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2 You are in a chemical laboratory and given_two beakers. Each contains a clear, colorless liquid. You are told that beaker / contains sugar dissolved in water and ...

Question

2 You are in a chemical laboratory and given_two beakers. Each contains a clear, colorless liquid. You are told that beaker / contains sugar dissolved in water and beaker Il contains sodium chloride (table salt) dissolved in water. You don't know how much sugar or salt is dissolved in each container. The safest, nost definitive way to determine which beaker has the sugar water and which beaker has the salt water is to pour off a few mL from each beaker into separate containers and then Amea

2 You are in a chemical laboratory and given_two beakers. Each contains a clear, colorless liquid. You are told that beaker / contains sugar dissolved in water and beaker Il contains sodium chloride (table salt) dissolved in water. You don't know how much sugar or salt is dissolved in each container. The safest, nost definitive way to determine which beaker has the sugar water and which beaker has the salt water is to pour off a few mL from each beaker into separate containers and then Ameasure their densities Badd more water to each solution Cheat both solutions to dryness D_filter both solutions through filter paper add sugar or salt to each solution taste both liquids



Answers

Three beakers contain clear, colorless liquids. One beaker contains pure water, another contains salt water, and another contains sugar water. How can you tell which beaker is which? (No tasting allowed!)

All right. Welcome back. So this problem, we have a beaker. You must The gas 300. No leaders in it of us. Saltwater solution. And it's at a 2% concentration. Excuse me. Um, 2% concentration, and we want to increase that to a 3% concentration. So how are we going to do that? Well, this right here means that what? I know how much salt is in the water right there. It's not no leaders of salt water in 2% of it is salt, right? Sort of almost like my 20.0 to you. I'm not one of us. Six, I guess. Milliliters of of salt. Right. All right. So we have six million years of salt secret. You range You were three rate, 3%. Uh, a new point of water and a new volume of water. Or just call it X. So if we divide both sides by pointing through three, we should get the new alignment water. And I won't give us 200 milliliters secret eggs, will we? Um no, not with water level right there. That means that we need to boil 100 liters of water. Oh,

First, let's figure out a few masses. We'll figure out the mass of the solution but taking the difference in mass of the evaporating dish before and after adding a solution. 12.5 grams. Then we can figure out the mass of any C L after evaporation by taking the mass of the n a C l that stuck after all the water evaporated minus just the massive evaporating dish would get 1.4 grams and then we have to figure out mass percent. We'll take the mass of any CL divided by the mass of the solution times 100. We get 11.6% in a C l. The density of the solution could be determined, which will need for part B by taking the mass of the solution, which we determined to be 12.5 grams, divided by the volume of the solution which was given to us at 10 milliliters and we get 1.205 grams for middle leader. So if we start with what we know, the grams of the sodium chloride divided by the grams of the solution, we need to convert the grams of sodium chloride into mold sodium chloride and then the mass of the solution into, um, leaders of solution. And we will get more clarity. So to convert the gram sodium chloride into mall sodium chloride will use it smaller Mass. Then to convert through the mass of the solution into mill. Leaders of the solution will use the density of the solution, which is 1.205 grams per mil leader. And then we don't want middle leaves in the denominator. We want leaders in the denominator. So will on the tail end here. Convert leaders are milliliters of solution into leader solution, and we'll get 2.40 Moeller sodium chloride, then last of all, we want to convert the similarity that we just calculated 2.40 into a new mill. Arat e. When we take 10 milliliters and we dilute it to 60 milliliters, then we can use the delusion equation and we'll solve for X and X in this case will be three 0.99 Moeller sodium chloride if we don't do any rounding it all until the very end

Drivel. Question one told. You can pass in two ways. One chemical way can be called us at. And that's Euler nitrate. The issue Jerusha Which one? Ive well, I saw that which will give you Washington Dusty's. So you're nasally alright? Because the equation So the rest is so busy goes that he's with test. I wish so A lotion. Okay, the I saw this that Nazi sodium chloride and squid does that mean to you? Because we completely know the solution sugar and show that will go and test. But if you don't know the name of the Schuler so you cannot pass, okay?

Without knowing all of the techniques that are available to a chemist in the laboratory to determine whether or not an Aquarius solution contains table salt. You likely won't be able to provide some of the answers that I will provide, but hopefully you could recognize that you could determine whether or not the suspected clear colorless liquid, which you assume to be. Water contains table salt is you could evaporate off the water after evaporation. If it contained table salt, you would have table salt left over. You also might know that you could conduct a conductivity test If if it is pure water, it will be a very poor conductor. If it contains table salt, it will also be, it will be a good conductor. Other techniques might be to carry out a tea tray shin with silver nitrate and the chloride would precipitate out. Or to use instrumentation, such as an inductive coupled plasma instrument or an atomic absorption instrument that would directly measure the presence of sodium ion.


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