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20. How many molecules of CICO in 14.2g of CI,CO? 2[. How many atoms of Cl are in 14.2g of CLCO? 22. Calculate the mass of Cl are in 14.2g of CICO. 23. If presented...

Question

20. How many molecules of CICO in 14.2g of CI,CO? 2[. How many atoms of Cl are in 14.2g of CLCO? 22. Calculate the mass of Cl are in 14.2g of CICO. 23. If presented with the wave diagram; you should be able (0 identify its following components: (a) wavelength, (b) amplitude (c) frequency 24. In what region of the clectromagnetic spectrum is photon found that possesses twice as much energy as one in the blue region ( 442nm) of the visible spectrum? 25. What is the wavelength (in nm) of photon emi

20. How many molecules of CICO in 14.2g of CI,CO? 2[. How many atoms of Cl are in 14.2g of CLCO? 22. Calculate the mass of Cl are in 14.2g of CICO. 23. If presented with the wave diagram; you should be able (0 identify its following components: (a) wavelength, (b) amplitude (c) frequency 24. In what region of the clectromagnetic spectrum is photon found that possesses twice as much energy as one in the blue region ( 442nm) of the visible spectrum? 25. What is the wavelength (in nm) of photon emitted during transition from the n=3 state to the n= state in the H atom? How much energy was released by the electron during this transition? 26. Give the values of n, and m; for the orbital in a 3d subshell. 27. Indicate which of the following sets of quantum numbers in an atom are unacceptable: (a) (1,1, (b) (3,0,-1 , ) (c) (2,0,+1, 1), (d) (4,3, 1 ), (e) (3,2,+1,1) 28. What is the maximum number of electrons in an atom that can have the following quantum numbers? n = 4,[ = 3 29. Indicate the number of unpaired electrons present in cach of the following atoms: B, Nc; P Sc, Mn, Se, Kr; Fe, Cd;, [, Pb, Cu; Cr:



Answers

An electron confined to a one-dimensional box has energy levels given by the equation En = n2h2>8 mL2
where n is a quantum number with possible values of 1, 2, 3,…, m is the mass of the particle, and L is the length of the box.

a. Calculate the energies of the n = 1, n = 2, and n = 3 levels for an electron in a box with a length of 155 pm.
b. Calculate the wavelength of light required to make a transition from n = 1¡n = 2 and from n = 2¡ n = 3.
In what region of the electromagnetic spectrum do these wavelengths lie?

Hello, friends. Here it is, given that Adam in three d state, um, it's a photon off wavelength for 75 point Jiro it toe nanometer when it decays toe. So where's the state? We have to find energy off photo. Use the selection, Dude. Find that allowed tradition if an atom to be an external magnetic field off 3.5 Testa ignored spin off electron if energy off three D state Toby minus 8.5 Electron volt bit. No magnetic field. They What is the energy? If the state into which it is splits in magnetic field, deeper water, the allowed babe length that we have to calculate, Let us to start solving it. Okay, let us see the solution. The president's off external magnetic field sift energy levels up and adult, depending on the value off em. The selection rules tell us that for allowed tradition, data is called Tobon. They am hell. Toby Jiro are unless minus but energy can be given by energy. Off photo Knees at sea by Landau 4.136 10 To the power minus 15. Electron Bold second and tow three into 10 to the power eight upon 4 75.82 There no meter on solving it. You will get 2.61 toe electron volt. Be part yeah, for allowed tradition data, and it's called Tobon. Euro are plus minus one for three D state, and it's called 23 Harris, called Toe on a Mammal, can have 21 Jiro, minus one minus two and two p. State and it's called Toto, and it's called Tobon on American Help 10 minus one. Therefore, therefore, there are nine allowed transition from three D State to so Pete in the presence off magnetic field. Wow! And it's called Toto Amel is called Toe, and it's called Tobon A man. It's called, too, but Ellis got toe, um, Ellis called Cuban Toe Ellis Culture one. Emily is called to zero, and it's called Toto AML. It's called to burn toe L. It's called Tobon on a mariscal to burn, and it's called Toto. Um, l is called to zero, and it's called Human M. L. Is called Toe one, and it's called 20 A man is called to zero, and it's called Tobon a medical, too. When this is you, let me correct it. Alice called Toto. Um, l It's called toe doodle Ellis. Call to one, um, elliptical Tobon. And it's called Toto. I meant it's called to my husband. Ellis called Tobon a mariscal 20 and it's called Toto. A man is called to minus one Ellis. Call Tobon. I mean, it's called Tu minus mint Alice Skull toe Hammond is called Tau minus two, and it's called Tobon, a man it's called to minus one in cheap part. Delta's is Gatto Movie in two weeks, that is 5.78 Tend to the power minus five Electron bull per Tesler and toe 3.5 Tesla. So it is to be 0.0 23 LePen bolt ready deep. The energy difference off allowed tradition equal toe energy difference. If no magnetic field were present, that is 2.61176 electron volt and that value plus minus delta E 0.23 203 Electron volt. Therefore we will get for is called Toe 2.6. Double 176 Election Bowl Baby lent Ege 4. 75.0. It took nanometer and foot. He's called toe to point six Double 176 Electron Bull plus 1760.2 to +03 Electron bowl that is 2.611 963 Electron Volt Babel in Toby 4. 75.11 night nanometers That son. Thanks for watching it.

