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Solve the following equations and tick the correct one.The real roots of the equation $cos ^{7} x+sin ^{4} x=1$ in $(-pi, pi)$ are(a) $-frac{pi}{2}, 0$(b) $-frac{pi...

Question

Solve the following equations and tick the correct one.The real roots of the equation $cos ^{7} x+sin ^{4} x=1$ in $(-pi, pi)$ are(a) $-frac{pi}{2}, 0$(b) $-frac{pi}{2}, 0, frac{pi}{2}$(c) $0, frac{pi}{2}$(d) $0, frac{pi}{4}, frac{pi}{2}$

Solve the following equations and tick the correct one. The real roots of the equation $cos ^{7} x+sin ^{4} x=1$ in $(-pi, pi)$ are (a) $-frac{pi}{2}, 0$ (b) $-frac{pi}{2}, 0, frac{pi}{2}$ (c) $0, frac{pi}{2}$ (d) $0, frac{pi}{4}, frac{pi}{2}$



Answers

The equation whose roots are $\cos \frac{2 \pi}{7}, \cos \frac{4 \pi}{7}, \cos \frac{6 \pi}{7}$ (a) $x^{3}+x+1=0$ (b) $8 x^{3}+4 x^{2}-4 x+1=0$ (c) $2 x^{3}+3 x^{2}+x+1=0$ (d) $8 x^{3}-4 x^{2}+4 x+1=0$

And this from given equation. Can we read it as Both times one foursquare defects elsewhere. Plus Cossacks to be part of four as equals to one. This becomes 4. 1 plus It was followed four x minus two cost square of x. Less hp. four x -1 Is equals to zero. Opening and moving the terms around we get five was followed four eggs minus mhm square of X Plus three is equal to zero. Can we open us? Cause We're X -1. Mhm Five. Hospital effects minus three equals to zero. Case one. Is that 4square of X is one which means that it should be and by belongs to an anesthesia. Second we have foursquare affects us. Three by five. From here you get that access to Empire. The s minus was in Mosul through three by five. That's all these are the two solution.


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