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Answers

Consumer Reports provided overall customer satisfaction scores for AT\&T, Sprint,
T-Mobile, and Verizon cell-phone services in major metropolitan areas throughout the
United States. The rating for each service reflects the overall customer satisfaction considering a variety of factors such as cost, connectivity propped calls, static
interference, and customer support. A satisfaction scale from 0 to 100 was used, with 0 indicating completely dissatisfied and 100 indicating completely satisfied. The ratings for
the four cell-phone services in 20 metropolitan areas are as shown (Consumer Reports,
January 2009 ).
a. Consider T-Mobile first. What is the median rating?
b. Develop a five-number summary for the T-Mobile service.
c. Are there outliers for T-Mobile? Explain.
d. Repeat parts (b) and (c) for the other three cell-phone services.
e. Show the box plots for the four cell-phone services on one graph. Discuss what a
comparison of the box plots tells about the four services. Which did Consumer
Reports recommend as being best in terms of overall customer satisfaction?

So to plot this data, it's not going to look particularly good, but we have five degree or 55 degree intervals from 50 to 90. So let's say every line is five. So 55 60 65 70 75 80 85 90 60 70 baby 90. So it and then So you were going from somewhere between 20 chirps per minute to 211 chirps per minute. So let's do it by twenties. 20 40 80 100 1 20 1 40 1 60 1 80 200 2 20 So 2 20 All right, let's actually label 201. 60 1 20 and 80. Wait. So I did something wrong. All right. We're going by twenties. Yes. So 20 40 60 80 101. 20 at 1 40 Uh, 1 60 1 80 Yes. So I messed up. That's 200. And then here's to 20. Right? So plotting this 50 is at 20. 55 is 46. 60 is 79. 65. There's 91. 70 is 1 13 75 is 1 40 80 is 1 73 85 is 1 98 and 90 is to 11. Now, to find the regression line, we use our calculator and we get and is about 4.8567 T minus 2 20 0.9667 where? And so now if we want to grab this are, uh, t r n intercepts of this is N Oh, actually, I'm sorry, Uh, in this case, we put our axes opposite. That's fine. So and is the chirping rate right? I should are. Actually, they're fine. And is the chirping rate T is the temperature. So are an intercept is going to be quite negative. So will be somewhere down here, and we'll have positive. So and, Ah, if we estimate the tripping rated 100 degrees Fahrenheit, we plug in 102 teen and we get and of 100 is approximately 2 65

It is probably gonna talk about frequency and time constant. So let's say that we have a wave that I'm a drive here like this and we plot the empathy of the wave as a function off the time cheap. Mhm. Um, I just write different. That could be It's yes. Here. Okay, so this is the amplitude A Let's say, if we want to calculate the frequency of this way Well, let's say that here we have that the time is equal to three seconds. Um, so we can ask ourselves how we calculate the frequency this way. Well, we have to count how many oscillations there are inside these three seconds. And then the divide, the number of the oscillations by the time. So the frequency is equal to the number of oscillations then divided by time. The time t Now, how many escalations air there inside these three seconds? Ah, here we have one solution. Then we have two and three. So there are three escalations in three seconds. And you know the frequency is equal to three divided by three or one hurts that. Then we're also gonna talk about time constant. So consider that we have a wavelength was an amplitude because his fault a is equal to 30 minus times e to the team to the minus c developmental where tau is called the time Constant. Yeah. Okay, uh, notice also that, uh, this time costs, um, towel can be interpreted as the time necessary for the amplitude to decay by a factor of mhm. So a off T equal Tao is equal to a zero divided by eat. Okay, so now we can go into activities way. Have the wave shown here The figure, Any questions? A. We have to calculate the frequency f. Well, notice that in the 1st 2nd, we have Tom one to three four on. There's actually something wrong here. The one shouldn't be here for that. Um, no one should be here. Okay, so for five oscillations in one second, so the frequency is equal to five divided by one or five hertz, then in question. Do you have to calculate the time constant? Be town Khost. Tell I'm sorry. Eso basically notice that a is equal to five units 12345 and ah, a equal to a zero. Divided by e is equal to five units divided by, and this is approximately 1.8. So we have to, uh, in order to find how you have to see at what time? The attitude the case to 1.8 units. So basically, uh, what time? 1.8 is approximately here. So at what time? The frequency that pleased 1.8. And we can see that it's approximately at two milliseconds. Okay, actually, here in Rhode five herds, it's actually going to be a little more specific. The frequency is equal to five oscillations, divided by one milliseconds. So this is actually 5000 hertz five que hurts for For that eso the time constant is equal to two milliseconds, and this concludes our exercise.

And question number 18 13 MPP s is the 46 data value in the authority that asset this 45 of the 50 data values are smaller than 13 MBPs So 45/50 equal to 0.90 call to 90 person The ex percentile have the property that x percent off the radar values are below the percentile. Thus 13 MBPs corresponds. Was buying peace person tired and that the final answer Thank you.

In this question. Number 17, we have that 2.4 m. PBS is the 30th. That's ah value in the sorted that I said this 29 of the 50 the era values are smaller than 2.4 m PBS so 29 over 50 equal to 4.58 equal to 58%. The ex percentile have the property that X person off the data that values are below the person tied the 2.4 m p. V s corresponds with the 58th person tired that the final answer. Thank you.


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