All right. Hello, everybody. Today we're gonna be doing some calculations based off of the equation for the combustion of glucose. This process is how our body derives energy from the breakdown of glucose. So first things first, Um, assuming that the molar entropy of combustion, I how much energy is released when glucose is combusted is negative. 2800 killer jewels. Let's say that you take in 2400 kilocalories each day. So what amount of glucose will you need for that? So there's a pretty simple dimensional analysis. We have 2400 kilocalories. You'll notice one calorie is 4.184 jewels. So one kilocalories, obviously, um, 4.184 kila jewels. So we just plug this ratio in. And now that we have killer jewels, we can actually convertibles glucose. So we say one more glucose over negative 2800. Killing you up. Sorry, we don't need the negative. The negative is just telling us that it's exit 30. But for our purposes here for dimensional announces, we won't need So putting all this together, you're going to get three 0.586 moles of glucose. I'm going to assume that the 2400 and 20 100 numbers have four sig figs. Just because I feel like 266 would be a bit less for this problem. Okay, that's your most glucose. Now, to get from that to your moles oxygen, all we're gonna do is use our equation. We have one mole of glucose here, and we have six moles of oxygen. So 3.586 most glucose means that we will therefore need six moles of 02 for each mole of glucose. So our total malls, too is going to be six times 3.586 which is 21.5 two moles a vote to Okay, so that's you're part a. Now, let's move on to part B. So part be asked us how many moles of electrons will we need to reduce that? Uh 02 from part. So let's bring back our equation. C six h 12 06 plus six two gives us six C of to plus six h two up. Okay, um, now let's make our equation for the reduction of box. So we have 602 Um, going Teoh six h 20 That means we need to add in 12 extra age plus is on this side, which means that we also need 12 e minus on this. So for every six moles of oxygen, we're gonna need 12 moles of electrons. Which means that if we come back earlier, we'll see 21.52 moles of oxygen. All right. Times 2 12 Moles of electrons for every six moles of oxygen. Well, then give us 43.0 four moles of the electrons that are needed to reduce our oxygen. All right. Pretty simple. Pretty straightforward. Okay, let's go on to part C. Okay, So Part c asked us to find the current that travels through the body based off of the amount of electrons, Um, that we found in part B. So this is more dimensional. Announces 43.4 moles of electrons times We have 6.22 times 10 to the 23rd electrons. Permal, right. You should definitely know that ratio. And then each electron, as I've written up here, has a Coulombe a charge of 1.6. So two times 10 negative 19th coolers So we right in that ratio. And then what we're left with is four going 152 times, 10 to the sixth. Cool ups. Okay, so So this is our Coolum a charge now to find current. Well, we know that, um, this is the amount flowing in one second. Sorry. Sorry. This is an entire day, right? This is the combustion of glucose for the entire day. So we need now need to calculate, um, 4.152 times, 10 to 6 cool ums for one day, and then we just start using dimensional analysis toe convert a date down sometimes one day, 24 hours and then one hour is 3600 minutes seconds. And so ultimately, what we end up with is four 0.15 to divide by 24 divide by 3600 and we will eventually get a total current of 48.6 amps running through our body at any given point in time on average. Okay, Awesome. So let's move on to part D if this standard. So now we're saying that in this electron chain, our potential our current is 48.6 but our potential is gonna be equal to 1.0 volts. So from this, we want to find the power, right. That's the Watts. Okay, So the equation for power is P equals I ve And where eyes current in amps and V is potential revolts. So we're going to say power is one point. Oh, volts. Times 48.6 EMS, which will give us 48.6 watts. That is your final answer. Thank you very much. Have a good day.

