5

5. Given the two sequence of length are: x(n) {1,3,5,7,9,11,13,15} h(n) {1,3,5,7,9,7,5,3} Find the circular convolution:...

Question

5. Given the two sequence of length are: x(n) {1,3,5,7,9,11,13,15} h(n) {1,3,5,7,9,7,5,3} Find the circular convolution:

5. Given the two sequence of length are: x(n) {1,3,5,7,9,11,13,15} h(n) {1,3,5,7,9,7,5,3} Find the circular convolution:



Answers

Find the generating function for the finite sequence $1,4,$ $16,64,256 .$

I am. This one goes your half times would I end just you over a and and we get the injury. Coach Jude and I tried to find the anyone but formal gonna have times when the choke last Jew on Jew and we're gonna have Thames with ah three. And it could be 2 3/2 Now, the a Jew, will you go to 1/2 times with the 3/2? Blessed do it. Even invited 300. You forget 1/2 times window. Do you like to plus for over three and then which would include your half times with the isn't over six. Now then we have done I press eight ego just 17. And then which get Nico to $17? Uh, it's around and we see that can be a very big truth. Be one fun weapon for 16 on this will be in the 1.5 if we say that, uh, and these known increasing. And how did you find the limit? I'm to see guns, Nia. I would assume done no limit under high end. And just your infinite day, you could use some constant isn't obliged under limit under AM less one. And we're also a good you, Some constant interests. Well and now every applied a limit on both sides on this question Here as you getting out and Ego John Half temps in the rescue of him now, everyone to bite you on both sides as you get it. You know, tickled Joe l plus two over and from here I bring everyone to the left inside. If I am, the air included two over him isn't implies that the air square was echoed. You do, and therefore I should get now must EKO jobless I minus squared. And that too. And because I and it's no increasing and ah iso is is you could you two already and we see that it cannot be negative here as well and is always quantitative here. Therefore, we should get only the blessed now. So that's where we the answer and we could you describe to

The general Deep ocean. You're in this question is minus two six rippin minus 54. So on so forth. Okay, so we have to find out the fifth time. Time of signals. Right? So that really actually minus two on the common defense are common ratio are will be 60 100 minus 200 miners quit. Okay, so the combination job So the foot from a five g e. R. S to power fight dryness. Toronto is minus two in tow. Artist minus three is too powerful for the official. Provided is coming on B minus 10 It. Okay, so this is the full term of the given geometric progression. Oh, it's so weird that it's time for a m E artist to about minus, huh? You already? How? That is minus two. And the artist minus three is to God m minus one. Okay, so this is the next time all the some articulation. So this large resolution for this was she

