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The pH of an aqueous acid solution is 5.85. Calculate the K for the acid. The initial acid concentration is 0.010 M_ Round your answer to two significant figures....

Question

The pH of an aqueous acid solution is 5.85. Calculate the K for the acid. The initial acid concentration is 0.010 M_ Round your answer to two significant figures.

The pH of an aqueous acid solution is 5.85. Calculate the K for the acid. The initial acid concentration is 0.010 M_ Round your answer to two significant figures.



Answers

The pH of an aqueous acid solution is 6.20 at $25^{\circ} \mathrm{C}$. Calculate the $K_{\mathrm{a}}$ for the acid. The initial acid concentration is $0.010 \mathrm{M}$

For this problem. We're going to be finding k A. And we are given that we haven't acid and we're making the assumption are acid is just gonna be a simple acid in the form of hydrogen ion in an ion. And it has a pH of 6.20 The initial concentration of the asset, my H A concentration is going to be 0.10 Moeller. Now, um, we're going to have for our final concentration are equilibrium. Concentration of our acid will officially be 0.10 minus some quantity X that associates. But I happen to know that that's going to be a very low number. So this is going to be approximately equal to 0.10 Moller. So that's what we're going to use for equilibrium concentration. Now I'm going to write. I'll do this in a sort of a light blue color our acid lips that didn't take our acid. H A is gonna be an equilibrium with our hydrogen ion and our anti hunt. All three of these air a quiz. So when we write our K expression, it's going to be H plus times a minus over the concentration of H A. Now I know that h a We just said this is gonna be our our acid concentration. That's what we're using for a denominator. And we were given a pH of 6.20 So if I take 10 to the negative 6.20 that will give me that My H plus concentration of 6.310 times 10 to the minus seventh. And that is my H plus concentration. And it's also my an ion concentration. So these two concentrations are both 6.310 times 10 to the minus seven. Okay, let me see if I have room to put this right here. So we're finding k A. And I know that that's going to be equal to 6.310 times 10 to the minus seventh squared over 0.10 and I get my K A. Is equal to 3.98 times 10 to the minus 11. Now, I only have two significant figures here, and I have two decimals in my pH, which means I could have two. So this gonna equal to correct sig figs 4.0 times 10 to the minus 11th. Thanks for listening.

Mhm. In this question, a 0.750 mol solution of a mono protic acid is known to be 1.7% ionized. We have to find out the ph of the solution also we have to calculate the value of K. For this asset. So that given as it is 0.0750 mon a protic acid, mono protic acid. Mhm. And it is 1.07% ionized. And let's start writing the reaction and let the mono protic acid B 80 so eight A plus water producers a minus and 83 or plus. Now let's draw the ice table division. Yeah. Mhm. Yeah. Mhm. Here the initial concentration Which is 0.0750 moller dear. Oh dear! Oh now things concentration less minus X plus X plus X. And here equilibrium concentration will be +0750 minus X. Here X. X. Now this solution is 1.7% ionized. So X will be 1.07% of 0.0750. So the fellow forex will be 0.0008025. Their stuff. Hello four eggs. Now excess concentration of high Dona Mayan. Therefore concentration of high Dona maya is 0.80 to five. So ph will be create means negative log hi dani. Um And concentration will be negative log 0.080- five. There are four p is 3.096. Now we have to figure out that K. E acid ionization constant. K. A. Will be concentration of a minus times concentration of high Dooney um iron divided by the concentration of the acid. Now a minuses X H. T. O. N. Plus and concentration also eggs. And this one is 0.0 point +0750 minus six. All the equilibrium constant that is K. A. Now we know that hello for X. Which is 0.8025 square x square. And here 0.750 minus the Hello affects which is very small. Still we are using since we know this one. Therefore K. A. Is this one? Now uh value for 0008025 square is 6.44 times 10 to the power negative seven. And if we subtract this one we get 0.742 Now we get eight 67 times 10 to the Power -6. That this is the value for. Okay. So we got A. A. And also that ph right and the ph was here That is three 096

Over one morning. We all know that the concentration off each posted for a week as it is calculated using these relation k eight times by the concentration off the week as it so. Now the value off key A will be equal. The concentration off each postive Bauer two divided by the concentration off the week I said So the concentration off each postive is equal timber negative value off B H, which is 4.52 So it will be timber or negative. The value off pH power to dividing by the concentration off the week as which is open toe one night. So the result will be 4.8 times Boynton bore negative nine. Andy Lees is a simplest way to calculate the the value off Key A I think.

So for a check Our acid, the acid association constant. We're looking for K A is describing this reaction or h a reacts with water access an acid. In other words, it gives up this H plus So yet h 30 plus in in the car. If you base a minus three, this Ha jin went over here. And so if we perform a nice table on this Mom, this is the same sort of ice stablemate race. This this is sort of same sort of hive table you do for a simple lasted based association question. Um, and you should be really comfort. This will get the following. So our initial amount were told is 0.115 Ignore water. We have zero initial over here. Changes minus X plus X plus X and start equilibrium. We have a fallen values. This should be comfortable to you from the equilibrium unit and just turned in cracks problems. And so, if not, I have earlier questions that describes in detail. So r K is equal to our concentration. First of our products. So HBO, plus times a concentration of a minus. Remember this the mass action expression over the concentration of the reaction here. H a ignore water. It's a liquid. And you know, we plug in what we have at equilibrium, which is acts acts for numerator chefs X squared over 0.115 minus sex. But we have done this before. So this how is this? Well, instead of being given K, were given acts but in an indirect manner, since we see that this is the same accidents here, if we can figure out the conservation of H 20 plus were set and so were given that the pH equals 3.29 So remember the concentration of H 20 plus. This is by definition, what Ph is is tense, the negative pH so 3.29 And so that equals acts. And so we can plug in this value over here and find K. And when you do that, you'll find that the K equals to 0.297 sometimes tense, the negative six no units this case


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