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Table 3: F2 phenotypes (left cell) and counts (right cell) Phenotype Wild_ type males Wild type females Eye color White White Wing shape Vestigial Vestigial Straigh...

Question

Table 3: F2 phenotypes (left cell) and counts (right cell) Phenotype Wild_ type males Wild type females Eye color White White Wing shape Vestigial Vestigial Straight TotalMutant males Red StraightMutant females Red Straight VestigialStatistical analysis:Based on the outcome of the Fl and F2 progeny you should now have some idea on the type of inheritance that you feel the mutant alleles follow: giving your phenotype ratios from your predictions do your results match these ratios? Use chi-square

Table 3: F2 phenotypes (left cell) and counts (right cell) Phenotype Wild_ type males Wild type females Eye color White White Wing shape Vestigial Vestigial Straight Total Mutant males Red Straight Mutant females Red Straight Vestigial Statistical analysis: Based on the outcome of the Fl and F2 progeny you should now have some idea on the type of inheritance that you feel the mutant alleles follow: giving your phenotype ratios from your predictions do your results match these ratios? Use chi-square analysis to determine if you will reject O retain YOUI null. b) what do you conclude is the mode of inheritance occurring for these mutant alleles?



Answers

In Drosophila, three autosomal genes have alleles as follows: Gray body color (G) is dominant over black ( $g$ ). Normal wings $(A)$ is dominant over vestigial $(a)$ Red eye $(R)$ is dominant over sepia $(r)$ Two crosses were performed, with the following results: Cross I: Parents: heterozygous red, normal $\times$ sepia, vestigial Offspring: 131 red, normal 120 sepia, vestigial 122 red, vestigial 127 sepia, normal Cross II: Parents: heterozygous gray, normal $\times$ black, vestigial Offspring: 236 gray, normal 253 black, vestigial 50 gray, vestigial 61 black, normal Are any of the three genes linked on the same chromosome? If so, what is the distance between the linked genes (in map units)?

Closed. The recombination frequency is the lead off. Occurance off pretty combination between a beer off linked jeans on it can be calculated by don't tell number off re confidence divided by total number off progeny assuming one map unit is equal to 1% off re combination recombination frequency hertz in deter mining The distance between two genes on in generating will engage map. So there is four plus 47 less 44 less five, which equals 200 grow. Ginny shows recombination between genes. He Andi from beef. Therefore, our if that is recombination frequency becomes 100 by Carlson 1001 in 200 which is equal. Do then person or didn't map unit. Thus the combination fraction between A and B is then map unit. Now there is four plus 57 plus 84 plus five, which is equal to 180 progeny. Shoe recombination between genes be on D. C. Therefore, art if between B and C is one a d divided by 1001 much of late by 100 which is equal toe, 18% 0 18 Mad unit. So the genetic map becomes no, since there are 100 progeny show recombination between genes A and B on 1 80 progeny show recombination between genes B and C. Therefore, the expected read of double recombination will be 100 divided by 1001 into 1 80 divided by 1001 which is 0.1 in do 0.18 which is a 0.18 That this eating but 1001 however, did it. Actually four plus five that is nine are observed as double re components. Therefore, the coefficient of oh incident is observed. Do you see you divided by expected BCU, which is equal to nine by 18. That is zero point, right. Therefore, the coefficient off coincidence is 0.5

What is the difference between rescue herbal and non respirable maternal of back, certainly for mutations. So this is where the gene products is inherited directly from the mother, and it's not produced initially was I got's rescue herbal means for if the father has a wild have alley, all the zygote may end up as expected, developing normally or is non rescue ball needs With these I got cannot develop normally, no matter what be can a type of the father is. So what's the difference? Uh, apart from what I've just said, Rescue Herbal tends Teoh pacts later in developments, which means that perhaps be his ego can produce between products itself to compensates if be maternal effects pump work. Where is non rescue? Herbal tends to act very early on. Before was, I go compulsively compensates for me since member

So here we have a male just saw Fela, who is homos, I guess recessive for the cinnabar and brown I color jeans. Normally, this would make him have white eyes. But due to a duplication on his Y chromosome of the positive brown Jean Heat now has red eyes, right? He has made it to a female dress. Awful A who was cario typically normal, meaning that she has no abnormalities in her chromosomes like he does. And she is also home is, I guess, recessive for the cinnabar and brown jeans, meaning that she actually does have white eyes. What kind of offspring is going to be created once? Thies to mate? Well, based on what we know about sex and sex determination, we know that males have to pass on their Y chromosome in his Y chromosome. The males y chromosome has a copy of the, um, brown gene on it, which means that all the males that they produce will have red eyes. They would be CN minus CN miners B w minus B w minus B w plus. They'd look almost identical to this male because both the male and the female have the same otherwise normal jeans here. But because he has an extra copy on the Y chromosome, all of his male offspring will have red eyes. The female offspring, on the other hand, will look almost identical to this female right here because they don't have this extra y chromosome. And as we just stated, the genetic information between these two was identical. Otherwise, from the Y chromosome, intense females don't have Y chromosomes. You can comfortably say that they will have white guys.

Love independent assortment by mental stage sets. Else off genes are inherited. They inherited independently off each other's the linkages, the condition in which the genes are present together. While in Ritter generation found after the many years off mender, sometimes jeans air so closely presented a chromosome, then it will not be sorted independent into the next generation. This condition opposes the second law of mental finding. So in other words, linkage is the exception. Or we can say deviation from the law. Independent assortment or the second Law of Genetics and concerned cross her true Dikkers for two characters females Fruit fly crossed with male with resistive home. Ojeda's genes for the same characters results off the cross. Our great body with normal things are 1 26 black body with vestigial wing is 1 25 great body with vestigial wing is 24. Black body with normal things is 26. Ah, symbol for body color and different length of things are great. Bodies be like bodies. Clippers normal things is V G plus and vestigial wings is Vigee, so the cross will be great body normal. Wien are, um, BG BG plus then B and B G and here is the black body with vestigial wings be beachy and B v g. This is the histories, I guess. Female Jada's female and the 60 home was like a female. So the cross would be, Yeah, first great body, no moving B plus B G plus be Maiti 1 26 and then they black body was teacher wing Black body was teacher living Will they be B g B B g? It is all it is 1 24 So total is to 50 parent tell Then again, we have black. I'm sorry, Gray body Vestigial ving is B plus V G and B B and which is a total of 24. Uh, it's black body normal. Ving A P V G plus B and VG total is 26th two so 50 Sorry, 53 convenient out of 300 progeny is 20 to 50 year out off 300 progeny he's 2 50 are but until on da 50 ah re convenient type This results is This result is deviation from required mental ratio that is, one is to one is 21 is 21 The provided data shows that the linkages. President between the gene off the body color and winky link. So frequency off recombination estimate of the proportion off the recombinant progeny in across It can be measured by the formula frequency off Riffa frequency off re combination is equal to number off. Recombinant. Throw Jeannie upon. Yeah, number off total Perot. Jenny. So over the help off of ah formula, we can estimate the recombination off frequency of body color and we engine of the fly. So, uh, frequency of rock recombination number off recombinant progeny as 50 and a number of total Virginia is 300. That is zero point six. Therefore, the recombinant frequency mhm Rico Vinent frequency is less than 50%. So this result proves that Jean off body gala and moving length are linked Fred each other


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