5

Determine the volume enclosed between the hemispherical surface ~ = f(t,y) = ~ = 0 plane by evaluating the double integral FRr f(z,y) dA polar coordinates Give an e...

Question

Determine the volume enclosed between the hemispherical surface ~ = f(t,y) = ~ = 0 plane by evaluating the double integral FRr f(z,y) dA polar coordinates Give an exact value_ V = [4 points]22 y2 and the

Determine the volume enclosed between the hemispherical surface ~ = f(t,y) = ~ = 0 plane by evaluating the double integral FRr f(z,y) dA polar coordinates Give an exact value_ V = [4 points] 22 y2 and the



Answers

Use polar coordinates to find the volume of the given solid.
$$\begin{array}{l}{\text { Enclosed by the hyperboloid }-x^{2}-y^{2}+z^{2}=1 \text { and the }} \\ {\text { plane } z=2}\end{array}$$

For these two guys are intersecting. So you see, this is two ax squared. Plus two squared is equal to six. So the X squared plus y squared is equal to three. R squared is equal to three. So ours equal to rat three. And we're taking only the positive coercion because we're in the first often Teo R R is going to range like this. And if we're in the first often were only ranging from zero to pie over too. All right, so right. We can rewrite thes can rewrite Z as equal to one plus two r squared and Z is equal two seven. Okay, so one of these is above One of them is a bolo. And it's not too hard to see that we can rewrite our into girl like this. The plane is above this. Is Purab Allied good and we've got d are already already. Okay, so again, this doesn't depend on data. So we can just do this into girl really quickly. Seven are minus r minus two R cubed d r So integrating this we're just rewriting it. We can get or answer so that three r squared nice to over four are to the fourth from zero to ride three. Okay, so when we plug in Right three, get nine minus. Let's see. Is going to one half. Ah, So, three, Let's see. Is going to be believe eighty one here. So I'm sorry. No, that will not be anyone. It is nine. Okay. So that high over two times nine over to nine. Over. Full nine pi over four.

You want to find the volume bounded by this parable, Lloyd? Uh, and the planes equal seven, which is the light blue plane up here. But only in the first auction. I have a drawn all the way around. Okay, so first, let's switch to polar. So the, um, problema ideas equals one plus two are square and the plane Z equals seven. Okay, so we're gonna have these pieces so they're gonna be bounded on the top by seven and bounded off the bottom by the parable Lloyd. And then we're gonna look in the first OC tent, and so we're gonna look at what, This circle of intersection down here in the first OC tent. So we're gonna set, um, equal to each other. Seven equals one plus two are square, so six equals to R squared. So R squared is three. So are is the square root of three. Alright, so here's what we have. So we're going to go zero to pi over two zero to the square root of three. Because we're coming out like this. Uh, top minus bottom. Already already. Fatum so is your in a pi over two zero to this word? of 37 minus one that six. My Let's do six are minus two are cute, the R D theta. Okay, so we get zero pi over two six r squared over two. So three r squared minus two are to the fourth over. Four. So are to the fourth over to zero squared of three D theta. So is your the pirate or two square to three square? There's three that's nine minus nine halfs d theta. So that's nine halfs data from zero power to so nine pi over four.

