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Match the following aqueous solutions with the appropriate letter from the column on the right:1.7.8*10-2 m K,POA Highest boiling = point D20.13 m MnBrz B. Second h...

Question

Match the following aqueous solutions with the appropriate letter from the column on the right:1.7.8*10-2 m K,POA Highest boiling = point D20.13 m MnBrz B. Second highest boiling point 3.0.19 m MgSo4 Third highest boiling point 040.4m Glucose(nonelectrolyte) D. Lowest boiling point

Match the following aqueous solutions with the appropriate letter from the column on the right: 1.7.8*10-2 m K,POA Highest boiling = point D20.13 m MnBrz B. Second highest boiling point 3.0.19 m MgSo4 Third highest boiling point 040.4m Glucose(nonelectrolyte) D. Lowest boiling point



Answers

Which aqueous solution from the column on the right has the property listed on the left? Explain your choices. $$\begin{array}{ll}\hline \text { Property } & \text { Solution } \\\hline \text { 1. lowest electrical } & \text { a. } 0.10 \mathrm{m} \mathrm{KCl}(\mathrm{aq}) \\\text { conductivity } & \\\text { 2. } \text { lowest boiling } & \text { b. } 0.15 \mathrm{m}\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(\mathrm{aq}) \\\text { point } & \\\text { 3. highest vapor pressure } & \text { c. } 0.10 \mathrm{m} \mathrm{CH}_{3} \mathrm{COOH}(\mathrm{aq}) \\\text { of water at } 25^{\circ} \mathrm{C} & \\\text { 4. lowest freezing point } & \text { d. } 0.05 \mathrm{m} \mathrm{NaCl} \\\hline\end{array}$$

If we compare for substances. Ah, a cheese Hochul ch 20 h c a c l to KBR and any to s 04 We'll find that the any to s 04 has a higher, higher boiling point on the lower freezing point on the other solutions based on its morality and the number of ions it has. Ah, the H o ch two ch 20 h will not associate, so it'll have the lowest vapor pressure.

Let's not the following properties with the correspondent solution for one, the lowest electrical connectivity. This property matches up with a solution. Be because sucrose is a non electrolyte and it will not conduct electricity very well. Number two. The property is the lowest boiling points, and the lowest boiling point matches up with a solution. De because d 0.5 mol an A C l would have the least number of total ions present for three. The highest vapor pressure of water. The highest vapor pressure Yeah, of water at 25 degrees Celsius. So So Property three matches up with solution D and this once again, uh, this is the lowest small fraction of Salyut irons and a higher mole fraction of water. And for four, the property is the lowest freezing points and this matches up with a solution A and solution a 0.1. Moeller Casey l do the highest part concentration of ions present in the solution. It's

We'll work on problem 94 from Chapter 13. This problem were asked to rank three aqua solutions Ah, in order of increasing ah collective properties First osmotic pressure boiling point freezing point in vapor pressure specifically at 50 degrees Celsius. So our three solutions are I 0.1, and Lorca's and morality sodium nitrate number two is 0.1 m glucose and third is 0.1 in calcium chloride, and these are all awkward solutions. So if you are given equal masses than we would need to take into account the identity of the compound because the molar masses will be different and so result in different particles. But here were given the exact same number of moles because morality takes into account moles. So what we need, uh, really plays the the only role that will determine this is the Vantaa factor or I, which would be to for sodium nitrate, one for glucose and three for calcium chloride, based on how they associate in solution. So, in part, A, B and C of A, B, C and D. We need to rank the collective properties, uh, which are osmotic pressure boiling. Point freezing point and vapor pressure and 50 degrees Celsius. So we want to rank it in order of increasing each of these properties. So for a, uh, osmotic pressure is going to increase According to this equation, eyes equal to M I R t So M is fixed for all of them are Tia's are constants. So to rank them, uh, the lowest one would be, too, because it has a value I value of one next highest would be number one sodium nitrate and highest would be calcium chloride for boiling point. We have a similar expression, which depends on I. So we know that boiling point will increase with the number of particles. So we have the same trend to than one, then three. So 213 is the order of increasing effective collective properties. However, when we're looking at freezing point where we want to put it in increasing, and so we know that the solution that's all you'd depress is the freezing point. So we need to reverse our order. So the lowest freezing point is three because it's lowered the most based on the identity of the number of particles from the Salyut. So we just put the reverse order, um, Inter to put the identity of being, uh, saw you. And then vapor pressure eyes going to behave the same way as the 1st 2 days so it will increase the more particles you have so again, to Roman numeral 21 and three is de correct order.

To answer this question, there are two things that you need to recall. One is that osmotic pressure and boiling point both increase with total solute concentration. However, in the case of freezing point and vapor pressure, freezing point and vapor pressure are going to decrease with increasing concentration. So let's calculate the total concentration of all salute species and all three of these solutions. It'll be point to morale for sodium nitrate .1 morale for glucose. And because calcium chloride separates into three species, one calcium and to chlorides Will have .3 mil al. So the boiling point and the osmotic pressure will be greatest at .3 mil al and lowest at .1 morale. Then in the case of freezing point and vapor pressure it'll be just the opposite order. The highest concentration will have the lowest freezing point when referring to the lowest freezing point, these rain orders of increasing values. And it will also have the lowest vapor pressure.


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