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UtilityInlet (PC)Outlet (SC)Cost (S/GJ)Low-pressure steam12512433 psia (0.22 MPa)4.54Medium-pressure steam High-pressure steam Electricity Cooling water175174127 ps...

Question

UtilityInlet (PC)Outlet (SC)Cost (S/GJ)Low-pressure steam12512433 psia (0.22 MPa)4.54Medium-pressure steam High-pressure steam Electricity Cooling water175174127 psia (0.875 MPa) 4.77 250 249 575 psia (3.97 MPa) 5.66 NYA N/A 18.72 5 0.378 Refrigerated water 15 4.77 Low refrigerant N/A 8.49 Very Ow refrigerant N/A 13.11 Ultra low refrigerant 100 N/A 33.20 data from Product and Process Design Principles by Seider, Lewin; Seader; Widago_ Gani and NB;

Utility Inlet (PC) Outlet (SC) Cost (S/GJ) Low-pressure steam 125 124 33 psia (0.22 MPa) 4.54 Medium-pressure steam High-pressure steam Electricity Cooling water 175 174 127 psia (0.875 MPa) 4.77 250 249 575 psia (3.97 MPa) 5.66 NYA N/A 18.72 5 0.378 Refrigerated water 15 4.77 Low refrigerant N/A 8.49 Very Ow refrigerant N/A 13.11 Ultra low refrigerant 100 N/A 33.20 data from Product and Process Design Principles by Seider, Lewin; Seader; Widago_ Gani and NB;



Answers

Some vapor pressure data for Freon-12, $\mathrm{CCl}_{2} \mathrm{F}_{2}$, once a common refrigerant, are $-12.2^{\circ} \mathrm{C}, 2.0 \mathrm{atm} ; 16.1^{\circ} \mathrm{C}$ 5.0 atm; $42.4^{\circ} \mathrm{C}, 10.0$ atm; $74.0^{\circ} \mathrm{C}, 20.0$ atm. Also, $\mathrm{bp}=-29.8^{\circ} \mathrm{C}, \quad T_{\mathrm{c}}=111.5^{\circ} \mathrm{C}, \quad P_{\mathrm{c}}=39.6$ atm. Use these data to plot the vapor pressure curve of Freon-12. What approximate pressure would be required in the compressor of a refrigeration system to convert Freon- 12 vapor to liquid at $25.0^{\circ} \mathrm{C}$ ?

Hi friends. Here it is. Given are two states compression. Yeah, a refrigeration psychic bit suppressing it. Using R 1 34 8 as a flute, we have to find the rate off early B but power required power input so that these two parameters we have to calculate from refrigerant table a 11 to 8 13 in first state temperature T one is 819 degrees Searches liquid is saturated weapon and toffee to 55.60 Global park age and n trophy Toby point 9 to 711 Colonial parquet jee Park Calvin In state two Pressure is P two having the value 1400 clo Paschal and trophy off state to it's called Toe State one. So enthralled Free Toby to 81 point 56 Closure Park age in ST three Pressure is 1400 club basket. Uh huh. Flood is saturated, Lee. Good. So in this state and thoughtfully Toby 1 27 point to fight Global park Eiji in a state foot and okay and toll fee is equal toe as three batches 1 27.25 Global Park egy. That is a throttling process in a straight five temperature is 8.9 degrees. Soldiers fluid. It's saturated. Look good and tell me Toby, 63.91 Ecological Park Igic at six to be. It's called toe at five. That is 63.91 Colonial Park EGY. In a state seven temperature is minus 32 degrees. Else's fluid. It's saturated pepper, so Aunt Alfie is to 30 point 93 Hello, jewel Packaging on end profit. Toby. 0.95819 Colonial Per K G Yeah, Park Calvin in ST Food. Sorry. In ST eight, pressure is 400 Club Paschal and Trophy off Eighth State is going toe an trophy off seventh state. So on Toffee Toby to 64.51 Colonial parking and energy balance on separator mass. Floor it in six. Estate and tow. Add eight minus at five mass flow rate in second straight at one minus H four. So from here must floor it in sixth state. You will get mass flow rate in second state in tow at Japan, minus as toe upon at eight minus 85 So in the problem it is given must flow it in second state. Toby two kg per second, so just putting the value go into to 55.6 minus 1. 27.55 upon to 64.51 minus 63.91 So you will get mass flow rate in six estate Toby one point to wait kg per second. The rate off willing will be mass flow rate in this existed in tow at seven minus at six, putting the value 1.28 to 30 point 93 Minus 63.9 months of it is to be 213 points 7 kg joule per second, the total power input so the compression must floor it off. Success state at eight minus at seven plus mass flow rate in second state as to minus engagement. Putting the values 1.28 to 64.51 minus 2. 30.93 plus two into to 81.56 minus to 55.6. So on solving you will get 94.9 globe. What? That's all Thanks for watching it

