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A) The potential difference across three (3) resistors that are connected in series are 6V, 12V and 8V. The supply current is 13 A. Determinei) The current through ...

Question

A) The potential difference across three (3) resistors that are connected in series are 6V, 12V and 8V. The supply current is 13 A. Determinei) The current through each resistorii) The total circuit resistanceiii) The values of each of the three resistors b) Given four(4) resistors all with J rating of 322. State how they must be connected to obtain an overall resistance ofi)Z [email protected]) 78n0

a) The potential difference across three (3) resistors that are connected in series are 6V, 12V and 8V. The supply current is 13 A. Determine i) The current through each resistor ii) The total circuit resistance iii) The values of each of the three resistors b) Given four(4) resistors all with J rating of 322. State how they must be connected to obtain an overall resistance of i)Z 0 @) 78n0



Answers

Four resistors are connected to a battery as shown in Figure $\mathrm{P} 28.16 .$ (a) Determine the potential difference across each resistor in terms of $\mathcal{E} .$ (b) Determine the current in each resistor in terms of $I .$ (c) What If? If $R_{3}$ is increased, explain what happens to the current in each
of the resistors. (d) In the limit that $R_{3} \rightarrow \infty,$ what are the new values of the current in each resistor in terms of $I,$ the original current in the battery?

Well, dish up the batteries to love words. So there are three resistance connected in cities with the bedroom. The 1st 1 is living sense of seven home. And the 2nd 1 having real sense off do any to home on the 3rd 1 is having ready to send. So 1 41 home lived this really sensitive name. This are one this nameless are due and this is numbers, man three. So we can go split the regular interest since s in cities. Equal interest since is equal to some of the reticence off unusual resistors. Two article in physical to our one plus our true colors are three. Which is you, Goto, 37 home. Who knows? 22 home fellas. 1 14 11 So you get are a blend. Is he going toe? 200? Wow. So the girl watching through between can be calculated by using home can be calculated by using homes. Alarm that icicle too. We have on article and here these to award a bond article. Aunties wondered. Well, um, so we get there parental, Bodine is your goal. Do you're a point 06 mbia now in the second part of this problem We want to calculate potential difference. Across are one or two and our tree since restores our quantity in cities The current friends room Each race studies Sam. So now we want to calculate What is it? Gross. The other one. So we're detected. Us are one Is we want is a goto current times reticence here guarantees 0.6 m Pierre multiply One is could be seven home. So we get we want equal toe wind, dude, Through wars No, again we want to calculate We'll take a dozen are too So what did you cross our toe physical through high times? I do so here I cz zero bine 6 a.m. Pierre My reply are you is 22 on So we get we to equal toe one line, three wars? No, we'll get across. Oh, I see again By taking forms along every three Zeke Alto high times RC here eyes zero point little six m Pierre, My people I am after is 1 41 on. So we get with three physical do and find 46 Worse

In this question of this um Get arrangement for three resistance. There are two parts in this question. You want to find a total power dissipated and the potential drop across each. Okay so in part a find out total power dissipated. Yeah. First is to find a total resistance. So I'm is one two. Okay so we can see that are two and archery are parallel. He then So R. two tree the tool one of our two plus one of our archery and receive boko. And yes. So you'll be getting a there you see almost And then R. one and R. 2 3 in series. And so the equivalent resistance is uh 192 us that you see. Mhm. 288. Okay so the power dissipated is calculated using we square over our are equivalent then numbers. The answer is 51. Okay so this is the answer for part A. Okay next in party. Um So we want to determine the potential drop across the resistor his office so you can find a total current investigates. Okay, so this is equal to V over our total are equivalent. So 100 indeed divided by 288. And this is 0.417 mps. So to be one is equal to I. R. One And this is 0.417 times one night two. Here you get he wants and that have you to and delta bigotry are the same because they are proud of. So it's equal to -501 180 when it's 80. It is. Yeah. So these are the answers. Mm And that's all for this question.

Hi. And this given problem. There are the resistors which are joined a parallel combination with each other. These are the terminals A and these Yeah the Upper one. This is 6.0 own the lower one the middle one that is 12 10 home And the lower one again. This is 610 home. These three are the resistors. It is given that the potential applied between the terminals A and B. Is that a BBAB. And that is given as 3.6 gold. So in the first part of the problem we have to find the magnitude of all the currents passing through These three races. Stores Ivan and I do and I treat uh huh as for potential remains the scene in parallel. So here the potential will be even is equal to B two is equal to V three. And that will be able to be ready or on the resistor. So using arms law The current passing through the first resistor. The Upper one that is even by Arvin. But even this is the a. is 3.6 divided by six. Oh I went here comes out to be Tzeitel boring six mps. Then for I too That is we to buy our two Means 3.6V invited by Well mm So yeah, it will come out to be Yeah, we'll come out to be 0.b. I am here. And finally For the 3rd resistor. I three Will be given by the three by Artery. So here it will be 3.6 walt again And six widened. 0 home again. So I agree Will again be equal to 0.6. NPR. Hence finally we can write these three answer says Ivan. I do and I three for Ivan and I three both of them are still point six ampere And I do is 0.3 ampere. So these three are the answers. What about first part of this problem? No. In the second part of the problem we have to find total current drawn from the power source. Using jobs laws. Total current drawn out of the source. That will be equal to one class. I do less likely means this is 0.6 plus 0.3 plus 0.6 and fear and and services one wind Why I am here. Total current coming out of the safe. And this is the answer for the 2nd part. This problem. Thank you.

In this problem we have a battery that has a voltage of home votes and three resistors connected to it In series. So you have are one 42 homes Our 2 17 owns and our three 110 homes. And in a we want to find the current flowing into the battery and be the voltage across each resistor. So for a we use Homes Law, which is the voltage in the battery equals the current flowing into it times the resistance. So since we're looking for current, we solve for it by dividing both sides by our so we get current equals footage divided by resistance. But here the resistance is actually the equivalent resistance of the resistors or the some of the resistors in series. And because they are in serious, that are equivalent is our one. Those are two Plus our three. So when you add up all the resistors in series, you get the equivalent resistance. And you can plug it in to our equation for current. And We get the answer for eight. And then for me we can use almost lot again full touch equals current and resistance. And since the resistors are in series we can use the same current for each resistor. So then we would get for the first one we would be voltage across the first resistor equals the current times are one. So we know our one is and once we get the current from A we can just simply plug it in and that's all for the voltage across the resistor. So again for a from our equation for current we have current equals voltage times the equivalent resistance. And again they're in series. So the equivalent resistance is R one, R two P. S. R. Three. So you have 42 Plus 17 Plus 110. So the equivalent resistance is 169 Holmes. So then plugging this in to our equation we get current Equals the voltage of the battery which is 12 divided by the equivalent resistance on 69. So in a the current flowing into the battery is .07 eps. And because again the resistors aren't serious, this current is the one that's flowing through each of them the same. So then mp we want to find the voltage across each resistor. So we have for the first one B one equals the current times are win. So then plugging in the current we have 27 times R. one which is 42. So for the voltage across the first resistor we can being one equals 2.98 votes. Then for the next two resistors it's going to be the same process. So you have the to the voltage across the second sister was. Current times Are too, so we have 107 Times II Resistor to 17. So Me too, Is 1.19 bolts. And then For the voltage across the 3rd resistor Currently have current times are three resist for three. So then we .07. For the current times are three, which is given as 110. And so finally the voltage across the last resistant is 7.7V.


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