Okay, So for this problem, we're letting our set and be the number of regions. Annuity is surface of a sphere is divided by end great circles. So what that means is, if we have our sphere, when a plane intersex it, it runs through the center. It's gonna intersected at a point that creates a circle or on the surface of create a circle. It's a great circle, because as long as the plane runs through the center of this fear is the largest circle possible when a plane intersex it so the plane would intersect closer to the bottom. You could also get a start over a smaller one. Okay, So, for example, if we have this one plane in there well, once intersex is under sex, uh, this circle the surface is not divided into two regions. All right, but say we add another one case. Let's have a another plane intersect here. Well, now the the surface is in four regions. Okay, let's say we had 1/3 1 So now we're gonna one more, and that's that's even just let it be this sort of vertical intersection. Okay, so they're great circles this winter on the edge. So that means we have four in the front and four in the back affectionate space. We have say this one in the back here, but it would correspond with this wedge in the front so that there's two and same free cheese. Other panels, the sister of the idea of how these these numbers are growing and relating to each other. So how do you represent that? It is really the big question. So if we consider the number of regions from the previous step, let's just let our and minus one be the number of regions from the N minus one. Great circles. So previous to the blue circle, it would have been four. Only draw our next great circle. It run through the previous ones at two points, right, So ran through the green one here, two points and it ran to the red one here at two points. So it's gonna the end the great circle past twice through each of the end of minus one regions. Okay, that means the n minus one regions will be divided into three regions and become three times and menace one regions. Okay, so that's so says the R N is equal to three the n minus one regions. But what's really happening is that hey stayed. Our previous regions are increasing by two times and minus one. Okay, so a recursive relationship takes the previous one and looks at how it's actually just increasing it by two times and minus one. And so, for instance, if we take that blue line, for example, the previous number have been, and in four we add to it, too. This is our third great circle. Says would be three minus one, which is a total of eight, and that does check out with if we just buy inspection, add this. Okay, so it's a good sign for our little formula here. Okay, so do you want to consider the initial conditions? So when we had a sphere that just had the one circle right, we got two regions. And, of course, when we had get this fear with zero great circles. Okay, then you are just going to have no divisions, and it will be one as your answer. Okay. And so that takes care of part, eh? Concern now. And the question is, will let's find our n using it oration. And so we'll start with what we derive for R N, which, of course, is our to the on a minus one plus two and minus one. Okay, so that we can consider going to spray this all a bit further. So what about what is art and minus one, then? Well, Arthur and minus one is equal to Artie and minus two plus two. That's and minus two. And then we have to add the two times and menace water from both sets two times and minus one. Okay, so we're gonna just put in the value for what are seven minus two equal. Okay, so that equals R the M minus three plus two, the n minus three. And then we're gonna carry this second partial part of the equation down. We have two times and minus two plus two times and minus one. All right, so in the pattern is becoming clear, okay. Says that eventually is gonna equal aren't one plus two plus all the way up to the to the N minus one. Okay, this is really gonna be equal to and are one is just call we, but it up. That's just equal to two. So this is gonna be equal to two plus and from an minus one some, So yeah. Kay, go zero two k. All right, well, this does that nice week, actually. Simplify it even further, okay? When he use use the fact here that the sum from HK equals want on a K is equal to end times and plus one over two twenties. That little fact here and simplify this a little more. So first, we're gonna just pull this two out of the some sort. Indeed, Two plus to do the sum cable zero and minus one of K. They won't put this in and get that That is equal to two plus two times and minus one times n over two. And you're You think those don't look exactly the same. But it's because of of the difference here in our range, Casey to account for that, never in a space will move on to the next page. But that will simplify into two plus and minus one times and which I think looks fine the way it is. But depending on well, they're not. You want to continue simplifying? It could be two minus and plus and square cancel federation. You could get that our span is equal to to minus and presidents.

For this problem, we have been given five different sequences. Each sequence is defined by a recursive relation with an initial condition. So it's enough information to get us started on our sequence, and we need to find the first five terms of the sequence. So let's begin. Let's do the very first one says my eight to the end is going to be six times eighth e n minus one. We're eight to the zero equals two. So our first term is to we've been given that now are recursive definition says to get to the 10th term I take six times the previous term. So to get to a sub one, I'm gonna go to a sub zero, which is the one already have here Time six. So it's gonna be two times six or 12 now to get to that third term where a is a sub to I take six times the previous one a sub one, so six times 12 will be 72. And again, I just keep multiplying each successive term by six. So those are our first five again. We can keep going. This sequence doesn't stock with five terms. That's Justus faras, we need to go for this particular problem. Okay, let's go on to be this time a Saban equals a sub and minus one squared, and we're told that a sub one equals two. So first term is to to get to the 10th term. I take the prior term, and I square it. So a sub two means I square ace of one. Okay, I've got a sub one is too. So I'm going to square. That neck gives me four. For the third term. I square the second term 16 for the fourth term. I square the third term 16 squared is 2 56 and then I square to 56 I get 65,536. Hey, what about number three here? Uh, this time I have a sub en equals a sub and minus one plus three times a sub end minus two. And so this case, they've told us that a sub zero our first term is one and a sub one is to. So we have given us the first two terms, and the reason they've given us to is because this recursive definition looks at the prior two terms. So to get to the third one, which is since we started with a subzero to get a sub to I'm going to take a sub end minus one. So ace up one plus three times the two prior one a sub zero. So to plus three times, one is going to be five. Okay, Now, let's get to that. That fourth term, a sub three. I take a step, too, which is five plus three times a sub two sub one, which is to So it's going to be five plus three times to or 11. Okay. And the last one, we're gonna take 11 plus three times five again. We're going back to different spots each time. And that gives us 26. Okay, Number four a Saban equals and times a sub n minus one plus and squared times a sub minus two. Okay, so, again, this one because we have an n minus one and and n minus two, they have to give us two numbers to start off with, and they dio they both are ones to begin. So let's take a look at what we get. This is a subzero name sub one. So a sub to this one right here. I'm going to take two, because that's the value of n times the previous one. So two times one okay. Again. And it's too. So two squared is four times their entry to previous, which is also one two plus four is six. Okay, how about the next one now and is three. So I have three times the prior one, so it's gonna be three times six plus and squared since then is three. That's nine times the entry to previous, which is one. So I have 18 plus nine, which is 27. Okay. And our last one now and it's going to be four. So I have four times the prior one, which is four times 27 and square that 16 times two previous, which is six. And want to put all of that together? I get 204. Hi. So some of these you can do in your head fairly easily. Some of them it helps to write down the intermediate steps just to keep everything straight. Okay, last one. We have a cement equals a suburban minus one plus a sub n minus three Okay, so we're going back one and then three behind. So this case, they have to give us at least the first three, which they dio. We start with one to and zero. So this is a subzero ace up one. A sub too. So our next one is gonna be a sub three. So and is going to be three. I go back one spot, which is zero plus the +13 places back, which is one. So that guy is going to be one. And now, if Ennis four I go, one position back, which is one plus three positions back, which is to one plus two is three. So that is the first five terms off all five sequences in this problem.