So in this problem, we're gonna be solving for the vault. Um, it is not above the surface of our first equation. Z is equal to our science data below the X Y plane laterally by X is equal to zero and also by R is equal Teoh three sign Vegas or last um, equation. And also ah, quick note is that this is in the first OCD. And so we have three equations that are gonna help us solve for R double integral equation for the volume so that we can solve for our volume. The first thing we're gonna do is solve her Are we know that our X is equal to, um, zeros. We have zero is equal. Teoh are co sign data. So then we have a value of our that is equal to zero on were also given already at the top that R is equal to three sign data. So we have our two values for R and now we just have to find our values for data. So because we were to get this, we have three sign data is equal to zero. Those are to our values. So then we would have that the sign of data is equal to zero on but have the sign of negative one of zero equal to Fada on Sign is equal to zero in a couple of points of scientists equal to zero. Um, zero pie and two pi were in the first often too, though so we know that it's going to be 0 to 1 have played a is equal to zero on If we were to manipulate some of our other equation swell and we were just bring in our our execution with our co sign on our, um we would have our are zero is equal to our coast. Fada and, uh, plug in for our r and have zero is equal. 23 sign Khost Fada zero is equal to our sign coasts. You know, we already figured out our values for one sign is equal to zero. And our values now always should look at or when our values for one co sign is equal to zero and so co signing is equals would have coasts negative. One of zero is equal to fade out. So when data is equal to high over to on three qy overture and So we're in our first often. So we know that this is gonna be when faded is equal to pi over two. So we have our bounds here, Um, on we can use this information out of form our equation. So and it just right out our Interpol's and we're gonna have Our fate is from zero to hi over to, and we're going to have our ours from 0 to 3. Sign data. We were already given an equation for Z, which is are our sign Fade us. We can just place that end. And we also that this is going to be times R d the DRD data on now from here just going and brackets so that we can just start solving for our our equations. We're gonna have r squared sine. They'd, uh, um just know our skirt d r. And then our son data is going to be out here. Do you eat up on? So the integral of r squared is just equal. Toothy enter is equal to r cubed over three. So we're gonna have our cube over three, so we don't need that ended only one from 0 to 3. Sign data times are a sign Veda be data and I like it's gonna be filling in, so we're gonna have three sign cute over three minus zero. Cute over three that all of this times sign beta d data. Oh, and this is just gonna be equal to zero. So this is just one across out. So we're gonna have, um, nine, not mine. Sorry. 27 like 27 times side cubed over three, we will have nine. But first, let's, uh, just to each step, visually to of nine. Um, sign the fourth Data de Beta, and we can just take out our nine in our next step. And we're also going to now separate sine squared data sine squared data D sita. For that, I'm gonna just show us the equation we're gonna use. So there is a handy, um, trick equation that we can use, which is that the no sign of to ada is equal to one minus two sine squared data. So from this, we know that sine squared data is just equal to Lana Dynasty Co sign to data over to, and we're just gonna plug this and for r sine squared values from zero to pi over two of one minus the co sign of two fajita Go for two times one minus Nico sign to fade up over to Di Stato to And actually let's take out our 14 because we have to. What has thus everyone four that we can take out missile make our lives easier Would just be left with one minus co Sign of to Clayton Times one minus that co sign to Leda D beta over two. And now we're gonna have one minus to co sign to date after data plus co sine squared to Data de Data on do you have night of four from Sierra two Pi over two. And we're going to just actually make a big fashion from zero to pi. Over two of one Di fada minus two times the interval from 0 to 2. Pi it over to co sign to data plus the integral from zero to pi over two of co sine squared off to data. Will do debater there. Sorry, I'm missing a D data. That's a plus. And now we can do the integral. Um, you could be the first interval which is going to be so one deep