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Fmd hby drwing Jnd using this mobile4+25+hmJh - 2 - 1...

Question

Fmd hby drwing Jnd using this mobile4+25+hmJh - 2 - 1

Fmd h by drwing Jnd using this mobile 4+25+hmJh - 2 - 1



Answers

Multiply by using the special case products. $$\left(h+\frac{1}{6} k\right)^{2}$$

CO two molecule CO two molecules is he I saw the structural CO two molecule is I saw a structural with with h d c L two with h d c L two and and C two. H two molecule. So according to the option option B and option B. R, correct and said for this problem option B and option D. R. Correct answer for this problem. I hope you understand the answer of this problem.

Here, we need to divide the two fractions. So when dividing fractions, it's easier to look at it when writing it horizontally. So we're going to divide it horizontally. So the first two fractions, we're going to find a common denominator and rewrite it as a single fraction. So the first fraction or the H is missing. An H R common denominator is H So the top part becomes H squared minus one divided by in the second set of fractions. The first fraction is missing an H. So we're going to multiply by H. So we get five age. It is the common denominator. And on the top we get H minus one. So when we look at it again h squared minus one, we can factor by the difference of squares that becomes H minus one H plus one divided by H R. Division. Sign becomes a multiplication and the second fraction we flip so five H divided by H minus one. So now we cancel out what we can our H one minus ones cancel out our H cancels out. So we're left as the final answer five times a quantity H plus one

In this question, we have to multiply the given polynomial by using especially case product within bracket three edge minus K hole square. We can compare the given polynomial by the formula A minus bi really square a Z equals two a square minus. Do a B plus B squared. There it will be equals toe three h andi be will be equals two. Okay, On further substituting the value in the above formula, we will get a square that this tree h foolish where minus to my deployed with a that is created My plan would be the risk a plus B squared their risk a holy square. On further simplification, we will get nine at a square minus six. Hey, bless Gaius crab.

And so for the given question, we have a session, given position is Gcl too and SNCf to exist together in equal solution. The reason for this, Given ization is on heating GCS to supply times. So here we have the correct option for the given statement is the option D exertion is falls, but the reason is two. So here we will write the correct assertion for the given reason. So correct position is Gcl too, and SNC and two cannot exists cannot exist together in a glass solution. And the reason is here on heating. Yeah, Gcl too. Sublime songs. So here is false and but are is true. So the correct position is GCL to end. SNC cannot exist together in a solution.


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