Before we begin these two problems, I just want to write out the equations that we're going to be using for both of them. That way we can quickly plug in the numbers. So let's start. The first equation that's going to be relevant is the question that they're not the question, the equation that they gave us in the question. So this is going to be the energy of the ejected electron, which is E. K. Equal to 1/2 the mass of the electron times velocity squared. This is going to be equation one. Next equation two is going to be our, um, typical equation for the energy of a photon. So it's going to be. Energy is equal to Plank's constant, which is h tends to speed of light, which is see all divided by wavelength and as a reminder. Each is equal to six point six 261 times 10 to the negative 34 dual seconds, and C is equal to three times 10 to the eighth meters per second. And then equations three is going to be that the energy that was injected. So let's call that e total a question to you is also we're gonna call me Total. The eternal is again the energy of the incident. The energy that got injected No, that energy is going to equal the energy of the ejected electron in addition to the ionization energy. So what does this mean? That means the total amount of energy that was injected is equal to the energy of the particle, the electron that came out as well as the energy that was required to take out that electron in the first place. To these are the three main equations that we're going to be using in basically this order for both parts A and B of the question and as a reminder, energy. We want to keep it in jewels until the very end, were asked to convert it to kill a jolt from all. So let's start with for a So in part, A. We're going to be looking at rubidium. So let's start with equation number one an equation. Number one. We're gonna be looking for E. K. It's equal to 1/2 times the mass of an electron, which is given to us as nine point 10 nine times 10 to the negative 31 kilograms. Now we multiply all of that by velocity. Squared velocity is going to be too. Wait for five zero times 10 to the six meters per second squared. So it took all of that into a calculator. We'll get two point seven 34 times 10 the negative 18 jewels. It's no, we have our e k. Now we can sell for you total. So that's his equation. Number two. So again, E t is going to equal 6.6261 times 10 the negative 34 dual seconds. I want to play that. But three times 10 to the eight meters president. Right. All of that, by the way, blink so we were given the wavelength in nanometers. But actually since velocity isn't leaders per second and speed of light is also in meters per second, you want to turn the wavelength from nanometers which is 58.4. Union leaders turn that into meters by dividing by 10 to the nine tend to the 90 meters and everyone meter. So that will give us five might beat for times 10 to the negative eight meters so we can put that into our equation. 5.84 kinds. 10 for minus eight meters. Like all of this into a calculator, you'll get three point four. You're a one times 10 the minus 18 jewels. So now we hav e k and e t. We can use a question three to sell. Who are you won? Three. I's sorry. So again we have e total, which is 3.4 01 cures that's gonna be equal to 2.734 kinds. Tone the minus 18 two l's and it's gonna be plus e I You know, when we saw her eat, I will get six point six seven to times 10 to the negative 19 Jules sooner we have e I, but we want to convert it to kill the jewels promote. So in order to do that, you have to write this on your page. We're gonna have to take 6.67 to times 10 to the minus 19 jewels. We're gonna have to convert jewels. You too, killer jewels. And there's 10 to the three jewels for every killer jewel. And we also need to introduce moles. Remember that this is the energy of one full time, which is a particle, so we can use ABBA Guardo's number. So we have 6.0 to 2 times 10 to the 23. So times it's gonna be Permal. So, you know, we could solve for killer jewels promote and that will give us about for our two for three. Can the jewels from So that's our in search apart. Hey, so now we can move on to part B. So again, we're going to be using these same three equations. So let's start pretty with equation one. So again, equation one, we're gonna have e k equal to 1/2 the mass of an electron, which is 9.109 times 10 to the negative. 31 kilograms times velocity squared. So philosophy is 1.2 for zero times 10 six meters per second. We're gonna square that no, that is going to be equal to 7.0 to times 10 to the negative 19 jewels. That's good. No, your e k. So let's move on to number two Equation number two again, we're gonna be solving for e. T e. T is equal to how are Constance which were 6.6 to 1 times 10 to the minus 34 66 1 And that's gonna be dual seconds. Multiply that by three times, tend to the east, and that's gonna be in meters per second. All of that divided by wavelength. And again, we have to convert labeling from nanometers two meters. Yes, we have won 42 millimeters. There's 10 to the nine and the meters every one meter. So it's gonna be 1.42 times 10 the minus seven meters. You could bring that back into our equation. 1.42 times 10 to the minus seven. Peters, we flew off that into a calculator. You get one point four times 10 to the minus 15 cules. So we have ET and you K. Well, we have to do is so for me. I So we have e t in the equation. Three. It's gonna be equal to okay, plus e I. So it's gonna be all right below 1.400 times 10 to the minus 18. It's equal to 7.2 times 10 the minus 19. These are both jewels plus plus e I So if we saw for E I, we're going to get seven times 10 to the minus 19 jewels. And now we simply have to comfort this into killer jewels. Promote me to the same thing that we did on top the 7.0 times 10 to the minus 19 jewels convert that Dicko Jewel's promoted by first dividing by 10 to the three fuels for everyone Kill Joel and again her particle per foot on. So we use over Guardo's number just 6.0 to 2 kinds. 10 to 23. Everyone more. This is particles. So again we put this fall into the calculator, we get about for 22 4 21 All right, boards, this is gonna be our final answer. Hurt to be

