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I 38 where x %td 9 transverse What distance E L Save Progress E 1 docs Interval 1 SerPSET9 1 betwecn B4.Ot) ddescrbed b seconds, Practice Another Version 1 li the w...

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I 38 where x %td 9 transverse What distance E L Save Progress E 1 docs Interval 1 SerPSET9 1 betwecn B4.Ot) ddescrbed b seconds, Practice Another Version 1 li the wavc dunction V when E Ol U pdll element has 1 (a)? L 0.175

I 38 where x %td 9 transverse What distance E L Save Progress E 1 docs Interval 1 SerPSET9 1 betwecn B4.Ot) ddescrbed b seconds, Practice Another Version 1 li the wavc dunction V when E Ol U pdll element has 1 (a)? L 0.175



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In Exercises $34-39,$ compute the flux $\oint \mathbf{F} \cdot \mathbf{n} d s$ of $\mathbf{F}$ across the curve C for the given vector field and curve using the vector form of Green's TheoremIf $\mathbf{v}$ is the velocity field of a fluid, the flux of $\mathbf{v}$ across $\mathcal{C}$ is equal
to the flow rate (amount of fluid flowing across $\mathcal{C}$ in square meters per second). Find the flow rate across the circle of radius 2 centered at the origin if div( $\mathbf{v} )=x^{2}$ .

This problem covers the concept of the Lawrence transformation and from the Lawrence transformation, subjecting data equals we be upon C. Okay we can reader this equation is the enter key equals gamma delta Ortigas plus comma. Better there? Dexter is upon C. Now this is a question of a straight line and the slope it's A. M. Equals gamma beta upon C. Now the value of beta has given us one upon gamma And to square it off γ Square -1. So they can read it this Lopez squared off gamma square minus one upon C. Now the slope of the graph equals on the vertical scale. The difference in the time scale is for microseconds are foreign to Then this -6 seconds upon. On the Oriental scale. The scale reading defenses 400 m. So from this forget square Rudolph gamma square minus one upon C equals One end to tell this -8 seconds four metre. Now we substitute the value of C and multiply on the right hand side so they get Thomas Square -1. And in spite of vehicles, one in two tenders minus eight seconds or mito into Train. Then there's eight m 4 seconds. A spirit of commas fire management equals see So the value of Kama from this we get 3.16. Okay so at Delta Express equal zero we get delta tedious equals The 30 year bond gamma and that extends equal zero delta tease two microseconds or two in 2, 10 days minus six seconds upon 3.16. So that temporal separation between the two events with respect to the moving famous uh, 6.3 into tenders -7 seconds.

So if you wouldn't draw a diagram of the factors we have this this would be the velocity of the water relative to the shore. And then here, uh, my apologies. Trying to make him straight here. It would be the velocity of the swimmer relatives of the shore. And then here this would be thieves. Velocity of the swimmer relative to the water. Excuse me. So if we want Teo, if we were to divine define an angle here, Fada, we consider it a sign of Fada is going to be equal to the ah velocity of the water relative to the shore. Ah, divided by the velocity of the swimmer relative to the water again sign if data would simply be opposite over high pot noose. So here it'LL be point five meters per second. Divided by point six zero meters per second s o arc sine would be equal Teo essentially five or six and this will give us fifty six point four degrees. At this point, we can say that philosophy of the swimmer Ah, velocity of the swimmer relative to the shore we'Ll simply be equal to the velocity of the swimmer relative to the water times Co sign of theta. So this will be point six zero co sign of fifty six point four degrees and this is giving us ah point three three two meters per second. So this would be the one to be one of her answers. This is how fast you have to go in order to reach directly across the the body of water. And then to find out how long it would take her, we would have to say that Delta acts equals of the times T and so we can say t equals delta acts over the which we just solved for. So we'll be forty five meters and then divided by again that value that we just solve for point three three two meters per second again, this distance here from this point to this point, that's forty five years. So it would be a T equals one hundred and thirty five point five seconds. So it would take her approximately just over two minutes in order to reach the end of the body of water. And this is how fast she would be going. That is the end of a solution. Thank you for watching

Here we have been given there that the velocity increases linearly with time. So we is equals two. Okay. Multiple weighty our kids. The value of case given as who. So it will be 2 to T. This is the velocity. And now we have been asked to point out the distance covered by the electron in the first three seconds. So so as we know a distance X. Is equal to U. T. Plus R a T square. So here the axle is and we need to find out the acceleration acceleration will be equal to D. V. Divided by D. T. But it will be calls to two m/s square. So let us substitute the value to initially spirit is zero less. Oh multiplied where excellence and it's two multiplied where time is given us three. They can go after calculus and we will get it as nine m. So let's compare the option. We see that option ups. And he's correct option here is. Yeah.

Everyone, This is the problem. Based on crossing the river here it is given there is a river off fifth, 75 m on A similar is capable to sing and still water with 145 m per second. Yeah, in the river current off water is 0.4 m per second. We have toe find the angle along with a long with his should swim to reason particularly approach it bank off the river So theater with a piston we have to calculate and we have to find the time taken to cross the river Suppose swimmer swims at angle theta V line off crossing Then it having their two velocity We as cost it, um and we as a sign of Titan. So crossing speed off the silver it's ves costed him on a drift to speak You drifted down to the ice cream Will be we as sign off data minus bit of Luke on it Drift must be zero so far and drifted. Toby zero zero. Sculptor B has signed off theta minus VW. So sign off theater. You will get btw upon V s. That is theater is sign and worse off. Quite fully. upon quite 45 that is theater is Cotto. Sign in reversal 819 That is 62.73 to me. Time taken to cross the river. It's got oh, width of the river upon crossing his speed The crossing spirits Yeah, We s cost student 75 upon V. S s white four fight cause off 62.75 So time off, crossing the river will be 3 57.14 seconds. Hard. 5.95 minutes. Garzon. Thanks for watching it. Yeah.


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