5

Hoanaciowkie (5 points) Hou: Iandomly choose one of the chips Fecond chip ithout replacing the first chipu voLicndquuly[assume letters represent color of the chip...

Question

Hoanaciowkie (5 points) Hou: Iandomly choose one of the chips Fecond chip ithout replacing the first chipu voLicndquuly[assume letters represent color of the chips (WJhite; (BJlack. (GJreen, (RJed] Find probability of pulling a green and then black:0 1/256u5Ka1/18Kz8M5_

Hoanaciowkie (5 points) Hou: Iandomly choose one of the chips Fecond chip ithout replacing the first chipu voLicndquuly [assume letters represent color of the chips (WJhite; (BJlack. (GJreen, (RJed] Find probability of pulling a green and then black: 0 1/25 6u5 Ka1/18 Kz8M5_



Answers

There are five red chips and three blue chips in a bowl. The red chips are numbered $1,2,3,4,5$, respectively, and the blue chips are numbered $1,2,3$, respectively. If two chips are to be drawn at random and without replacement, find the probability that these chips have either the same number or the same color,

In problem 14 we have about that contains eight ships out of them buy bread and three blue. The red shapes are numbered from 1 to 512 3 45 And the blue ones Are numbered 123. We will choose to ships at random and without replacement. We want to find the probability that these ships have either the same number or the same color. 1st. Let's get the number of combinations to select two random ships out of it. Certain number of combinations is it choose to eight c. 2 gives 20 it. And to find the probability that these ships have either the same number of the same color. We add the two probabilities, same numbers or the scene color means to have the probability to have the same numbers plus the same color. And we know that. To get the probability we divide by the total number of combinations. Then we divide by 228 Divided by 28 as the total number of combinations. Let's get the number of combinations to have the two ships being of the same numbers to be of the same number. This means we have only three, combination one and one. Two and two. Three and three. These are the only combinations to have. Then just three. Let's get the number of combinations to have the same color to have the same color. We have two options. The two ships are red or The two ships or blue. Then We have two options. We add them together. The 1st 1 is to choose two out of five red. Then it's fine if they choose to the second the second option is to choose two out of three blue. Then it's three choose to, then it equals city boston plus three Which is three plus 13. Fight it by 28 It's 16 while by 28 Gives four divided by seven which is the final answer of our problem.

Mhm. Okay, for this problem we have 12 poker chips. All right. Three red, Yeah. Four wiped and five blue. Okay. The question is asking, what is the probability of getting a blue chip? Okay, probability again, is successes over total attempts? Okay. A successful draw would be to get a blue chip. So there's five ways to do that. The total number of options, there are 12 possible chips. So the probability of getting a probability of getting a blue chip is 5 12.

We are given that a box can paint them red chips, 20 chips and 50 green ships. And we need to draw fire chips from that box first. The provocative that all chips are blue at least one is green at most. One is ready. So let's draw right for sample space or sample space will be drawing five chips out of 30-plus 2015, less than 16. So we have to draw or select five chairs out of 60. So this is our sample space now for a number of a number of a all blue chips. So how many blue chips? We have 20. And from this 20 we have to select five to get outlook. So 20 C five therefore probability of A will be 20 C. Five. 460 C five. So in solving this will get a resolution, next number of B. The number of these asking for at least one green. So at least one green can occur when we select agree to one Green chip or we can select then Out of 13 is elected one grand chief And remaining four will be selected from other that is 20 plus 10. 13 protect in C. Four. Then next year will be if you sell it two green from 13 In the morning will be selected will be three then three Green from 30. Then we'll have to select 50 C. Two. Then we'll select four green. In fact PC one and then select five green. So will not select anything from restaurant. So this is a number of B. So our probability of B will be number of P. Four. Number of days. So a number of B. So we'll take the model be here do what I do to buy it Number of years which is 60 c. five. Okay now let's move to the final one. That is probability of scenes for that. We need number of C. So you're saying at most one day, so you cannot have more than one day. So how many red chips we have? We have tendered chips out of 10 we can sell at zero and the rest Will be selected from just 50 chips, so five chips or we can have 12 from the red and the rest for will be From another one. So this is our number of years since we cannot have more than one number of 63, the probability of civil B 10 C zero 50 C five. 10 c 154. Uh huh, 60 C. Right. And that's a solution and

Okay, so a box gardens turn red chips, 20 blue chips, 30 green. Uh if five drawn from a box find the probability of the indicated situations, the first one is that the probability That four of them are agreeing? So the probability of four green is equal to. Um So we want we are selecting oh from 30 green and we want four of them to be green. So what that means is from the remaining uh blue plus red, which is state. Again we will then get the last one. Uh then divided by the sample space of selecting uh five chips from 16. Use our calculator. Uh This would be Approximately 0.15. And the second chaos is where we can get at least two red, which means Greater or equal to two. Let's So there are many uh it's longer. If we we say we take two or 3 or four reds, it's a little bit longer. So the best is to take a compliment Which is one that. They are less than to rand's. So less than two reds means that I am going to uh to have either zero reds. If it's zero rates, what does it mean? It means the I've paid picked from 3rd green and 20 blue which makes it 50. Uh and I select all the fall. Okay. And uh No, no I select all the five. And if I do that it means uh then I will have to say this over the sample space. So this in this case we've got zero red and alternatively we can pick one red. And the probability of picking one. Read simply means From the 59 red. We'll pick four and then from the red And How Many Leads? 10? We select one and all this is over the sample space. So this would be equal to Settle .1 Night. And lastly the probability that at most two blue at most simply means Less or equal to two. So what it means is that we can have zero blue. Zero blue means we take all the others which are 10 blocks for uh which are 10 plus 30 which has 40. Uh And then we are selecting all the five 90 blue balls. Then this is over the total sample space, which is uh Or we can pick um 1. 9 Blue Ball. And How Many Blues Do We Have? 20? And from the blue. No, we can pull pick for 90 blue and one below over the sample space, which is 6 to c. five. Then the last is when we also peak three non blue. And from the blue we pick two and offer the sample space. And if you put this in the calculator, You get 0.87


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