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Celculata fe Rancent ( onlc cheraster lor each Thz LO bend ofthe lellotane Eemnuant bonet oxdeThe Na-Clbond tabla saltThe Fe-5 bond In E tron sulfideThe Fe-0 bond...

Question

Celculata fe Rancent ( onlc cheraster lor each Thz LO bend ofthe lellotane Eemnuant bonet oxdeThe Na-Clbond tabla saltThe Fe-5 bond In E tron sulfideThe Fe-0 bond iron oxideWhat type of bonding would you expect forBronzecopper/tin alloySuperglue 5 polymer adhesive)Barium sulfide430 stainless steel has = thermal expansion of approximately 11 umlmfc Ifa bar of 430 stainless 50 mm long at 259C, how long will be when is heated to 500*C?

celculata fe Rancent ( onlc cheraster lor each Thz LO bend ofthe lellotane Eemnuant bonet oxde The Na-Clbond tabla salt The Fe-5 bond In E tron sulfide The Fe-0 bond iron oxide What type of bonding would you expect for Bronze copper/tin alloy Superglue 5 polymer adhesive) Barium sulfide 430 stainless steel has = thermal expansion of approximately 11 umlmfc Ifa bar of 430 stainless 50 mm long at 259C, how long will be when is heated to 500*C?



Answers

Classify each substance in the table as either a metallic, ionic, molecular, or covalent network solid: $$\begin{array}{|c|c|c|c|c|} \hline \text { Substance } & \text { Appearance } & \text { Melluge eolut } & \text { Electucal eonductive } & \text { Solvinity to Mater } \\ \hline \mathrm{X} & \text { brittle, white } & 800^{\circ} \mathrm{C} & \text { only if melted/dissolved } & \text { soluble } \\ \hline \mathrm{Y} & \text { shiny, malleable } & 1100^{\circ} \mathrm{C} & \text { high } & \text { insoluble } \\ \hline \mathrm{z} & \text { hard, colorless } & 3550^{\circ} \mathrm{C} & \text { none } & \text { insoluble } \\ \hline \end{array}$$

Answer for the question here. According to the given information mentioned in the table and the coaching. So here we will classify the substance, classify a substance as either um metabolic if you want. I unique molecule, er our call and network. So here we have properties of X. Mentioned in the table are mistress and the label. And on the given prop on the basis of the given properties we conclude eight X. Is metallic, X. Is metallic and next we have why? On the basis of the given properties here, why is call it? And that is I am exhausted. These are the classification of X. Y. N. C. On the basis of the Cuban information mentioned in the table.

So based on that figure, 23 point 15 we can see that party off. The question is only Burnham Carbone Ill. So this CEO is known as Carbon 96. Art be off the ocean. Ease. That is osmium garble nine, that is five and part See off the ocean is Are you do see your then. So all these are carbon complexes so we can see that the structural for this complex So you can see that this is Ari. And here Carbonell. And this is Carbonell. This is Carbonell. And then hit Ari. That means her metal metal bonus present. And then we can see that this is Carbonell. This is Carbonell. This is again carbonite card. When I This is Carbonnel. This is Carbonell and one more like this. This is the carpentry. So we see that there is total 10 Carbonell. So in this structure, no body off the ocean is rd off the ocean. We see that that in case off party iron and nickel carbon in our liquid. And that is, uh, cobalt carbonate. A solid at room temperature so we can see that the vic in turmoil regular for self attraction the big in demonic cooler forced off a direction the week Intra molecular force off a direction and and a little molecular moss No, only cooler mus and no molecular months and symmetrical, symmetrical structure off nickel and symmetrical secure off nickel. And I didn carbonation results in results in liquid stayed at room temperature. The good state, Uh, a room temperature. They could state at room temperature, But But we can see that because off. But because off dole metal atoms, because off to metal atoms in the higher molecular mas And, uh hi, Ed Molecular moss. Because we know that, uh, in case off to metal molecular masses. Higher, higher molecular mass. Hi, Adam. Monica Lamar's and less symmetrical less that this less symmetrical estimate weaken carbon nine cobalt carbonate. You can see that, Kabyle. Let's symmetrical cobalt carbonell less symmetrical. Cobalt carbonate, strong and remote. Regular forces strong inter molecular inter molecular forces leads to a solid lead store. Solid add room temperature at room temperature. So therefore we can see that that is iron and nickel carbonara. Uh, carbon nine liquid at room temperature and go bald. Carbon nine, uh, solid. Add room temperature at room temperature at room temperature? No, but he off the ocean is we have given this complex. So this is sodium vanadium carbonara. Six. So we have given this metal Callister. So we see that this compound, this compound, this compound would be an eye nick would be. And I Nick sold like I make sold like material sold like material consisting Gulf consisting all Annapolis consisting off Annapolis and would be see Or Carbonell Vanadium Carbonell six minus iron Because this compound designed it so that it can break in tow, less minus charges. So that is an A plus. And we see your minus we when Adam Carbonell six minus IMEs.

In this problem, the nature of the compound age. The nature of the compound E chromium three cell fate chromium three self fate, e t. J, green colored water, solid walls of stance, water soluble substance. So according to the option, according to the option option siege, correct here. Option C. H. Correct answer for this problem.

In this exercise, they're asking us to measured the terminal expansion of two different materials. There's super in Navarre. She's a really cool material with a very low coefficient of terminal expansion. And we want to compare with the same table made of steel. All right, so first of all, we want to know how much the table expand. If the temperature increases by six degrees, so or they'll The tea here is six degrees and what we want to know is how much will the table expand? That is dot the l. So this equation here is what we need to use in this equation. We have Alfa, which is the coefficient of thermal expansion and is different for different materials. Super in Hvar has a very low alfa compared to other materials like steel. And then l zero is the length of the material that we are considering. In this problem, zero is equal to 1.8 meters because that's the length of this of the table which is shrinking and expending depending on the temperature. Great in the problem we have Alfa, it is given for environment and it is 0.2 times 10 to T minus six. It's one. Those are the units, both alpha and for steel. So I'm gonna write in Hvar because this is only for environment. Alfa for still is different. It is 12 times 10 to the minus six and seeing it's so let's compare Delta for environment is equal to offer times l's here times Delta t And when we do the multiplication, we obtain two point 16 micro meters and my computer is 10 to the minus six meters and then for steel Well, we will be using the same equation. So this 1st 1 was for environment because we used the coefficient of environ. Now this one will be for stealing. So we will use the offer coefficient of steel which is 12. I understand you made six degrees So it's just this one and same table, same length of table and same temperature change. So here is the same. We only changed the Alfa number and what we obtain is 129 0.6 micro meters again. So this is a lot more. In fact, if we do the ratio between two points 16 and 129.6 what we find is that this is close to 1 60 won over 60 18 which means that steel will expand 60 times more than environment, which makes us realize how, um how important in Hvar could be for very sensitive measurements like the ones described into problems.


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