5

Dtessunc | JBu Tke nex{ day; nn tronl voluni 0t 65 5 4hcn balleon Inllalcd t0 atmosthictic Assutuin g ele tempcruturc rctnains canstunu Khat Ihc nex holumic aniies;...

Question

Dtessunc | JBu Tke nex{ day; nn tronl voluni 0t 65 5 4hcn balleon Inllalcd t0 atmosthictic Assutuin g ele tempcruturc rctnains canstunu Khat Ihc nex holumic aniies; and Ihc atnurphcnic [ycssurc dtups 01.98' ba Ofthe balloon Wutces"

Dtessunc | JBu Tke nex{ day; nn tronl voluni 0t 65 5 4hcn balleon Inllalcd t0 atmosthictic Assutuin g ele tempcruturc rctnains canstunu Khat Ihc nex holumic aniies; and Ihc atnurphcnic [ycssurc dtups 01.98' ba Ofthe balloon Wutces"



Answers

Pick our rhe corrcet srarcmenr/s abour noble gascs (a) $11 \mathrm{c}$ cannor be usct in prefcrence ro nitrogcn $\left(\mathrm{N}_{2}\right)$ to dilute the oxygcn in the $g$ as cyclindcrs used by divcrs. (b) $1 \mathrm{tc}$ is used in wearher balloons and airships. (c) He is used in cryoscopy to obtain the very low temperarures required for superonducrivity and lasers. (d) $\Lambda \mathrm{r}$ is used in metallurgical processes.

In this problem, I'm writing the reaction. Just look at it carefully. Any energy for at be your ford four H two will react to form any and at four at people for plus four as to and and ME energy for add bill for will react to form and the beauty plus an STD plus as to So according to the option. In this problem option. See each correct. Was there not that we have any Beauty which reacts with metallic oxide to give colored or to post fails.

In the first part of the problem we have to find the total by armed force that is acting on the 600 bellows. So first of all we I am writing the given data for the institution. So we have given the That the radius of the balloon is given to us that are as close to 0.5 m. And we know that Dere of the areas. That is 1.29 kg permitted Europe. Now we can say that by armed force is given by That is 600 gallons into on back and forth on one balloon. So this this is 602. This will be Roy of air into the into the volume of the balloon. Now, I am going to put all the data in the execution So this is 600 into this is 1.29 into this is 9.8 and volume of the balloon is given by that is it's physical balance. So we can see that this is four by three and two pi r cubed. So this is 0.5 whole cube after holding this weekend. This is 14 to 10 to the power three newtons. What? I can say four kg newton. So this is the total by armed force acting on the balloons. And this is our answer for first part of the problem. Now, in the second part of the problem, we have to estimate the net upward. 4th on All the 600 balloons. So we can say that that net of workforce is given by that is total by own force minus total weight of the balloon. That is m into Z. Total back and forth. We have calculated that is working on your tan minus total weight is you turn as that is 600 into weight of one balloon. That isn't 1 3 into 9.8 after holding this weekend. This is two point two and 2 10 to the power three Newton's or I can say 2.2 kN. And this is an upward direction. So this is our answer for the second part of the problem. Now in the third part we have to tell did why at high altitude the balloon begins to burst. So we can say that this is the part. At high altitude, the pressure is low, so low pressure is there and because of this pressure balloon will expand and it begins to burst. This is our answer for the final part of the problem. Thank you.

All right. This problem goes the concept of by and see. And for party, the bite force is the density of the air into the volume of the balloons. Uh And to the gravitational acceleration of the bank of buoyancy force. The eagles, the density of air into the number of balloons Into the volume of a single balloon. That is 4.3 by our cue. I am. So gravity is not acceleration or by rearranging we can write the cells and uh sorry four by three. And by row G. Into our two. Now, so should the value to calculate the branch of bank fourth. So B equals 4.3 Into the number of blues. 600 into five. into the density of air. That is one 2 9 kg or meet. OK into 9.8 m. Four seconds square into our cube and radius is uh zero point five m Q. So the band force on the balloons. four into Denver three notice. Yeah. Now, Barbie From the northern 2nd law of motion. The net force equals the band force master. Which okay are the net force equals the brand force minus and into the mass of a single balloon time. See gravitational acceleration now so shoot the value. So the net full sequence. Four Into the industry. Newton's -600 and two. The mass of a single balloon is 0.3 Kg 0.3 Kg. And to 9.8 m four seconds are the net force on the system is 2.2 and two Tenders 3 notice along the vertically upward direction. No bars, etc. Uh Mhm. The balloon dress because the atmospheric pressure at the high altitude is very less and the pressure inside the balloon will become significantly greater so that the balloon pops out so we're going to see the atmospheric pressure. Yeah. At high altitude uh becomes very less compared to that pressure inside the balloon and due to they stress in the balloon membrane at explodes.

Total brand forces given by Daughter Volume. Who it is number of billions. Times volume off one billion. Who is 4/3 by are cubes. This is a daughter volume times we have real density off air times, gravity so that comes out to be. We have got 600 balloons times for third 3.14 The radius is half meter pseudo born five cube identity off air is given by we have to take it to the 1.2. You know, Grandpa Meter Cube TimesG equals 9.8. So that comes out to be 3.69 times 10 to the three. New down. Now the net upward force will be the upward brand force minus the weight of the balloons, which is the upward Brian forces found to be 3.69 times 10 to the three minus the wait off one balloon is given by 0.3 kilograms, so that's 600 off them. Time. 0.3 times 9.8. So that comes out to be 1.93 times 10 to the three Newton. As the parson lowers be ADM, the atmospheric pressure increases So the Bedouins burst


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