data, the integral of that is just gonna be cool to data. And that is gonna be minus two times the go from zero to high her to co sign of to Stato di Fada plus the integral from zero high over two. And we're going to rewrite this, um, last question before we put it in. So as we had seen up here, we have that formula. There is another formula with co sign. So there is a formula that says that the coastline of to data is equal to two times a co sign squared a data minus one. So because we have Teoh Veda up here, what we're gonna do is we're gonna say we have an X for a sabbatical to to data, and we're gonna just have this is the co sign of two X is equal to to your times coast and squared X minus one. So the coast selling to facts plus 1/2 is equal to co sign Squared X. Now we can just substitute in for our X values. One of the co sign of two times two seda plus one over two is equal to the co sign squared of to data. Andi, while we're here, we can also, um, do are you substitution of a growing need here? So we're gonna have the co sign of two beta, and we're gonna say that to say that is equal to you. So two D data is equal to do you so d Seita is equal to d you over Andi. So appear first that we can plug in for our equation. So we're gonna just look in this and to our equation. So we have the co sign up for data spawned over to D Favor on Now. From here, we can also look in our u um, values. So we have 9/4 times. Beta Scranton's here a little over two minus to Thomas the integral from zero to pi over to co sign you, Do you over to. Plus, we can take out or 1/2 year you will have the ah into go from zero to pi over two of co sign for theta plus one de. And now you can continue can. With this, we're gonna have our data from zero to high over to, and we can cross out or twos here, Just get out and have a negative. Um and we could actually thought for integral. So we're gonna have the coastline of you, D you interval of that, Which is just sign. So we have signed you from zero two pi over two plus 1/2 and I were going to split our last integral. So we're gonna have the integral from zero to pi over two the co sign for Data de Nada, plus the interval from security pie over to of one de Feydeau. And all of this is times 1/2. So now from here, we can do a u substitution or to be able to solve for this, but in 70 substitution, let's do a V. Um, just so we don't get computer that other you. So we have the is equal to fourth ada. So Devi is gonna be equal to four de theater. Said d The over four is equal to D data, so we can plug that in. Um, it's gonna have 9/4 times data from zero to pi over two. Sign of you from zero to pi over to plus 1/2 all times. The integral from zero I over to of co sign off the D. V all over four. Plus, now we have the integral off one D data, which is just gonna be equal to data so we can say beta from zero to pi over two. Ah, now we consult for our last integral. So just writing out beginning part of our equation? Yes, we have our 1/2 times the integral of co sign V DV over four on the coastline of B D. V. Over four is just equal to be Stein of the over four. And this is from zero to pi over two. And we have plus data from zero two pi over. Jim. Now all that's left to do is to plug in our diocese for you envy. And then we can start looking in our actual values. So view is equal to two with data and B is equal to fourth data. In case you forgot that Natalie have 9/4 10 state, often zero to pi over. To sign up to data from zero to pi over two us. I have all times Sign of four data over four from Syria, plus data zero hyper Joe that in a rocket. And we have to have another bracket for the just start playing in our values. We have 9/4 have status. Privatise 35 minus zero and 80 minus Theo Stein of two times by over two. Kind of two times zero plus 1/2 all times The sign for times Pirata all over, four minus thesis. Sign off four times zero before plus hi over to minus zero. Okay, so cross that are zeros. And the sign off two times two is just equal to the sign off high. She secret zero service crosses out signing zero time of two times. Here is equal deciders years. This is crosses out zero on the sign of four times pi over two is equal to sign of two pi, which is equal to zero. So this crosses out and the sign of four time zero is equal to decide of zero. So this is equal to zero, and that crossed us out. So we are left with over four i over to plus long, huh? Kinds that pie for tip just equal to nine over, plus pi over or just equal to, Not over four times to I over plus high before or which equal to 9/4 times three party over. Or she's people Teoh, 27 pi over 16 and that our value.

