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# For a reversible reaction, the concentration of the reactants are doubled, then the equilibrium constant(a) becomes one-fourth(b) is doubled(c) is halved(d) remains...

## Question

###### For a reversible reaction, the concentration of the reactants are doubled, then the equilibrium constant(a) becomes one-fourth(b) is doubled(c) is halved(d) remains same

For a reversible reaction, the concentration of the reactants are doubled, then the equilibrium constant (a) becomes one-fourth (b) is doubled (c) is halved (d) remains same #### Similar Solved Questions

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Use 0.212 0.212 2 2 Hz (g) constant 848 0.424 (mol/l) for the following ON (g) ezep the following reaction: to 1 determine 0.544 0.544 3 0.136 [ON] Nz (g) Give ! oheezte of JO} Mei each reactant 59 0.793 this reaction: 0.0991 0.0248 Initial and rate 341 1 average rate...
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##### Consider the reaction below:P + 7 0z ~ 2 PzO-If the reaction has an 82.3 % yicld, then how many grams of P Oio can be produced from the reaction of 97.3 g ofP ?compound is made of aluminum; silicon and oxygen (Al,Si,0 ) Three experiments were carried out to determine the formula of the compound: In the first experiment it is found to consist of 33.30% aluminum by mass: In the second experiment it is found to consist of 0.1733 compound. In the final experiment the oxygen found in [00.0 grams sili
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0/1 points Previous Answers SCalcET8 11.8.041. My Notes Ask Your Teacher Suppose that the series Ccnx" has radius = convergence and the senes Zdnx" has radius convergence 10. What the radlus convergence of series da)xn Need Help? biun MieOr W% 2 Iut 0/1 points Previous Answers SCalcET8 11...
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##### 1 How are Rolle's Theorem and the Mean Value Theorem related? ii. Use the Mean Value Theorem to show that if f is a differentiable function on [a,6] and |f' (2) < K for all x â‚¬ [a,b] then |f(b) _ f(a)l < Klb = a: iii. Let g(.) = 1/(1 + x4). Starting at To = 0.75, use four steps of fixed point iteration to approximate a solution of g(w) =x
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