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The cyclic connectivity of glucose would be typified by which of the following functional groups? OH b)...

Question

The cyclic connectivity of glucose would be typified by which of the following functional groups? OH b)

The cyclic connectivity of glucose would be typified by which of the following functional groups? OH b)



Answers

What functional groups are present in the simple sugars (monosaccharides)?

This question. We're looking at different molecules, and we're looking for an alcohol group to be contained in any of them. So an alcohol it's going to correspond to an O. H group found in the molecule. So we have maltose glucose fructose. We also have cholesterol and triglycerides. So the first thing you do when you see this question is you should be able to group the first three molecules and determined them to be sacha rides or carbohydrates, and the last two molecules are associated with lipids. So here you can group them into general categories, So sack rights tend to have a ring structure either six carbons or, in the case of fruit juice, you would have five carbons. So these, of course, have a ratio of C, H and O in a 1 to 2 to one ratio. And it's important to note that because off of certain carbons in each of these molecules, you're going to have hydroxide molecules or these alcohol groups. So here you can eliminate a B and see, because these are all going to contain some sort of alcohol group off of some of these carbons, and these will help them bond via like acidic linkages to other carbons to foreign policy saccharin. Looking at your other two options, we have glycerol and the triglyceride. So if you look at the structure of a triglyceride, this is going to consist of a cholesterol backbone and three fatty acid tales. What's important here is the glycerol itself. Not being bound to a fatty acid is going to contain hydroxyl groups off of it. However, in the formation of ester linkages between fatty acids and the cholesterol backbone, you're going to form the connection between the oxygen molecule and the alcohol group and bind it to the fatty acid. So essentially you are reacting the alcohol group to bind it to the fatty acid. So you're actually removing the alcohol group from the cholesterol itself. So cholesterol itself has the hydroxyl group. But when you bond the fatty acids to form a triglyceride, you are removing the hydrogen from that alcohol group and basically removing alcohols. So here the answer choice is E for triglycerides, because these aren't going to contain any ohh groups since they were removed from the attachment of the fatty acid molecules

Question here. Basically asked what is going to be the functional groups in Model Zachariah and all money sack arise here are basically linear. Simple ones are gonna be linear and unbranded hte, first of all, and that they will have one carbo cardinal no functional group which is suitable under toe. Oh, and one high drop So group H on each of the remaining carbon atoms.

Which of the following functional groups is not polar. We have car bono hydroxy l metal and Suffo hydro. Um, so the correct answer here is see metal. So the metal group is non polar functional group, and this is because the muscle group consists of a carbon atom which is bounded to three hydrogen atoms. Therefore, the metal group cannot form hydrogen bonds and won't be ableto contract with polar compounds such as water, thus making it hydrophobic as well. So it is a functional group that is not only non polar, but it is also a wonderful so thank you for watching and I hope this hope

A McDill in is a dice, aka ride. So for eight, identify the sugars in the mid Ellen. So from the structure of McD alone to glucose units, yeah, are connected to each other by a black ascetic linkage. Therefore, the sugar present is glucose. For part b, identify the black ascetic linkage. Still, the pita I'm americ carbon of glucose is connected to the C six of the other glucose molecule. The two glucose molecules are connected through a bigger 16 like a static linkage.


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