Okay. In this problem, we have a hydrogen atom with a mass of one point of just a proton one point six seven times sending negative twenty seven kilograms. In this hydra pageant, Adam admits a photon with an energy of ten point to evey. We were asked to find numerous things. Namely, we need to know what we want to find the kinetic energy of this haijun atom which will recoil after firing off this electron. And the reason why it will recoil is through conservation momentum. If it releases don't like trying with some momentum, it has to have an opposite momentum toe maintain conservation momentum. So it'll have a resulting kinetic energy and we wantto get the ratio of his kinetic energy to its total energy to determine if this recoil effect is going to be important enough to consider for a foe. Time admitted at this energies. So for equations, we need to know the energy and momentum of a proton given in terms of the blank constant and its wavelength, we'LL need to know the kinetic energy and momentum for a particle's mass, which is a simple, non relativistic expression. And I strongly believe that non relativistic equations will be appropriate for this particular situation because I do not think that it that this mass is going to have much velocity. So let's jump into it to start. So to start off ultimately we want to use momentum. But in order to get the momentum of a foe time, we need to know its wavelength. So we can start by taking its energy equals h c ever landa. And we can use this to find Landa, which is HC every and so numerically, we'd actually need to use planks constant in a it's evey form one point four point one three five times ten to the negative fifteen electron volts seconds multiplied by the speed of light three times into the eight meters per second, all divided by the stated ten point to evey. And this would give us a wave length of about one point two two times ten to the negative seven meters. So now we can set up conservation of momentum. So the momentum of the photons which is h over Lambda he's going to be equal to the momentum of the particle with Master Hye Jin ETA envy. We know everything except for the which is what we saw for visas h over and Lambda and will to come out to be about three point two five meters per second. So quite slow, as I predicted. This is why relativistic effects won't play that a major role. So now we know V. We confined the kinetic energy of our hydrogen. Adam, what happened? B squared, Plug me in and envy we will get a result of K equals equals about eight point eight times ten to the negative twenty seven jewels. And we can convert this into electrons by dividing by one point six times ten the negative nineteen jewels for electron volt, you get five point five three times and the negative eight electron volts. So this is an incredibly small number, which tells us that this kinetic energy of the recoil is going to be negligible very, very small, so we can get the ratio of kinetic energy to energy of the photo time which will be about five points for two time sending the night of nine so clearly while well, there's equal momentum being apart into the hydrogen atom because its mass is so large. That translates to a very, very tiny velocity that's imparted. That's a very, very small connect energy. So this recall effect in terms of energy will be negligible, barely going to move this Adam. And that's the main result. We have wavelength. That's important. Velocity that's important. Connect energy. That's most important, and that's it. Thank you very much.


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