Hello, friends. Here it is. Given Ah, geothermal heat pump given, do you thermal hate pump that degree off. Circling done on refrigerant in the convention fight. Mass flow rate off refrigerant. The heating load. Yeah. Coefficient of for formation of the pump. Minimum power input. Let us see it to solve this problem. We have to as you So I just since required the study. Operating condition. I just on a ticket. No lots and kind of technology on potential energy. No, Let us hear the analysis. We can do the analysis by using the property off refrigerant 1 34 e you think properties off a refrigerant R 1 34 8 using table A 11 so 8 30 for the state at four. The state temperature is contradictory. Senses quality or flu is 123 Pressure is 5 72.1 glow paschal and and tal Fee is 1 21.25 You know you'll perk aging for a statement. Pressure is 5 72 glow Paschal quality off flute is one that is saturated pepper. Aunt Alfie is to 61.64 Global park aging on n trophy is 0.9 toe fight Kill a jewel per Cajun in a state toe pressure. It's 1400 Globemaster as to his skull toe as one that is an trophy at a state one on state to worship on rental fees to 80.5 global per Cajun from Esteem David. A foot and trophy off water in ST One and trophy at the rate off 50 Researches, 209.34 Global parking on anti Alfie in ST toe at the rate off 40 degree. So it's this temperature 1 67 point 53 kg Dual per Cajun. The situation temperature at conventional pressure Oh 1400 Clo Paschal. An actual temperature at condenser outlet saturated at the rate 1400 club mascot is 52.4. The result is at a state three. Pressure P three is 1400 club basket and tell feeds 1 21 125 Colonial parking on temperature in this state would be 48.58 degree searches. The degree off supporting is Delta T sub cooling he saturated minus 23 That is 52.4 minus 48.58 That is three point it to degree, searches the rate off heat absorbed from the geothermal water and have a porter age mass fluid off. What? Into changing and trophy in ST one to its state toe. That is 1065 So it is to be 2.71 eight globe. What? So a rate off? Low off I refrigerate, It rate off heat absorbed from geothermal water upon changing and profit, that is why 01 night 36 Hello, jewel Parking. The power input. So the compression must floor it in tow. H two minus judgment. Plus, he transferred to the heart junction as toe to 80 point. You're a pipe minus 2 61 164 as two men. Assessment plus Q out. So it is to be 16563 clover. So right off he transferred toe the hot but their way mass flow rate in tow. As to minus s three subsidy being developed, you will get 3.7 You know what coefficient of performance amount off the heat transfer rate off amount of the transport with the hot, rigid wire on working put rate off doing the work so it will be 4.68 So coefficient of performances. 4.6 it the river civil coefficient of performance of the psychic one upon one, minus temperature, offloading shin upon temperature off or junction. So it is to be 12.92 So minimum birth input your minimum power input a rate off. Transferring the heat at high temperature. Toe efficient, off performance off reversible process. 3.7 upon 12.92 So it is to be quite 238 globe er, that's all for it. Thanks for watching it.

