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Find IA infteckier poials X an) - P(v) = #x- 37+/x-8Hhnt: And dlorivabiele;...

Question

Find IA infteckier poials X an) - P(v) = #x- 37+/x-8Hhnt: And dlorivabiele;

Find IA infteckier poials X an) - P(v) = #x- 37+/x-8 Hhnt: And dlorivabiele;



Answers

Use a $u$ -substitution and Table 7.1 .1 to evaluate the given integral. $\int \frac{1}{x(\ln x)^{2}} d x$

Okay, were asked to find the President Valley of Investment that pays out continuously at a rate of 800 per year, assuming our is equal to 0.0. Okay, we have a formula for a present value of income stream paying Artie dollars per year continuously for two years. But that's this P is you consider in a row from Gerald G of our tea, each unit of our t d t. He said our rate was equal to zero point, so it and were paid 800 for a year. So that's our authority. And we're paid this for five years. So Archie is five. So p is equal to from 0 to 5 of 800 e to the negative 0.0 h g ut. Okay, Now, taking the interval of this, you get 800 over and negative jail points. 08 e to the power of Mandeville 0.8 T evaluated at five. And so Okay, so we get 800. You didn't need a job. 108 That's why culvert Natives opens. 08 minus plus 800 over. So point. So eight e to the negative self one. So It's time. Sell discount. So? So we get won something. These two together you get $3296.80.

Ln off 0.38 is a cold Oh minus 0.9676 I have to convert it into exponential form. So when Ellen has given orders, Ln means the base of the longest E on the longest taken on 0.38 This value is given to me as minus zero point 9676 So if I have to convert it into exponential form, that means I'm going to raise eaters to the power minus zero point 9676 on the value is going to be obtained a 0.38 So that is why answered in exponentially question so that it

So we're given certain quantities and we have a couple of quantities from tables that we need to look up, namely the specific volume and CP. So we have these written here and we can refer back to these if needed, as we do the problem. So we have a temperature of 25 C, which is 298.15 Calvin, we have Alfa P, which is 2.1 times 10 to the minus four Inverse Calvin. We have the initial and final pressures. The initial pressure being 100 killed Pascal's and final pressure for compression being 1000 killed Pascal's and this is a process for the entropy is constant, so that's gonna be important. So we'll go ahead and start and so we'll have DS equals zero. The entropy doesn't change. And from that we have this ah, relation that we're gonna obtain just rolling down and feel free to pause this video and play it back. If you need to you to go through the steps, we're gonna have the partial derivative of temperature with respect to pressure for a fixed entropy equaling the temperature over the CPI times the partial derivative of volume will respect the temperature when the pressure fixed. So then we also have Alfa P Equalling the partial derivative of volume with respect to temperature with pressure fixed, divided by volume so continuing we can write this as the partial derivative temperature with respect to pressure. Where the interview held fixed equals the temperature times Alfa p times the volume the specific volume divided by C p. So we'll assume that the let me scroll down some. Or we'll assume that in this process the partial derivative of temperature with the pressure respected pressure is constant during the compression. This allows us to get a change in temperature while the pressure changes. In other words, while the pressure increases in order for the compression to occur. So from that we can calculate the change in temperature. We have the quantities on the right hand side of the equation. We have the temperature right here. We have CPI would have Alfa, we have the specific volume and we have We can get a change in pressure because we have an initial on the final pressure. So if we continue, we go ahead and substitute in these numbers because If you recall, we have all these numbers up here, so you can you can come back, you composites video and get these numbers written down right here. And then you can come back and substitute into this equation right here. And that's what we do. In this next step. We go ahead and we put in these numbers and the temperature difference that we get. The change in temperature turns out to be a very small number, but its 0.135 Calvin And indeed, that's very small.

Hello students welcome back in this question, we have to find out the molar conductivity and the equivalent conductivity of CSE are due at infinite dilution. Okay, so finding out the equivalent and first of all I'll find out the equivalent conductivity. So equivalent and activity will be given by half of London Lord for CIA do place and one time you of London out of C l minus. Okay. And I am given these values already so I'll just put them So it has given half of London north of C two places. They want to be 11 night right? And land and out of sale minus is given to be 76.3. So this comes out to be 135 Yeah. Simon centimeter square where equivalent. Okay. And now I have to find out the molar conductivity at in fire delusion. So Moeller connectivity at infinite dilution for CSC L too would be equal to London north of Seattle plus and two times two times the Lebanon out of C l minus. Okay, so this comes out to be 11 night Plus two times of 76.3. So it comes out of it 2 71 56 centimeter square caramel. Okay, so that's it. Thank you


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