Similar Solved Questions

5 answers
1 The h W presence Seleoltowlta E that apply: structural 1 8 oa W and 1| features know li 01 papuoq the allow electronegative on the V an answer? alcohol to oxygen oxygen atom atom No Idea exhibit Intermolecular hydregen
1 The h W presence Seleoltowlta E that apply: structural 1 8 oa W and 1| features know li 01 papuoq the allow electronegative on the V an answer? alcohol to oxygen oxygen atom atom No Idea exhibit Intermolecular hydregen...
5 answers
(10 points; per acre hus Eone spraying = Porson centein equipment section 5 insecticide must distbution] with of 2 pine forost randomly rented mean the number of selected cost of 55.00 5150. The To treat Ano diseased trees acre. per [ree. Let C denote dlacuaed trees are diseased trecse Find the expectod the total spmying sprayed with Find value of the cost of the variance cost the cost
(10 points; per acre hus Eone spraying = Porson centein equipment section 5 insecticide must distbution] with of 2 pine forost randomly rented mean the number of selected cost of 55.00 5150. The To treat Ano diseased trees acre. per [ree. Let C denote dlacuaed trees are diseased trecse Find the exp...
5 answers
1 Skctcn Need Help? (ind tn 1 1 1 ae givcn ask YQU toeti turn In this graph ) 1 1Sreton Need Help? On Dader points region 1 TDur instructor SCalccc4 Jolbau @tored by the aiver 0.1-010 1 1 111 1
1 Skctcn Need Help? (ind tn 1 1 1 ae givcn ask YQU toeti turn In this graph ) 1 1 Sreton Need Help? On Dader points region 1 TDur instructor SCalccc4 Jolbau @tored by the aiver 0.1-010 1 1 1 1 1 1...
5 answers
Question 40.8 ptprojectile that is fired with an initial velocity of 132 m/s is inclined upward a an angle of 519. It lands ata point -28 m lower than the initial point. Calculate the time of flight
Question 4 0.8 pt projectile that is fired with an initial velocity of 132 m/s is inclined upward a an angle of 519. It lands ata point -28 m lower than the initial point. Calculate the time of flight...
5 answers
725 435 38 0 4X
725 435 38 0 4X...
5 answers
Sketch Bode plots for the following systems: St2 tf = (Also write the sinusoidal steady state solution of this system t0 the 82+20 $ input 10 sin (2 t).) s+1 tf = (s+10)(s2+s+100)
Sketch Bode plots for the following systems: St2 tf = (Also write the sinusoidal steady state solution of this system t0 the 82+20 $ input 10 sin (2 t).) s+1 tf = (s+10)(s2+s+100)...
5 answers
Draw the Lewis structure for each of the following compounds. The carbon atoms are central in each one.(a) $mathrm{C}_{2} mathrm{H}_{6}$(b) $mathrm{C}_{2} mathrm{H}_{4}$(c) $mathrm{C}_{2} mathrm{H}_{2}$(d) $mathrm{C}_{2} mathrm{Cl}_{2}$
Draw the Lewis structure for each of the following compounds. The carbon atoms are central in each one. (a) $mathrm{C}_{2} mathrm{H}_{6}$ (b) $mathrm{C}_{2} mathrm{H}_{4}$ (c) $mathrm{C}_{2} mathrm{H}_{2}$ (d) $mathrm{C}_{2} mathrm{Cl}_{2}$...
5 answers
What is the slope of the line tangent to f (x) = X33x2 + 2x 4at the point (1, =4)?
What is the slope of the line tangent to f (x) = X3 3x2 + 2x 4at the point (1, =4)?...
5 answers
5. What are the solubility rules for common ionic compounds in water? 6. Balance these reactions and classify it: a. The combustion of decane (C H forms water and carbon dioxide b. Magnesium metal reacts with iron (III) oxide to form magnesium oxide. 7 . What reactant must be present in order for a reaction to be considered a combustion reaction?
5. What are the solubility rules for common ionic compounds in water? 6. Balance these reactions and classify it: a. The combustion of decane (C H forms water and carbon dioxide b. Magnesium metal reacts with iron (III) oxide to form magnesium oxide. 7 . What reactant must be present in order for a ...
