5

(10 = points) Let g: R ~ Rbe a function where g(x) -/ points) If A = {xl1 < x < 4} find g(A). points) If f: R 7Ris function where f (x) = x2 + 1, find (f + g)...

Question

(10 = points) Let g: R ~ Rbe a function where g(x) -/ points) If A = {xl1 < x < 4} find g(A). points) If f: R 7Ris function where f (x) = x2 + 1, find (f + g)(2), (fg) (2), (f g)(2) and (g f)(2). points) If € = {~9,-8}; find the set D = {x € Rlvx((x € D) ~ (g(x) e c))}:

(10 = points) Let g: R ~ Rbe a function where g(x) -/ points) If A = {xl1 < x < 4} find g(A). points) If f: R 7Ris function where f (x) = x2 + 1, find (f + g)(2), (fg) (2), (f g)(2) and (g f)(2). points) If € = {~9,-8}; find the set D = {x € Rlvx((x € D) ~ (g(x) e c))}:



Answers

For the functions $f(x)=3^{x}, g(x)=\left(\frac{1}{16}\right)^{x},$ and $h(x)=10^{x+1},$ find the function value at the indicated points. $$g\left(-\frac{1}{2}\right)$$

It was well, even F Thanks, Coach. In a tree about X and going to find a ever managed to do so. It means that what you need to let their minister in. Judah. Thanks again. That three bowel minus two. So again I go to one of ah, three square And could you want overnight?

Three a minus one Upon a squared minus seven A plus 10 on D A This of suit X with eight a minus one upon a Squire minus four plus toe. A bless one upon a esquire minus three. A minus 10. Not just give them that F A. It was still here. No random l O f A, which is three a minus one upon a esquire, minus one. A blessed 10 equals toe a minus one upon a is far minus four plus a plus one up on. It s quite a minus. B a minus 10. No fact lies the denominator. So it is quarto three a minus one upon it is quiet minus Why? A minus to a plus. Dead. Did you meet up a split? You go to a minus one upon a plus two a minus two. Bless to a plus one upon effect. Lodging. This is called a Esquire minus five. A bless a minor step no. Again. You will find three A upon each common here. So a a minus five minus two. Come one a minus five de Quito a minus one A born a minus two and a plus two bless a plus one upon a common here in this, a minus fight again. We can take us to come on over here. It could be minus. Fight some more ahead. This is three a upon a minus five A minus two equals toe a minus one upon a minus stool and a plus. Two plus two a plus, one upon a minus five on a plus two. Now let us find the below. A part which denominator Iggo. So your nominee Joe at a Quito equals five and a Quito minus two. So these are the Delaware denominator. You just rule out this fellow. If answer comes 25 and minus two, that will not allow. That is not answer. No. Move ahead and with Elsa ob denominator. So, Elsom Oh, denominated! It's a minus Stool a plus two and a minus. Fight normal supply. With this, no mental and you'll find it is equal to three times a A plus two If we're a minus one a minus five quarto plus toe A plus one times a minus two. No, he was just wouldn't lie here. This is three a Esquire. Let's six. It will go. A Esquire minus six. Yeah, plus five. And this world. Good food a square. Multiply this to a Esquire minus four A plus a minus two. Normally ahead, this is a leper. Inside three A square six a right inside a square. Best way square It is square minus six. A minus for a which is minus stand A blessing minus nine A on five and minus two, which is a little blast. Three now three a square, three a spare. Cancel each other if nine comes labrum Side six A plus nine A equals three, combining like terms So 15 a equals toe three A little three by 15 35 Job teams ableto one by fight. So this is answer.

In this problem. We have two functions. Aftereffects equals 10 minus X in G of X equals the square root of X. So, in part, a first part of the problem we need to evaluate the function f composed of G a value of one F composed G of one could be rises to equal f of g of one on the inside of F f composed of G of one. And in this we equal f off G of one being square root of one will put one and for X in g of X to get the square root of one, I swear it of one simplifies toe one. So we have f rooms. F of one g of one becomes one so need evaluate f of 1/2 of one. But this in black half of one equals tan minus one or that equals nine. So in summary function F composed of G of one equals nine. Let's go to part B. This problem Part B is similar, but a little bit different. We need to evaluate the function G composed of f of one this time. So this time the outside function is G in the inside function. His F evaluated that one. Or in other words, the output from F of one would equal the input into the function g to this equals G of f of one f of one being 10 minus 1 10 minus x with X being one. This becomes G of 10 miles. One becomes nine Any violent G of nine just a square root of nine, which is equal to three. So in summary function G composed of F at one equals a value of three. It's going to part C part C. We need to find an expression from function f composed of G of X. We're not gonna find a number of this time. We're going to find an equation or expression for the function f composed G of X right, and this really equal f of the function G of axe serving US input into the outside function of death. C equals F of G of X g of X, being the spirit of X to be substituted. Spirit of acts in four x and f of x This week equal 10 minus x or 10 minus the square root of x. This time the expression 10 Minus the root of acts. Square root of X is the expression for the function. F Composer G of X And finally, let's go to part D part. Do you need to find expression for the function G composed of F of X or, in other words, G of half of X on the inside Z equals G of f of x f of X being in black 10 minus x the expression 10 miners Expert service input into the function G So this equals the square root of the input 10 minus x That is our expression for the function g.

We live in the ocean tree. Thanks. Because you won over 16 power. Thanks. And we want to find that she off the man is gone and force you get what you need to play. The money's one into the X. You begin the 1/16 power minus one, and here an extended accordionists extend here.


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