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8 heat b) Using the V ohee H deiconinezh 32 Squoay absorbed for the mixture (assume...

Question

8 heat b) Using the V ohee H deiconinezh 32 Squoay absorbed for the mixture (assume

8 heat b) Using the V ohee H deiconinezh 32 Squoay absorbed for the mixture (assume



Answers

The percentage by volume of $\mathrm{C}_{3} \mathrm{H}_{8}$ in a gaseous mixture of $\mathrm{C}_{3} \mathrm{H}_{8}, \mathrm{CH}_{4}$ and $\mathrm{CO}$ is $20 .$ When $100 \mathrm{~mL}$ of the mixture is burnt in excess of $\mathrm{O}_{2}$, the volume of $\mathrm{CO}_{2}$ produced is: (a) $90 \mathrm{~mL}$ (b) $160 \mathrm{~mL}$ (c) $140 \mathrm{~mL}$ (d) none of these

First of all, let's have a look what all is given in the problem. Given his own mixture is given which contains C3H8, ch food and see you now. It is given that the percent by volume, percent by volume four CFC 3 achieved is given as 36.5 and the volume has given us 100 ml. Now it is given that it is, the mixture is burned in oxygen and we are supposed to find out that value must see you to produced. We have to find the volume of See You two produced. So Pastor fall, we know that mixture mixture volume is 100 ml, like the volume of ch four B X. And force you. We can let it as y. Now we know that X plus Y plus 36.5 Because four C 3 H eight, it has given us 36.5 is equal 200. This is a regression number one. Now x plus y equals 200 -36.5. Which will be equal to X plus Y equals to 63.5. This is equation # two. No, let's write the promotion reaction. C3 H eight plus five or two. Well formed. 30 to plus forage talk. Now we know that it is 36.5 g 36.5 by volume portion is given. And this will be three and two. Yeah. Mhm. 30.5 equals 209.5 will come now for meeting. Meeting plus two two will form Ceo to plush switch to now let it be as extremely and write the condition reaction for see you as well. For see you. It will be this. No put it is why now we know that volume of Ceo to produce this volume off Ceo to produce this. X plus Y plus 109.5. Now, X plus five the value of explosive I can we put from equation to that is nothing about 63.5. So 63.5 plus 109.5 it will come around 1 73 ml. Of sio two will be produced. Hence the correct option is option number B.

All right. So for this problem, we're giving the falling reaction. Morose defined the heat released in this reaction killer jewels per gram of be five h nine. So hard to do this will first have to find the heat released by this reaction in total. And wherever that it a constant pressure reaction, which this is. The changes in entropy of the reaction is equal of the heat released. So in order, find the heat released by this reaction on we have to do is find the change of entropy of this reaction which we could do by using the heat's information of the products and react. It's remember that, nor to find the changing to be of a reaction, you take the sum of the heat's information of the products and subtract the some of the heat's information of reactions. So we can do that by five times change. Sorry. The key information. Um B 203 solid, plus nine times the heat information. There's liquid water minus a reactive. So minus two times the unit formation of be five h nine menace 12 times the heat of formation of 02 gas. Now we just need to figure out thes values for the heats of formation one has given to us and the rest weaken. Look up in appendix or table five times the information of B two or three solid, which is negative. 1263.6 Killer jewels Permal lost nine times the heat information of liquid water, which is negative. 258 Sorry. 85.8 Killer jewels Promote minus two times to get information of be five h nine just 73 point to kill Drills Parole minus 12 times the heat information of 02 gas which is zero killer jewels promote. So we calculate this out. You find that the change in Antalya this reaction and the heat released by this reaction is equal to negative 9000 36.6. The jewels per mole of reaction and what I mean by mold of reaction is one go through of this reaction using exactly two moles of P five h nine and 12 moles. So two gas. That's what I mean by one mould reaction. Just one go through of this reaction so we can do some store geometry toe figure out this heat in terms of killer jewels per gram of be five h nine instead of killed joules per mole of reaction. So we start with our heat. Now we need the bottom part in terms of be five h nine. So for one mole of this reaction, we know that two moles be five h nine. Try to Jean online are used And for every mole before five h nine, we know it has a molar mass of 63.1 to 2 grams. So we know that the heat of this reaction negative Sorry, negative 71 0.58 killer jewels for graham of be five h nine liquid.

So for this problem, we're supposed to find the killer. Jill's Laffite, released per gram of the compound of a program of compound reacted with oxygen. The given reaction is the following. So the first step in solving this problem is finding the Delta h of this entire reaction. And from there we can find the final answer. So Delta h of this entire reaction can be expressed as the nine times the heat information of age to plus five times the heat of formation of B two or three minus the heat information of the reactant. But for oxygen, you know that that zero, because it's an element. So the only thing we need to subtract is two times the heat information of be five h nine. And so when you look up the heats information for each of those things, we could then plug those values into this equation. So for the heat information of water negative 285 0.8 killer jewels promote The heat of formation of B 203 is negative 1263.5 kilograms per mole. And finally, the heat of reaction of the heat of formation of beat of be five h nine is 73.2 killer joules per mole. As given in the problem. When you put all of that into the calculator, you will see that this yields negative 9000 and 36 0.1 killer jewels for more. Now the problem here is that this isn't the final answer because it isn't in terms of the grams of oxygen that is reacted. And so we need to express it in terms of grants. So we know that negative 9000 and 36 killed Jules are released for every two moles of be five each nine. We simply then divide by the molar mass of be five h nine to get it in terms of grams and the molar mass of be five h night happens to be 63 grams and let me plug it in. You get the final answer is negative 71.7 killer jewels per gram of be five h nine, and that is the final answer

Yeah. Thermodynamics is essentially the science that investigates the relationship between heat work, temperature and energy. And the first thing we'd like to investigate is the combustion of butane in the exo thermic reaction. So we have c. four h. 10 The 13 over to oh two Gives us full c. 0. 2 At five H 20. Where delta H. Nought is equal to negative 2658.3 kg jewels. And so what we have is the standard entropy change of the reaction. Which is the difference between the some of the entropy of the formation of all of the products species and the some of the entities of the formation of all of the reactant species. So we can substitute the heat of formation Valley Using the information from the table and the -265 8.3. So where we have delta H. Nought is equal to the sum of the malls. The entropy of formation of the product subtract the some of the malls, multiplied by the entropy of formation of the reactant we sold for The entropy of formation of C4 Age 10, which is negative 1 to 4.7 kg joules per mole.


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