So here in this problem, we're using the heat pump toe. Maintain the temperature of the space to 25 degrees Celsius. On we're using the refrigerant 1 34 a onda it absorb heat from a geothermal Bordeaux on it enders at 60 degrees Celsius. Onder the drain Inspection X off water one, it is zero Onda Uh, the water exit at Cambridge Oh, 40 degrees Celsius on X, the blue to the tetrahedron. Instruction is zero and they're saying that the pressure off the refrigerant R inlet and outlet off of operator is seen. That means be one here is equal to P two here in case for the refrigerant. So first of all will be calculating the intel Avi's by using the table given in the book, I will be using the saturated of order table that is given in the book to calculate and tell before this condition, and it comes out to be as to 51.18 Killer Jewell perk itchy on similarly, by using the same table that and help for this condition, it will be 1 67.5 curricular jewell package e no next level big calculating the intel before a refrigerant art inlet and out laid off evaporator that is de even. It is given us 12 degrees Celsius on the dryness traction. At this point, it is 0.15 Now, by using the saturate the table off saturated 1 34 8 and profitable and then help according to this condition, it will be which one. 96.54 collegial, per cagey on the pressure. At this point, it will be 443 point three Calabar school and they're saying that he wouldn't be do seem so. We can say that B two is also equals two p one, which is 443 0.3 Calabar School on the dryness Traction here it is one because it exits are situated Ripple That is where it is. One nothing tell yet for this condition it will be approximately 2 57 point treacle. A jewel perk. Egy. Now we can say that the rate of feet transferred from the water is the energy change off the water from inlet to exit on. This is nothing but you a lot and it'll be equals. M dot w names, which the blue one minus vegetable too. Onda Mustard off photo in the cushion. It is given us 0.65 Gage, you per second. So if you have all the release here to calculate the belief Cool doctor, we can park it here. So this is 0.65 kg per second times. H w wonder it does. You have got cleared us to 51. It's to 51.18 minus H w Do is one Texas seven point 53 on this is the desk. A little park hee. So from here, we get the value of cured orders approximately 5.437 Killer jewel per second. That means skill. Of what? So this is your lord? No, the energy increase off The refrigerant will be equal to the energy degrees off the water. And the ever better doctors begin C that master it off refrigerant. It will be called struck your daughter. Divide by H two minus H one. Secure doors. We have calculated as five point 437 Kill of what Divided by H 20 is this one is H two so to 57 point three minus this is H one 96 point Pfeifle and then it escalated. Jewel package E. So from here will get the mosque loaded US 0.338 kg per second. So this was the solution for the A Bart. Next it will be soldering though be part of the problem on in the be part of the problem, we have to calculate the rate off heat supplied now from the first law of thermodynamics again saying that the rate off it's applied, it will be called to cool dot Bless the power input we have all level is significant buried here. Your daughter we have calculated as this one five point afford 37 kilowatt plus the power input it is given integration on it is given us 1.6 kilowatt. So we're buggered here. This is 1.6 kilowatt. So do you watch dot It comes out to be as nearly 7.0 folklore. So this is the rate off it sublight rescue edged or that this was a solution for the B. But next it will be calculating the sea Bart. So in the sea park, if we have to calculate the Seop so we know that the Seop is equals to courage dot divide by the power input On a huge dot we have calculated as 7.4 kilovolt in the last party. We have calculated list on the power and could were given as one points explored. So you get us 4.40 So this was a vision for though, see part next in the re. But we have to calculate the minimum power and put through the compression at the same rate off each applied that when we have those unit Courage daughter saying on power input we have to calculate and at a minimum. So for that we're to calculate the maximum seop and magazines You hope it will be called to one minus one Divide by one minus two year old divide by teach where th is the source temperature and realizing temperature. So one divide by one minus the sink temperature. It has given us 25 degrees Celsius, so we have to convert this thing into Kelvin. So we're going to add to 72 to do it so we'll get to 98 Qwilleran do white way th were given us 60 decrease lt's we have big this temperature to be sth onda. It will come if we're going to convert this thing into Kelvin will get 333 Qwilleran. So this one is 343 Kelvin So we get the maximum Seop as this one is maximum as nearly nine point Fife one. Now we can calculate the minimum power input and it will because to courage dot Divide by the Seop maximum So cute Daughter is 7.0 Focal award divide by magazine Seop is 9.51 So we get from here the minimum part and put us 0.740 So this was a solution for a D part. I hope you got a problem. Thank you.

Hi, everyone Here it is given to a evaporator compression refugees and I could with a refrigerant R 1 34 8 fine cooling rate off The high temperature have evaporated. The power required for compression. See coefficient of performance. Let us start solving it. We have to do the analysis right. Using David A 11 a 12 and a 13 for fruit properties at ST three. Pressure is 800 kg. Paschal flip is saturated Lee Good and Tal Fee is 95. Fight for it. Kill a dual park igic at four. It's called Toe H six is approximately. It's called toe H three. 95 point for it. K G Clue Jewel Park Eiji. That is the throttling process at the state. Five temperature is given zero degree flood is saturated pepper so and toffee at this stage. Toby to 15 0.50 Ecological park agent. Yeah. At ST seven, temperature is minus 26.4 degrees Celsius. Fluid is saturated pepper and 20 at this is stress. Toby to 34.44 Kalu do perky the mass flow rate through the low temperature. Yeah, and separated. Agent rate off. Heat absorbed mass. Floor it in tow at seven minus at six. So mass flow rate you will get This value is given eight colonial per second. That is to 34.44 minus 95.48 So it is 0.5 757 Okay, kg per second. The mosque floated through barman evaporated. Total mass flow rate minus mass flow rate at low temperature ever operator. So it is to be quite one minus. Why did Euro 5757 that is Why did you 4243 go Yugi per second Airplane energy balance toe A point in a system were to ever operator streams are recombined Floor it in tow. Enter fee. So from here and therapy at ST one will be fluid Putting the well too often anyone 0.4243 to 50.5. Why did you know 5757 to 34.44 upon 0.1. So it is to be to 41 point 26 closure Parky Yeah. Then pressure p one will be 100 glow Paschal H one is to 41 point 26 Closure will park Asian, so an trophy is 0.97 91 Clue Do Park a G park Calvin Pressure P two Having developed 800 kg paschal and profit as to its skull to s one edge to enter Alfie Having developed to 86 point Streeto pillow, you'll park age the cooling rate at high temperature. Ab operator cooling rate off high temperature have evaporated all right. Mass fluid and to changing and tall fee from is straight five too straightforward. So 0.0 full toe for three into to 50.5 minus 95 point for it. So you will get 6.578 global. The power input to compression must floated into changing and profit from state one to state toe. Total mass flow rate is given 0.1 and 12 ft off. State one. Profit 3.5 minus 95.48 So it is to be 6.57 it Golobart Um, sorry. It is to be 4.5, you know, six. The coefficient of performance off refrigeration rate off. Fooling upon power input eight plus 6.578 globe. What? Upon 4.506 global. It is to be 3.24 They're so thanks for watching it


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