5 answers
In Exercises 17–38, use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola’s axis of symmetry. Use the graph to determine the function’s domain and range.$$f(x)=(x-1)^{2}-2$$
In Exercises 17–38, use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola’s axis of symmetry. Use the graph to determine the function’s domain and range. $$ f(x)=(x-1)^{2}-2 $$...
5 answers
12. Determine the equation of the polynomial function shown in the graph below: The curve passes through the point (3, 12/. Write the equation in its factorized form:(x) = ax} bx? 2x + 12 The curve defined by the function intersects the X-axis at three points_ axis at three points: Two are known, and -3 Determine the equation of the function_
12. Determine the equation of the polynomial function shown in the graph below: The curve passes through the point (3, 12/. Write the equation in its factorized form: (x) = ax} bx? 2x + 12 The curve defined by the function intersects the X-axis at three points_ axis at three points: Two are known, a...
2 answers
You are conducting a test of independence for the claim thatthere is an association between the row variable and the columnvariable. X Y ZA46 6 52B39 10 28The expected observations for this table would be X Y ZABThe resulting Pearson residuals are: X Y ZABWhat is the chi-square test-statistic for this data? χ2=
You are conducting a test of independence for the claim that there is an association between the row variable and the column variable. X Y Z A 46 6 52 B 39 10 28 The expected observations for this table would be X Y Z A B The resulting Pearson residuals are: X Y Z A B What is the ...
5 answers
Collide and what is the rotation ab terms of qu the diagrar your work
collide and what is the rotation ab terms of qu the diagrar your work...
5 answers
Question 26 (2 points} What is the molarity of solution that is prepared by dissolving 5.467 sodium chloride in 150.0 mL of water?
Question 26 (2 points} What is the molarity of solution that is prepared by dissolving 5.467 sodium chloride in 150.0 mL of water?...
5 answers
With R = 0.06 m Add a screen shot of the Logger Pro plotMagnetic Field from a Wire Lab2dFieldLabQuestRaLadCH 1 Magnetic Field 21.14pTLounor !Ztitcl;Distances (cm)eCONNECTED SCIENCE SYSTEM Field StrengthLocation of Field SensorDirection (Conventional Current)CurrentChange t0 Electron Flow6.3 AI(A)1.52.83.44.45.66.37.1B (pT)0.004.889.2211.1814.6218.6421.1423.63
With R = 0.06 m Add a screen shot of the Logger Pro plot Magnetic Field from a Wire Lab 2d Field LabQuest RaLad CH 1 Magnetic Field 21.14pT Lounor ! Ztitcl; Distances (cm) e CONNECTED SCIENCE SYSTEM Field Strength Location of Field Sensor Direction (Conventional Current) Current Change t0 Electron ...
4 answers
(18pts) Give the general solution of the equation Y" + 2y' + y = 0 Give the form of the particular solutions (but do not solve for the coefficients!) of y" + 2y +y = 3e2t + 5e-t + 3.
(18pts) Give the general solution of the equation Y" + 2y' + y = 0 Give the form of the particular solutions (but do not solve for the coefficients!) of y" + 2y +y = 3e2t + 5e-t + 3....
5 answers
~I+clyXoMcT : meinioJnmmn JaEET Gtthi Soronmr gion (7itiz| MAlid nmrim & [05,4,13,32D0}Ramacu-icenns erontFunoMnehina Esescacimz Dices20420314481.9717373FZTI1350d
~I+cly Xo McT : meinio Jnmmn JaEET Gtthi Soron mr gion (7itiz| MAlid nmrim & [ 05,4,13,32 D0} Ramacu -icenns eront FunoMnehina Eses cacimz Dices 204 2031448 1.971737 3FZTI 1350d...

-- 0.019497--