second value is going to be the number of entries from S one squared. I'm sorry the degrees of freedom from s one square in this case is 24. And my last and final value is the degrees of freedom from my S two squared. So that's right here. I close all that up and there is my P value. However, I'm not quite finished yet. Okay, that is a P value for a one tailed distribution. What do I mean by that? That's a good P value. If that was a greater than or less than sign, this is a not equal to sign. Okay. That's not equal to sign. Which means um uh that which means that I have actually had the wrong P value right now. Since this is for a one tailed distribution and I need a two tailed distribution because they're not equal sign, I need to take this value multiplied by two. So equals I click on the value multiply symbol in google sheets. Asterisk hit A two and I'm done. That is my P value. Notice that P value is just a touch above 0.05, meaning I'm going to fail to reject the no hypothesis. I'm gonna fail to reject. And all hypothesis


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