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(10 pts) Your forensic Iab has just received shipment from hospital, contains 103 of a white solid. You FunA number of tests and find the [a]= (-J62" , has MP ...

Question

(10 pts) Your forensic Iab has just received shipment from hospital, contains 103 of a white solid. You FunA number of tests and find the [a]= (-J62" , has MP of 270*C and BP of 509*C The structure is as follows:After completing vour testing; You conclude the compound is thalidomide. You have also found the samplc to have an ee-589s,how much (in grams) of each stereoisomer do vou have?

(10 pts) Your forensic Iab has just received shipment from hospital, contains 103 of a white solid. You FunA number of tests and find the [a]= (-J62" , has MP of 270*C and BP of 509*C The structure is as follows: After completing vour testing; You conclude the compound is thalidomide. You have also found the samplc to have an ee-589s,how much (in grams) of each stereoisomer do vou have?



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You have a pure sample of the antiseptic aminacrine, $\mathrm{C}_{13} \mathrm{H}_{10} \mathrm{~N}_{2}$ (a) Calculate the mass in grams of 0.06500 mol aminacrine. (b) Calculate the number of aminacrine molecules in a $0.2480-\mathrm{g}$ sample. (c) Calculate the number of nitrogen atoms in this $0.2480-\mathrm{g}$ sample. (d) Calculate the mass of $\mathrm{N}$ in 100 . $\mathrm{g}$ aminacrine.

Okay, so we have to beakers. Okay. Sealed. So they're now in contact with the atmosphere, and they're gonna evaporate. Okay. And when this happens, actually, there will be solution being transferred from the least concentrated to the most concentrated solution. So we will have a flux. And we're told that the first solution loses seven grams of benzene to this. The unknown solution. Okay, so we know we have the data for the first solution that loses seven grams, and we don't have the data for the second solution. So we want to find out the number of malls here so we can figure out the more mass. That's the big picture. Okay, Uh, so at equilibrium, the to both solutions will have the same morality when that's the key here. Okay, so we know. And that at the end, the first solution will have 93 grams of bangs in left. Right? Because it started with 100 lost seven. So we have, uh, 93 grams off banking and to compute the morality. Where we do is to, um, take the number of most we know. It's point 15 months and divide by the massive solvent came Normally you need to convert this two kilograms. I'm not going to do this because actually, we're gonna use this value right away. So I just keep like this. But keep in mind if you want to report morality, you have to convert this two kilograms. All right, so if you compute this, the morality in these units will be 1.61 time. Stand to the negative three. They'll be malls. Program again. That's not the standard way to express will out it came. However, this will be valid for both solutions for the first and the second social. So that's great, because the second solution, we don't know the number of most. But now that we know that the morality has to be there, if will be the morality for the second solution as well, right? We can simply take the mass of the solvent, which will be 100 seven grams. Why? I have 107 because we had 100 and we gain an extra seven grams. Kendo was transferred. All right, so this Okay, this has the assumption that all of the solution the the vapor was transferred from one solution to the other temperature getting change. So we have a few assumptions here. Okay, so if you multiply that out, um, you should get 0.17 more. Okay, so that's the number of most. And now the final step is just to complete the molar mass. We have the mass. We didn't know the number of months, but we we knew the mass off the soy it. Okay. And the mass of the Sawyer was given 31 grams. We take that and divide by the number of months. That's how you compute molar mass. Okay, working this about 180 grams per mole.

Everyone. And thanks for joining me, Miss Hallstrom, as we talk about calculating a molar mass in a situation where vapor pressure comes into play, the system that we're going to be looking at is a closed system containing two beakers, beakers A and B beaker. A contains 0.15 malls of a solvent. It's NAFTA lean. So I'm just gonna put any pH because I don't have a lot of room there and it is contained in 100 grams of solvent and her solvent is benzene. Speaker B contains 31 grams of something we don't know what, and it's also contained in 100 grams of Benzie were asked to find the molar mass of B. What is the molar mass of B? We don't know that. And we know that this solution a is going to lose were given that it's going to lose seven grams of Benzie, seven grams of Benzie And where did that benzene go? It went over to here. So here's the other things that we know. We know that at equilibrium the concentrations are going to be equal, the concentrations will be equal, So the concentration of a will equal the concentration of B and that's gonna be in morality. We've got all the information we need to figure out the concentration of a So let's go ahead and look at the concentration of eight. The concentration of A will be in morality will be 0.15 moles of our naphthalene. And again, I'm just going abbreviate it in a pH divided By now remember, original 100 grams of benzene is going to be lowered by 7.0 grams, and I could divide this by 1000 to changes two kilograms. But we'll talk more in a moment about why I'm not. And then let's look at what's going on on for B in her be situation RB situation will have as grams of benzene it's going to add, so it'll have 107 grams of benzene. I should keep my Sig figs right here. Now the problem is how many moles of our substance air here? Well, remember that moles moral ality equals moles. I guess I don't need to do that. This is too hards. Um if I know Grams, what has stopped writing? I'm going to take my grams. Let me write this up here. My grams of my unknown divided by my molar mass, which is X will give me moles. So I'm gonna substitute for moles in here. Grams 31 grams of by unknown, divided by X. I don't know what X is now axes what I'm gonna solve for Okay, this is a pretty easy set up here. Um, let me just do 0.15 moles divided by 93 grams equals. This will be 31 grams divided by 107 x. So for X and I get 1 79 0.6 grams per mole. Since I only have one or two sig figs here, I'm gonna have to report 1 80 grams per mole. And since this is an experiment experimental design that could maybe be glucose something that you recognize quickly that has a molar mass of 1 80 grams per mole. Thanks so much for joining

