To draw stereo ice murders of a molecule with the formula C five age 10 with a double bond. Since it's an AL Keen, we will draw, Um, a few of the molecules will be a five carbon chain with a double bond in different spots. And then we will also have some four carbon sheen's with medical groups, attach to different places and all center changing television of our double bonds. And then, after we do that, we can determine which compound will have a system trans face murder. So pressure will start with a simple far Kurban Shane Well, but the double bond between Kerman one and carbon, too. The lines were present, the hydrogen, and they will look like this. This gives us 10 hydrogen and five carbons and a double bond. Next, we will have a wide carbon chain again. Instead of putting the double bond between carbon one and two, we will put it between carbon two and three and again add, uh, lines to show these hydrogen. And again we have five carbons tonight. Virgins. Now, if we move for our next compound people to stuff a bond between carbon three and four, it will be the same as this compound here just looked around. So instead, we're going to do it for carbon chain with out of a bond between. Carmen wanted to and we'll have a metal group. Put it here and then are the hydrogen. That's one option for our four carbon sheen. Another is we can have the method group here again, but put the double bond in the middle between, um, thes two carbons and then out or hydrogen in. The last option is to have a for carbon sheen and put the metal group here and another one over there. And this gives us five carbons and and 10 hydrogen. So these are the possible story I summers of a compound with this formula, and of these ones we can determine which will have a sister and by summer's. So the answer is this 2nd 1 here. Since the carbons attached to the double bond, both of them have two different groups on each of the carbons. So this car on the left is attached to a hydrogen in the metal group, and the carbon on the right of the Taliban is attached to an ethyl group. You know the hydrogen, all of the other compounds? Um, I cannot function in trans I summers. For example, this 1st 1 here, carbon on the left of the double bond is attached to hide regions. So since those are identical, none of them have priority. And the same goes for the rest. So the only one that confirms his entrance I summers, this is second compound here.