Hi This question. We have to find the volume of the solid and forgiven, um, that the volume is within this surface and it is outside of this surface. So the first thing we should do is, um we're going to make this equation be equal to R R um, so that we can graph it. And then we're also going to have Teoh later on make it equal to see if we have an equation with our our within it in order to put that into our double integral. So we would have our squared plus Z squared. It is equal to four run off r squared is equal to for minus Z squared, and we're going to have the square root of r squared is equal to for minus Z squared. Skirted that, um, one of our is equal to four minus the squared in the square. Rich. So what this is going to look like is something like this? Um, it's going to be from are 22 or two all the way around Andi. So for our second equation, withdraw with that one's going to look like on that one is going to look like, um it's gonna be about like that all the way around there. And so we want the area that is within our larger image or surface, but outside of our smaller ones. So we want all of this. And so we know that our equation, our first equation that we're gonna be using is going to be our smaller equation. That is going to be our lower bounds. So are are for our lower bound is own. Just say L b for a lower bound is going to be equal to two Khost data. And for our upper bound, we know this goes to to for our larger equation. So we're going to say our upper bound is going to be equal Teoh too, And, oh, so from here, all we have to do is figure out what our data values are going to be. So the first thing to note is this is a graph and polar coordinates. So is a little different from a graph. Um, like the X y plane. So the difference here is that this is equal to when I write this in black. This is equal to pi over two. This value and this is going to be equal to pi. Actually, not too pie. Um, for our equation, R is equal to two coast data. We could see that. So what that means is that this is equal to pi because at this point, so we know that we would have zero when coast is equal to pi over two. So that makes sense, right? Going, um, into this are and then ending here. But this is going to be high now because we would be going to 1 80 degrees, which is like this. But at pie, when coast is equal to pi, we get a negative one. So that changes the direction to be going this way. And we know that it's going to be a two out front, so we would have a positive two. And so that's how we know that this is pie and not too pie in this case. So our bounds is going to are going to be, um, for our so you know, from zero Teoh. Hi. So we're gonna have data is greater than zero, but it is less than pie. And that organ those are gonna be are bound. So now we can change our equation to where we have our rz, Um is going to be equal to some things Were gonna have r squared us Z squared is equal to four. And so we're going to just subtract r squared from both sides. So we're gonna have negative r squared on. Now we're gonna just take the square root of both sides, and that is equal to zero. So that is our creation that's going to be going into our integral. So we're going to have two into girls here. We're gonna have the integral from zero tau pi and the integral from two coasts Seda right? And then to to and we're going to have the square root of ar minus R squared r d r d vada And that is going to be our equation that we're gonna be solving. So I'm just going to rewrite this with rockets around our part that Onley deals with our and from there we can solve or start trying to solve for our equation, we're gonna have to do a bit of a manipulation with this, so we're actually gonna have to do a U substitution. So we're going to have Are you is equal to four minus R squared. So our d you is going to the equal to negative to our You are so r d r is equal to d you over negative to our and now we're just gonna plug this into our equation. So we have ours our first, uh, integral from zero to pi. And then we have our second from to coast data to to and we have our now square root of you. Times are times D you over negative to our and close our brackets with R D you on the outside and now we can cross out are ours. We can take out our negative one half You could take that are completely actually. So it's just out of our way. Andi from here we can solve for the integral So the integral of the square root of you. For that, what we're gonna do is we're using equation states that the integral of X to the N is equal to X to the n plus one over n plus one, and so you to the one half is equal to the square root of you. So we're going to have you to the one half plus 1/1 half plus one. And this is from two coasts Data to And of course, we have our D data out there. And this to being equal to you to the 3/2. Over 3/2 from two coasts. I stayed out to two D data Onda. Now we can take out our denominator by multiplying Are negative one, huh? By 2/3 Onda, we're going toe also now plug in for are you? So are you is equal to four minus r squared. So we have four minus r squared. We can plug that in so we're going to have four minus r squared to the 3/2 from two coasts data to to de Seda. And so we can, from the outside here, run across out our shoes. I'm going to be left with negatives one third and now we can plug in our values into our are. So we're