We are provided with Delia Dogs die, Trey, Shin, hear oxidation and reduction half can be presented out. Oxidation will be essence toe s and too positive. Plus two electron reduction will be n 03 Negative. Bless four height origin. Last three electron gives me and no, let's to edge too. This reaction for the Thai tradition can be summed up as three s n plus toe. You know, three negative less e th for the duke gives me three ascend to positive plus two and no plus four water. From the above chemical reaction we have three more off sn will be equal to two more off n 03 negative. The equal villains point is open that point 0344 litre. We calculate the number off moles off sm present. Here is the simple calculation. We have the mullahs Marceau fasten That is 118.71 from which we can determine the mask off sn using unitary method. So the marks off a scent turned out to be two point 74 months. Pretenders toe negative one ground which is equally villain to 51.3% off. December

Solving problems. 28 of chapter 15. Um, so they're journal. Eases off or talk silent. Um, gives basically three products glycol blocks l 23 Bhutan boot and die own. And people Val died in were ratio. Would you expect the three products Toby form? Give the order. Silent is a resident side breed of truth toe structures and those who is telling house that the actual Rachel was found three parts Greg sel one part 23 But on their own and two parts feel involved. Right? So we have And old zonal is this reaction. That means that when we have a double bond, the double bond is gonna be Cleve and ah, an oxygen atom basically becomes doubly bonded toe each of the original Alcon Karpin's. That means if we are flying zonal Easy's he here, we're gonna basically have so each carbon connected to the double bond, um, is gonna be bond toe an oxygen to a double bond. So let's start writing the formula off the orto silent. We can, for example, these one stage three C H street. Now, if we do and on general leases and then reaction, we think eso from thes one we're gonna have. For example, if we image toe believe these double bond, we would love on one side the two ch three ch three, see as he has three. So each carbon part of the double bunk, the myths, this one and this one will be connected. Toe anoxia jin through a double bone. And to the other group, there was a really there. Okay, then if we think about to cleave this carbon, these double bonds, so do Then we will love. See, uh, ch double bond oxygen. See the bulb on oxygen h. Same thing for these one. So we're gonna have two of these tothis and one of these. Now we can write a different reason on structure for the same molecule. So instead of having these double Bondi here, we can, for example, booty here. The next one is gonna be this one and this one, and we position again the two metal. Now, if we do the journalists again eso from this bond now, we don't have any more ch three ch three, but we have on one side Karpal and either Jen connected to the carbon. So these one, these other Jenny here and then double bond, oxygen, carbon, the bull run oxygen and C h tree on the other side. Okay, then if we consider this boned, we have one side ch three connected toe. A carbon there was connected to the other carbon through the double bonds. So is the one that will be connected toe an oxygen through double bond. And then this second carbon connected to oxygen. And I didn't Okay? And then if we take into consideration this double bond, we we love hydrogen, carbon, a couple bone oxygen and again. Okay, so we'll have This is one, that is We didn't really found it before, so it's one in total then these one with a CH three on one side. And the and I did on the other side is basically equal to this one. And this one. We're ready. Family here. We already have. Two were wanting here so far. A total otri. So going back to the problem, it was basically the only has that we'll have three parts off black would sell that. These, um these will Seoul is ready here. We know that we should obtain three parts. Oh, c h Uh huh. See, Oh, age, um, one part off the 23 Looking the orange. So, uh, to no Sorry one one of the bull Keaton, Go see it. Go see a street. See, uh, C h three and two parts. Oh, then on their ID. So this city stream C o see our age. Okay, so three off these. We have one here that's more with that red color one here and to be here. So we're good. We have three then the double kitten were known from the structure. But we have one, you hear? So we're good, And then we should expect to off The single aisle died, and we have want me here and one e here. But it got a little too. So I'm weird with those who with these one. So these two are the tool I read resident structures on the orto silent on that. Give Ah, it's product. The following products with this racial 31 and two


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