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Prublem Iyeu I Shax IhatIrhls ecll ' Loternuing #bether SIa cumesehl dteeent thw totiroan this chprer . hlakc aLre LLLat Juu state chich Ict and Muuthunni Jnit...

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Prublem Iyeu I Shax IhatIrhls ecll ' Loternuing #bether SIa cumesehl dteeent thw totiroan this chprer . hlakc aLre LLLat Juu state chich Ict and Muuthunni Jnit chorenteechnl2

prublem Iyeu I Shax Ihat Irhls ecll ' Loternuing #bether SIa cumesehl dteeent thw totiroan this chprer . hlakc aLre LLLat Juu state chich Ict and Muuthunni Jnit chorenteechnl 2



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In rhe rcaction: $\mathrm{AI}_{2}\left(\mathrm{SO}_{4}\right)_{3}, 18 \mathrm{I}_{2} \mathrm{O} \frac{\text { Trat }}{18 \mathrm{II}_{2} \mathrm{O}}-$ $A^{800^{\circ} C}>B+C .$ The producr $A, B$ and $C$ arc, respecrively (a) $\mathrm{Al}_{2}\left(\mathrm{SO}_{.}\right)_{3}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{SO}_{3}$ (b) $\mathrm{\LambdaI}_{2} \mathrm{O}_{3}, \mathrm{\LambdaI}_{2}\left(\mathrm{SO}_{i}\right)_{3}, \mathrm{SO}_{3}$ (c) $\Lambda \mathrm{l}_{2} \mathrm{SO}_{4}, \Lambda \mathrm{l}_{2} \mathrm{O}_{3}, \mathrm{SO}_{3}$ (d) $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}, \Lambda \mathrm{I}_{2} \mathrm{O}_{3}, \mathrm{SO}_{2}$

Okay, so now we have this vector in the complex space and we need to first found the country kate, the real part, imaginary part and then the norm of this vector. So they congregate. We only need to change the sign of those numbers that for the imaginary part of the factory, In this case we have six that remained the same one. And here we change it to -4. I. And the last component will be six plus two. I. Okay, so that's the country gate. Then the real part will be the terms that uh doesn't um have the imaginary number the eye. So those that are just the numbers in this case six, 16 And the imaginary parts, those that are multiplied by I. So in this case is 0 -4 and two. The last thing that we need to do is calculate the norm. So in this case is equal to the square root of the dot product of you with its congregate. Okay, these results into the square roots of through six plus one. Last 16 han Plus 36 plus four. This result into the square root of 93.

Hello there. Okay so here we have this venture this in in C. Three and we need to find the country, get the real part imaginary part and the norm of these. Very so the country, it is really easy. We only need to change the sign of those that are that have the I the imaginary part. That's the the only thing that we need to do when we talk about the country gate. We need to change the sign of the imaginary court. So we did the following factor too. Plus I Lux minus here buying this four. I I'm here -1 1 -9 So as you can see we only change the sign of the imaginary. Then we need to get the real part Basically is all the numbers that are not together with the iPod. So 201 imaginary port instead is those that have the I. So minus one 41 and finally the normal to the norm in the complex space is fine as the other problem of you with you in the complex the square root of the product of the vector with itself. But this is the square root of you don't product you congregate, and this result into the square root of four plus one plus four. I was 16 here and last one plus. Okay, so the result of this is the square root of 23.


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