going to have four minus. So now when R is equal to two, so two squared and we're going to have three to the fourth and then that's gonna be minus war minus two coasts data squared and that's going to be to the three over to de Vita. And so this is just going to be able to four minus four, which is equal to zero. So that's gonna cross out. We can take out our negatives, have one third and the interval from zero to pi of four minus four coasts squared data to the three over to D data. Andi from here we're going to do is we can take out four. So we're gonna have that and Weaken. Take out our four from that equation and just have one minus. Our coasts squared, and the square root of four is equal to two and two. Cute is equal to eight, so we can take that out. We're gonna have 8/3 out here, and so we're just going to have one minus the coasts. Two squared, Q B three over to D data. And from here, what we need to do is we're gonna plug in an equation for Coast two squared. So there is a trick function that states that. Sorry. Wrong. One, um, coasts of two Fada is equal. Teoh two coasts squared. Fada minus one. So are coasts squared. Fada is equal to the coast to Fada plus 1/2. We're just going to plug that into our equation. So we're gonna have 8/3. Central from zero to high of one minus Khost two Fate a plus one all over to Andi again. This is 3/2 and we have our d Seda. And so we're gonna three and zero to Hi. And we're going to have one minus the coasts over to data over to Klaus, actually minus one half three over to Di Fada. And now we can just simplify what? Which is just going to give us Ah one half minus the coast of to data over two. So that's just one minus the coasts of two data over to to the, uh, three over two. And so there actually is an equation that is exactly this. So there's a trick function that states that the coast of to data is equal to one minus the to sign squared data. So the sign squared pita is equal to one minus coast to data over to. So we're just got the plug that in and 8/3 from the integral from zero to pi of sine squared state, uh, the three over to defeat data. So of course, our square is just going to go away, and we're going to now be left with, um, and to go from zero to pi of sign cubed data D data. And so from here we're going to do is we're going to separate our signs into the sine squared data on sign state us with D data from 0 to 2 pi to a start, zero to pi, and we're going to plug in. Um, so there's an equation that states that one is equal to the sine squared data plus coasts squared data. We're gonna plug in for that. So we're going tohave birth three from zero to high, and we're going to have one minus coasts squared Data sign Theda D Data. And from here, we're just going to have the sign of they'd ah minus the coasts squared. They'd a sign beta d data. And now we're going to just split this into two. Integral. So all of it's going to be times 8 to 8/3. Sorry. Um, and so we're gonna have sign state, uh, integral of that. Minus the integral of coasts squared of this hesitancy Fade up. Sorry, um, squared sign data D data. And so from here, we're going to do a U substitution. Um, so we're going to have you is equal to coasts Seita. So our d you is going to be equal to the negative sign data D data. So d you over the negative sign data is equal to d beta, so we can just plug that into our equation. So we have our 8/3 times are internal hi, data d see minus are integral from zero to pi of ust's squared sine beta times. D you over the negative sign data we rate we ever did. So we're good. Um, And now we can cross out are negative sci fi. Then we can take out that negative and which is going to have a plus out here. So now we can actually solve for our inter girls. So the integral of, um, data is equal to, um negative coasts data. And this is from zero to high. That's going to be plus the integral of you squared d you, which is equal to you. Cubed over three from zero to high. And so from here, all you could do is plug in for our you and are you is equal to hosts data. And so we're going to have our eight over three times negative coasts. Data from zero to high plus coasts, Cube data over three from zero to potty. And now weaken. Just plug in for our values. So we're going to have eight over three of the coasts. Negative coast data a month. ADA is equal to pi. So coast of pie people to negative one. So this is going to be a plus one. Um, and then that's going to be plus, Khost equals I'm gonna just rewrite this so we have negative, and then this is going to be plus, so coasts of zero is equal to one, and then this is going to be plus, so the coast of, um hi is equal to one. That cube is equal to one, so it's going to be one over three, and that's going to be minus. I'm sorry, this is minus not a plus. Um, because it's the coasts of pi is equal to negative one negative one cubed is equal to negative one so we're gonna have negative one over three. So negative one third and this is going to be minus. So the coast of zero is equal to why Mr One Cube is equal to one third. So this is gonna be one third. And so we're gonna have 8/3 times. Que minus do over three, which is equal to eight. Over. Three of six over three, us to over. Plus, I'm sorry. This is a minus minus to over three, which is going to be equal to 8/3 times four over three, which is equal. Teoh 32 over nine, which is our answer.


Similar Solved Questions

5 answers
Bill and Sue and five of their friends g0 to the movies They all sit nert t0 each other in the same rOW How many ways can this be done if point ) Sue and Bill must sit next to each other?point Sue must sit in the middle"points) Sue sits 0n one end of the row and Bill sit s on the other end of the row?
Bill and Sue and five of their friends g0 to the movies They all sit nert t0 each other in the same rOW How many ways can this be done if point ) Sue and Bill must sit next to each other? point Sue must sit in the middle" points) Sue sits 0n one end of the row and Bill sit s on the other end of...
5 answers
To %in tne Ward Suncs, as208 team mus and Wlls4 games Qul ol maxim UM 5gamus:solve tne problem; Ilst Lhe posslb = arrangerrients Ossu8Howthurdwinnnatha Wiarld Sunnt aatlly Gntlowlnnern tram lasos thg fr3t game?WuysKmnwmutMy
To %in tne Ward Suncs, as208 team mus and Wlls 4 games Qul ol maxim UM 5 gamus: solve tne problem; Ilst Lhe posslb = arrangerrients Ossu8 How thurd winnnatha Wiarld Sunnt aatlly Gntlo wlnnern tram lasos thg fr3t game? Wuys Kmn wmut My...
5 answers
Use the Kruskal algorithm to find a minimum spanning tree for the graph G defined via V(G) = {a,b,€,d,e} E(G) = {ab,bc,cd,de, ae} @G (ab) {a,b} c(bc) {6,c} @c(cd) = {c,d} Dc(de) = {d,e} Dc(ae) = {a, e} and with weight function f {(ab,1), (bc, 2) , (cd, 2) , (de,1), (ae,4)}
Use the Kruskal algorithm to find a minimum spanning tree for the graph G defined via V(G) = {a,b,€,d,e} E(G) = {ab,bc,cd,de, ae} @G (ab) {a,b} c(bc) {6,c} @c(cd) = {c,d} Dc(de) = {d,e} Dc(ae) = {a, e} and with weight function f {(ab,1), (bc, 2) , (cd, 2) , (de,1), (ae,4)}...
3 answers
3-4Let 1 > 0, and let X],X2, with the probability density functionrandom sample from the distributionf(r;A )-A'xse-Ar}r>0We wish t0 test Ho:1 =H;:1 =Hint:Y = Xx; is a suflicient statistic for }Y =x} has Gamma( a = 3n. 0distribution_If n=4 find the most powerful rejection region with 0 =0.10.Suppose n =4 and12Find the p-value of the test
3-4 Let 1 > 0, and let X],X2, with the probability density function random sample from the distribution f(r;A )-A'xse-Ar} r>0 We wish t0 test Ho:1 = H;:1 = Hint: Y = Xx; is a suflicient statistic for } Y = x} has Gamma( a = 3n. 0 distribution_ If n=4 find the most powerful rejection regio...
5 answers
5.Convert the following Newman Projection into line structurepoints)CH;
5.Convert the following Newman Projection into line structure points) CH;...
5 answers
Sample of NO gas in a nonrigid container at a temperature of 115PC occupies = certain volume at certain pressure. What will be the temperature, in degrees Celsius; in each of the following situations?Both the pressure and the volume are cut in half:Temperatureb. The pressure is cut in half; and the volume doubled:Temperature
sample of NO gas in a nonrigid container at a temperature of 115PC occupies = certain volume at certain pressure. What will be the temperature, in degrees Celsius; in each of the following situations? Both the pressure and the volume are cut in half: Temperature b. The pressure is cut in half; and t...
1 answers
Integrate each of the given functions. $$\int \frac{p-9}{2 p^{2}-3 p+1} d p$$
Integrate each of the given functions. $$\int \frac{p-9}{2 p^{2}-3 p+1} d p$$...
1 answers
The control rod $C E$ passes through a horizontal hole in the body of the toggle system shown. Knowing that link $B D$ is $250 \mathrm{mm}$ long, determine the force $\mathrm{Q}$ required to hold the system in equilibrium when $\beta=20^{\circ} .$
The control rod $C E$ passes through a horizontal hole in the body of the toggle system shown. Knowing that link $B D$ is $250 \mathrm{mm}$ long, determine the force $\mathrm{Q}$ required to hold the system in equilibrium when $\beta=20^{\circ} .$...
5 answers
The population of California was 10,586,223 in 1950 and 23,668,562 in 1980. Assume the population grows exponentially.(a) Find a function that models the population t years after 1950.(b) Find the time required for the population to double.(c) Use the function from part (a) to predict the population of California in the year 2000. Look up California’s actual population in 2000, and compare.
The population of California was 10,586,223 in 1950 and 23,668,562 in 1980. Assume the population grows exponentially. (a) Find a function that models the population t years after 1950. (b) Find the time required for the population to double. (c) Use the function from part (a) to predict the popu...
5 answers
Find a function f(z) such that f' (2) 2e" 52 and f(0) = 3f(c)
Find a function f(z) such that f' (2) 2e" 52 and f(0) = 3 f(c)...
1 answers
Calclate2T (-4)" 22n sx neN Gn!
Calclate 2T (-4)" 22n sx neN Gn!...
5 answers
Submit Find #L decimal placcs: the length } Enter DNE 2*3 , Entcr your 1 5+4) Previcw whose 1 L cquation Not Exist; Hfor Infintty given by r 2.2172) on 0 Or4a culcuhlion (like 503 , 1 exactly 01 punox
Submit Find #L decimal placcs: the length } Enter DNE 2*3 , Entcr your 1 5+4) Previcw whose 1 L cquation Not Exist; Hfor Infintty given by r 2.2172) on 0 Or4a culcuhlion (like 503 , 1 exactly 01 punox...
5 answers
Find the solution of the differential equation that satisfies the given initial condition7V Pt , P(1) =Need Help?Road It Talk to _ TutorSubmit AnswerPractice Another Version
Find the solution of the differential equation that satisfies the given initial condition 7V Pt , P(1) = Need Help? Road It Talk to _ Tutor Submit Answer Practice Another Version...
5 answers
Analysis Date & Time 221/2020 7.53.59 PM User Name Admin Vial# Sample Narne 301-10 Sample ID 301-40 Sample Type Unknown Injection Volume 1.00 ISTD AmountData Name Method Nale Intensity 30000C: GCsolution CHEM 3[06 Spring 2020 Exp 30301130[-I0.gcd C:GCsolution DatalAmanda_lest Octgcm2000081000013minPeak# Ret Time Area Conc. UnitWark ID# Cmpd Name 1.891 896346 88.561 1.980 73098 7.222 2.128 1541 0.152 fV 2.645 2264 0.224 3.009 38868 3.840 SV Total 1012117
Analysis Date & Time 221/2020 7.53.59 PM User Name Admin Vial# Sample Narne 301-10 Sample ID 301-40 Sample Type Unknown Injection Volume 1.00 ISTD Amount Data Name Method Nale Intensity 30000 C: GCsolution CHEM 3[06 Spring 2020 Exp 30301130[-I0.gcd C:GCsolution DatalAmanda_lest Octgcm 20000 8 10...
5 answers
Ammonium parchlorate (NH,CIO4) the solld rocket fucl used by the U,5 Spacc Shullic Famnt (C1,)' Oxyqcn Qas (01)' Vntot (H,0), end Qreat E dcal energy;Icehatc DrttuCr nitrogon 0*8chlerina 03bWhat mass chlorine ga8 produced bY tne reaction 0l 3.5 of ammonlum ptrchlorate? Round your answer to 2 $ignificant dlgits_
Ammonium parchlorate (NH,CIO4) the solld rocket fucl used by the U,5 Spacc Shullic Famnt (C1,)' Oxyqcn Qas (01)' Vntot (H,0), end Qreat E dcal energy; Icehatc DrttuCr nitrogon 0*8 chlerina 03b What mass chlorine ga8 produced bY tne reaction 0l 3.5 of ammonlum ptrchlorate? Round your answer...

-- 0.019301--